\(B=\left(\frac{15}{16}+\frac{1}{17}\right)-\left(\frac{15}{16}-\frac{16.11}{17.11}\right)\)

\(B=\frac{15}{16}+\frac{1}{17}-\frac{15}{16}+\frac{16}{17}\)

\(B=\frac{1}{17}+\frac{16}{17}=\frac{17}{17}=1\)

\(\left(\frac{151515}{161616}+\frac{17^9}{17^{10}}\right)-\left(\frac{1500}{1600}-\frac{1616}{1717}\right)\)

\(=\left(\frac{15}{16}+\frac{1}{17}\right)-\left(\frac{15}{16}-\frac{16}{17}\right)\)

\(=\frac{15}{16}+\frac{1}{17}-\frac{15}{16}+\frac{16}{17}\)

\(=\left(\frac{15}{16}-\frac{15}{16}\right)+\left(\frac{1}{17}+\frac{16}{17}\right)\)

\(=\frac{15-15}{16}+\frac{1+16}{17}\)

\(=0+\frac{17}{17}\)

\(=0+1\)

\(=1\)

thank

\(\dfrac{151515}{161616}+\dfrac{1}{17}-\dfrac{1500}{1600}-\dfrac{16}{17}\)

\(=\dfrac{10101.15}{10101.16}+\dfrac{1}{17}-\dfrac{15.100}{16.100}-\dfrac{16}{17}\)

\(=\dfrac{15}{16}+\dfrac{1}{17}-\dfrac{15}{16}-\dfrac{16}{17}=\dfrac{-15}{17}\)

=\(\left(\frac{15}{16}+\frac{1}{17^5}\right)+\left(\frac{16}{17}-\frac{15}{16}\right)\)

=\(\frac{1}{17^5}+\frac{16}{17}=\frac{1+16.17^4}{17^5}\)

đáp số là số thập phân vô hạn không tuần hoàn

\(B=\left(\frac{151515}{161616}+\frac{17^9}{17^{10}}\right)-\left(\frac{1500}{1600}-\frac{176}{187}\right)\)

\(B=\left(\frac{15}{16}+\frac{1}{17}\right)-\left(\frac{15}{16}-\frac{16}{17}\right)\)

\(B=\frac{15}{16}+\frac{1}{17}-\frac{15}{16}+\frac{16}{17}\)

\(B=\left(\frac{15}{16}-\frac{15}{16}\right)+\left(\frac{1}{17}+\frac{16}{17}\right)\)

\(B=0+1=1\)

Vậy: B=1

Ta có: \(\frac{\frac{3}{7}-\frac{3}{17}+\frac{3}{171}-\frac{3}{1717}}{\frac{9}{7}-\frac{9}{17}+\frac{9}{171}-\frac{9}{1717}}\)= \(\frac{3.\left(\frac{1}{7}-\frac{1}{17}+\frac{1}{171}-\frac{1}{1717}\right)}{9.\left(\frac{1}{7}-\frac{1}{17}+\frac{1}{171}-\frac{1}{1717}\right)}\)=\(\frac{3}{9}=\frac{1}{3}\)

Sai đề òi,phải là \(\frac{38}{25}\) chứ

\(=8\frac{4}{17}-2\frac{5}{9}+3\frac{4}{17}=\left(8+3\right)\frac{4}{17}-2\frac{5}{9}=11\frac{4}{17}-2\frac{5}{9}\)

Chỉ cần k!

Nếu muốn giải đc..

Phải k cho mk,mk sẽ giải cho!

\(A=8\frac{4}{17}-\left(2\frac{5}{9}+3\frac{4}{17}\right)\)

\(A=8+\frac{4}{17}-\left(2+\frac{5}{9}+3+\frac{4}{17}\right)\)

\(A=8+\frac{4}{17}-2-\frac{5}{9}-3-\frac{4}{17}\)

\(A=\left(8-2-3\right)+\left(\frac{4}{17}-\frac{4}{17}\right)-\frac{5}{9}\)

\(A=3-\frac{5}{9}\)

\(A=\frac{27-5}{9}=\frac{22}{9}\)