rút gọn biểu thức :
N = 1 + \(\left(\dfrac{1}{2}\right)\) + \(\left(\dfrac{1}{2}\right)^2\) + \(\left(\dfrac{1}{2}\right)^3\) + ... + \(\left(\dfrac{1}{2}\right)^{100}\)
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Rút gọn biểu thức Sleft(xright)dfrac{1}{x^2}+dfrac{2}{x^3}+dfrac{3}{x^4}+...+dfrac{n}{x^{n+1}} bằng:A. Sdfrac{x^{n+1}-left(n+1right)x+n}{x^{n+1}left(x-1right)^2}B. Sdfrac{x^{n+1}-left(n+1right)x+n}{x^{2n}left(x-1right)^2}C. Sdfrac{x^n-left(n+1right)x+n}{x^nleft(x-1right)^2}D. Sdfrac{x^{n+1}-left(n+1right)x+n}{x^nleft(x-1right)^2}
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Rút gọn biểu thức \(S\left(x\right)=\dfrac{1}{x^2}+\dfrac{2}{x^3}+\dfrac{3}{x^4}+...+\dfrac{n}{x^{n+1}}\) bằng:
A. \(S=\dfrac{x^{n+1}-\left(n+1\right)x+n}{x^{n+1}\left(x-1\right)^2}\)
B. \(S=\dfrac{x^{n+1}-\left(n+1\right)x+n}{x^{2n}\left(x-1\right)^2}\)
C. \(S=\dfrac{x^n-\left(n+1\right)x+n}{x^n\left(x-1\right)^2}\)
D. \(S=\dfrac{x^{n+1}-\left(n+1\right)x+n}{x^n\left(x-1\right)^2}\)
Rút gọn biểu thức Sleft(xright)dfrac{1}{x^2}+dfrac{2}{x^3}+dfrac{3}{x^4}+...+dfrac{n}{x^{n+1}} bằng:A. Sdfrac{x^{n+1}-left(n+1right)x+n}{x^{n+1}left(x-1right)^2}B. Sdfrac{x^{n+1}-left(n+1right)x+n}{x^{2n}left(x-1right)^2}C. Sdfrac{x^n-left(n+1right)x+n}{x^nleft(x-1right)^2}D. Sdfrac{x^{n+1}-left(n+1right)x+n}{x^nleft(x-1right)^2}
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Rút gọn biểu thức \(S\left(x\right)=\dfrac{1}{x^2}+\dfrac{2}{x^3}+\dfrac{3}{x^4}+...+\dfrac{n}{x^{n+1}}\) bằng:
A. \(S=\dfrac{x^{n+1}-\left(n+1\right)x+n}{x^{n+1}\left(x-1\right)^2}\)
B. \(S=\dfrac{x^{n+1}-\left(n+1\right)x+n}{x^{2n}\left(x-1\right)^2}\)
C. \(S=\dfrac{x^n-\left(n+1\right)x+n}{x^n\left(x-1\right)^2}\)
D. \(S=\dfrac{x^{n+1}-\left(n+1\right)x+n}{x^n\left(x-1\right)^2}\)
\(S\left(x\right)=\dfrac{1}{x^2}+\dfrac{2}{x^3}+...+\dfrac{n}{x^{n+1}}\)
\(\Rightarrow x.S\left(x\right)=\dfrac{1}{x}+\dfrac{2}{x^2}+\dfrac{3}{x^3}+...+\dfrac{n}{x^n}\)
\(\Rightarrow x.S\left(x\right)-S\left(x\right)=\dfrac{1}{x}+\dfrac{1}{x^2}+\dfrac{1}{x^3}+...+\dfrac{1}{x^n}-\dfrac{n}{x^{n+1}}\)
