\(a,4^9:4^4=4^5\\b,17^8:17^5=17^3\\ c,2^{10}:8^2=2^{10}:2^6=2^4\\ d,18^{10}:3^{10}=2^{10}\cdot3^{20}:3^{10}=2^{10}\cdot3^{10}=6^{10}\\ e,27^5:81^3=3^{15}:3^{12}=3^3 \)

\(f,10^6:100=10^6:10^2=10^4\\ g,5^9:25^3=5^9:5^6=5^3\\ h,4^{10}:64^3=4^{10}:4^9=4\\ i,2^{25}:32^4:18^4:9^4=2^{25}:2^{20}:2^4:3^8:3^8=2\)

a)

4⁹:4⁴=4⁵

17⁸:17⁵=17³

2¹⁰:8²=2¹⁰:2⁴=2⁶

18¹⁰:3¹⁰=15¹⁰

27⁵:81³=3¹⁵:3¹²=3³

b)10⁶:10²=10⁴

5⁹:5⁶=5³

4¹⁰:64³=4

2²⁵:32⁴=2²⁵:2²⁰=2⁵

18⁴:9⁴=9⁴

\(4^9:4^4\)
=\(4^{9-4}\)
=\(4^5\)
\(17^8:17^5\)
=\(17^{8-5}\)
= \(17^3\)
\(2^{10}:8^2\)
\(=2^{^{ }10}:\left(2^3\right)^2\)
=\(2^{10}:2^6\)
\(=2^4\)
\(18^{10}:3^{10}\)
=\(\left(18:3\right)^{10}\)
=\(6^{10}\)

a) \(4^9:4^4\)

\(=4^{9-4}\)

\(=4^5\)

b) \(17^8:17^5\)

\(=17^{8-5}\)

\(=17^3\)

c) \(2^{10}:8^2\)

\(=2^{10}:\left(2^3\right)^2\)

\(=2^{10-6}\)

\(=2^4\)

d) \(18^{10}:3^{10}\)

\(=\left(18:3\right)^{10}\)

\(=6^{10}\)

e) \(27^5:81^3\)

\(=\left(3^3\right)^5:\left(3^4\right)^3\)

\(=3^{15}:3^{12}\)

\(=3^{15-12}\)

\(=3^3\)

f) \(10^6:100\)

\(=10^6:10^2\)

\(=10^{6-2}\)

\(=10^4\)

g) \(5^9:25^3\)

\(=5^9:\left(5^2\right)^3\)

\(=5^9:5^6\)

\(=5^{9-6}\)

\(=5^3\)

h) \(4^{10}:64^3\)

\(=4^{10}:\left(4^3\right)^3\)

\(=4^{10-9}\)

\(=4\)

i) \(2^{25}:32^4:18^4:9^4\)

\(=\left(2^{25}:2^{20}\right):\left(18^4\cdot9^4\right)\)

\(=2^5:9^8:2^4\)

\(=2:9^8\)

\(=\dfrac{2}{9^8}\)

a,4^9-4

b,17^8-5

c,2^10-5

d,6^10

e,81

f,

a: \(\dfrac{4^9}{4^4}=4^{9-4}=4^5\)

b: \(\dfrac{17^8}{17^5}=17^{8-5}=17^3\)

c: \(2^{10}:8^2=2^{10}:2^6=2^4\)

d: \(18^{10}:3^{10}=\left(\dfrac{18}{3}\right)^{10}=6^{10}\)

e: \(=\dfrac{3^{15}}{3^{12}}=3^3\)

f: \(=\dfrac{10^6}{10^2}=10^4\)

g: =5^9:5^6=5^3

h: \(=\dfrac{4^{10}}{\left(4^3\right)^3}=\dfrac{4^{10}}{4^9}=4\)

i: \(=2^{25}:2^{20}\cdot\dfrac{1}{18^4}\cdot\dfrac{1}{9^4}\)

\(=\dfrac{2^5}{9^8\cdot2^4}=\dfrac{2}{9^8}\)

\(=\left(3^4\right)^5.\left(2^5\right)^4=3^{20}.2^{20}=6^{20}\)

815+[95+(-815)+(-45)]

\(=\) 815+(95-815-45)

\(=\) 815+95-815-45

\(=\) 50

815+[95+(-815)+(-45)]

= 815 + ( 95 - 815 - 45 )

= 815 + ( - 765 )

= 50

815+[ 95+(-815) + (-45)]

=50

815 + 95 + ( -815) + ( -45)

= [815 + (-815)] + [95 + (-45)]

= 0 + [+(95 - 45)]

= 0 + 50

= 50

   815 + 95 + (-815) + (-45)

= [815 + (-815)] + [95 + (-45)]

= 0 + 50

= 50

Mình xin được trả lời :

815 + 95 + (-815)+(-45)

= [ 815+(-815) ] + [ 95+(-45) ] 

= 0 + 50

= 50

Ai k nhanh mình sẽ k lai vi minh co nhieu nick lam

= 815 +95 + (-815) + (-45) 

= [815+(-815)] +[95 + ( -45)] 

=0+50=50

các bạn li-ke mình cho tròn 325 với 

815+[95+(-815)+(-45)] 

= 815+[-765)]

= 50

815+[95+(-815)+(-45)]

=815+95+(-815)+(-45)

=[815+(-815)]+[95+(-45)

=0+50

=50

=815+(-765)

=815-765

=50

815+[95+(-815)+(-45)]= 815+95-815-45=(815-815)+(95-45)=0+50=50

= 76565 

815[95+(-815)+(-45)

=815[-720+(-45)]

=815(-765)

=-623475

mik nha!

­

  815{95+[-(815+45)]

=815{95+(-860)}

=815.(-860)

=-700900

Ta có:

\(\frac{10}{11}+\frac{1}{11}=1\)                           \(\frac{15}{16}+\frac{1}{16}=1\)

\(\frac{12}{13}+\frac{1}{13}=1\)

Vì \(\frac{1}{11}>\frac{1}{13}>\frac{1}{16}\)\(\Rightarrow\frac{10}{11}< \frac{12}{13}< \frac{15}{16}\)

b.

Ta có: \(\frac{-497}{496}>\frac{-497}{815}>\frac{-816}{815}\)

\(\Rightarrow\frac{-497}{496}>\frac{-816}{815}\)