\(\Rightarrow\left(x-1\right)S\left(x\right)=\dfrac{1}{x}.\dfrac{1-\left(\dfrac{1}{x}\right)^n}{1-\dfrac{1}{x}}-\dfrac{n}{x^{n+1}}=\dfrac{x^n-1}{x^n\left(x-1\right)}-\dfrac{n}{x^{n+1}}=\dfrac{x^{n+1}-x-n\left(x-1\right)}{x^{n+1}\left(x-1\right)}\)
\(\Rightarrow S\left(x\right)=\dfrac{x^{n+1}-\left(n+1\right)x+n}{x^{n+1}\left(x-1\right)^2}\)
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Rút gọn biểu thức sau:
\(A=\left(1+\dfrac{2}{1.4}\right).\left(1+\dfrac{2}{2.5}\right).\left(1+\dfrac{2}{3.6}\right).....\left(1+\dfrac{2}{x\left(x+3\right)}\right)\)
Bài 1 : Rút gọn biểu thức a. A left(a-2right):left{dfrac{a^2-b^2}{a^3+b^3}.left[a-dfrac{a^2+b^2}{b}:left(dfrac{1}{a}-dfrac{1}{b}right)right]right}dfrac{a-2}{a} b. B 1:left(dfrac{x+2}{xsqrt{x}-1}+dfrac{sqrt{x}+1}{x+sqrt{x}+1}-dfrac{sqrt{x}+1}{x-1}right) 2. Chứng minh đẳng thức :a. left(dfrac{6a+1}{a^2-6a}+dfrac{6a-1}{a^2+6a}right).dfrac{a^2-36}{a^2+1}dfrac{12}{a}b. dfrac{sqrt{x}-sqrt{y}}{xysqrt{xy}}:lef...
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Bài 1 : Rút gọn biểu thức
a. A = \(\left(a-2\right):\left\{\dfrac{a^2-b^2}{a^3+b^3}.\left[a-\dfrac{a^2+b^2}{b}:\left(\dfrac{1}{a}-\dfrac{1}{b}\right)\right]\right\}=\dfrac{a-2}{a}\)
b. B = \(1:\left(\dfrac{x+2}{x\sqrt{x}-1}+\dfrac{\sqrt{x}+1}{x+\sqrt{x}+1}-\dfrac{\sqrt{x}+1}{x-1}\right)\)
2. Chứng minh đẳng thức :
a. \(\left(\dfrac{6a+1}{a^2-6a}+\dfrac{6a-1}{a^2+6a}\right).\dfrac{a^2-36}{a^2+1}=\dfrac{12}{a}\)
b. \(\dfrac{\sqrt{x}-\sqrt{y}}{xy\sqrt{xy}}:\left[\left(\dfrac{1}{x}+\dfrac{1}{y}\right).\dfrac{1}{x+y+2\sqrt{xy}}+\dfrac{2}{\left(\sqrt{x}+\sqrt{y}\right)^3}.\left(\dfrac{1}{\sqrt{x}}+\dfrac{1}{\sqrt{y}}\right)\right]=\dfrac{\sqrt{x}-\sqrt{y}}{\sqrt{xy}}\)
Bài 1 : Rút gọn biểu thức a. A left(a-2right):left{dfrac{a^2-b^2}{a^3+b^3}.left[a-dfrac{a^2+b^2}{b}:left(dfrac{1}{a}-dfrac{1}{b}right)right]right}dfrac{a-2}{a} b. B 1:left(dfrac{x+2}{xsqrt{x}-1}+dfrac{sqrt{x}+1}{x+sqrt{x}+1}-dfrac{sqrt{x}+1}{x-1}right) 2. Chứng minh đẳng thức :a. left(dfrac{6a+1}{a^2-6a}+dfrac{6a-1}{a^2+6a}right).dfrac{a^2-36}{a^2+1}dfrac{12}{a}b. dfrac{sqrt{x}-sqrt{y}}{xysqrt{xy}}:lef...
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Bài 1 : Rút gọn biểu thức
a. A = \(\left(a-2\right):\left\{\dfrac{a^2-b^2}{a^3+b^3}.\left[a-\dfrac{a^2+b^2}{b}:\left(\dfrac{1}{a}-\dfrac{1}{b}\right)\right]\right\}=\dfrac{a-2}{a}\)
b. B = \(1:\left(\dfrac{x+2}{x\sqrt{x}-1}+\dfrac{\sqrt{x}+1}{x+\sqrt{x}+1}-\dfrac{\sqrt{x}+1}{x-1}\right)\)
2. Chứng minh đẳng thức :
a. \(\left(\dfrac{6a+1}{a^2-6a}+\dfrac{6a-1}{a^2+6a}\right).\dfrac{a^2-36}{a^2+1}=\dfrac{12}{a}\)
b. \(\dfrac{\sqrt{x}-\sqrt{y}}{xy\sqrt{xy}}:\left[\left(\dfrac{1}{x}+\dfrac{1}{y}\right).\dfrac{1}{x+y+2\sqrt{xy}}+\dfrac{2}{\left(\sqrt{x}+\sqrt{y}\right)^3}.\left(\dfrac{1}{\sqrt{x}}+\dfrac{1}{\sqrt{y}}\right)\right]=\dfrac{\sqrt{x}-\sqrt{y}}{\sqrt{xy}}\)
3. Chứng minh biểu thức không phụ thuộc vào biến :
a. A = \(\left(\dfrac{x}{x-y}-\dfrac{y}{x+y}\right):\left(\dfrac{x+y}{x-y}-\dfrac{2xy}{x^2-y^2}\right)\)
b. \(\left(\dfrac{1-a\sqrt{a}}{1-\sqrt{a}}+\sqrt{a}\right)\left(\dfrac{1-\sqrt{a}}{1-a}\right)^2\)
Bài 1 : Rút gọn biểu thức a. A left(a-2right):left{dfrac{a^2-b^2}{a^3+b^3}.left[a-dfrac{a^2+b^2}{b}:left(dfrac{1}{a}-dfrac{1}{b}right)right]right}dfrac{a-2}{a} b. B 1:left(dfrac{x+2}{xsqrt{x}-1}+dfrac{sqrt{x}+1}{x+sqrt{x}+1}-dfrac{sqrt{x}+1}{x-1}right) 2. Chứng minh đẳng thức :a. left(dfrac{6a+1}{a^2-6a}+dfrac{6a-1}{a^2+6a}right).dfrac{a^2-36}{a^2+1}dfrac{12}{a}b. dfrac{sqrt{x}-sqrt{y}}{xysqrt{xy}}:lef...
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Bài 1 : Rút gọn biểu thức
a. A = \(\left(a-2\right):\left\{\dfrac{a^2-b^2}{a^3+b^3}.\left[a-\dfrac{a^2+b^2}{b}:\left(\dfrac{1}{a}-\dfrac{1}{b}\right)\right]\right\}=\dfrac{a-2}{a}\)
b. B = \(1:\left(\dfrac{x+2}{x\sqrt{x}-1}+\dfrac{\sqrt{x}+1}{x+\sqrt{x}+1}-\dfrac{\sqrt{x}+1}{x-1}\right)\)
2. Chứng minh đẳng thức :
a. \(\left(\dfrac{6a+1}{a^2-6a}+\dfrac{6a-1}{a^2+6a}\right).\dfrac{a^2-36}{a^2+1}=\dfrac{12}{a}\)
b. \(\dfrac{\sqrt{x}-\sqrt{y}}{xy\sqrt{xy}}:\left[\left(\dfrac{1}{x}+\dfrac{1}{y}\right).\dfrac{1}{x+y+2\sqrt{xy}}+\dfrac{2}{\left(\sqrt{x}+\sqrt{y}\right)^3}.\left(\dfrac{1}{\sqrt{x}}+\dfrac{1}{\sqrt{y}}\right)\right]=\dfrac{\sqrt{x}-\sqrt{y}}{\sqrt{xy}}\)
3. Chứng minh biểu thức không phụ thuộc vào biến :
a. A = \(\left(\dfrac{x}{x-y}-\dfrac{y}{x+y}\right):\left(\dfrac{x+y}{x-y}-\dfrac{2xy}{x^2-y^2}\right)\)
b. \(\left(\dfrac{1-a\sqrt{a}}{1-\sqrt{a}}+\sqrt{a}\right)\left(\dfrac{1-\sqrt{a}}{1-a}\right)^2\)
Bài 3:
\(a,A=\dfrac{x^2+xy-xy+y^2}{\left(x-y\right)\left(x+y\right)}:\dfrac{x^2+2xy+y^2-2xy}{\left(x-y\right)\left(x+y\right)}\\ A=\dfrac{x^2+y^2}{\left(x-y\right)\left(x+y\right)}\cdot\dfrac{\left(x-y\right)\left(x+y\right)}{x^2+y^2}=1\\ b,=\left[\dfrac{\left(1-\sqrt{a}\right)\left(a+\sqrt{a}+1\right)}{1-\sqrt{a}}+\sqrt{a}\right]\left[\dfrac{1-\sqrt{a}}{\left(1-\sqrt{a}\right)\left(1+\sqrt{a}\right)}\right]^2\\ =\left(a+2\sqrt{a}+1\right)\left(\dfrac{1}{\sqrt{a}+1}\right)^2\\ =\left(\sqrt{a}+1\right)^2\cdot\dfrac{1}{\left(\sqrt{a}+1\right)^2}=1\)
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Rút gọn biểu thức sau:
\(A=\left(1-\dfrac{1}{1+2}\right)\left(1-\dfrac{1}{1+2+3}\right)\left(1-\dfrac{1}{1+2+3+4}\right)...\left(1-\dfrac{1}{1+2+3+...+n}\right)\)với n lá các số tự nhiên lớn hơn 2.
Với mọi k thuộc N và k > 2 thì ta có :
\(1-\frac{1}{1+2+....+k}=1-\frac{1}{\frac{k\left(k+1\right)}{2}}=1-\frac{2}{k\left(k+1\right)}=\frac{k^2+k-2}{k\left(k+1\right)}=\frac{\left(k+2\right)\left(k-1\right)}{k\left(k+1\right)}\)
Áp dụng vào A ta được :
\(A=\left(1-\frac{1}{1+2}\right)\left(1-\frac{1}{1+2+3}\right)\left(1-\frac{1}{1+2+3+4}\right)...\left(1-\frac{1}{1+2+....+n}\right)\)
\(=\frac{1.4}{2.3}.\frac{2.5}{3.4}.\frac{3.6}{4.5}....\frac{\left(n-1\right)\left(n+2\right)}{n\left(n+1\right)}\)
\(=\frac{\left[1.2.3....\left(n-1\right)\right]\left[4.5.6.....\left(n+2\right)\right]}{\left(2.3.4......n\right)\left[3.4.5.....\left(n+1\right)\right]}\)
\(=\frac{n+2}{n.3}=\frac{n+2}{3n}\)
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Rút gọn biểu thức
a. B = \(\left(\dfrac{a-b}{a^2+ab}-\dfrac{a}{b^2+ab}\right):\left(\dfrac{b^3}{a^3-ab^2}+\dfrac{1}{a+b}\right)\)
b. C = \(a:\left(b-2\right)-\left[\left(a^2+2a+1\right):\left(b^2-4\right)\right].\left[\left(b+2\right):\left(a+1\right)\right]\)
Rút gọn biểu thức
a. B = \(\left(\dfrac{a-b}{a^2+ab}-\dfrac{a}{b^2+ab}\right):\left(\dfrac{b^3}{a^3-ab^2}+\dfrac{1}{a+b}\right)\)
b. C = \(a:\left(b-2\right)-\left[\left(a^2+2a+1\right):\left(b^2-4\right)\right].\left[\left(b+2\right):\left(a+1\right)\right]\)