\(B=\frac{3+0,75-\frac{3}{19}}{\frac{5}{2}+0,625-\frac{5}{38}}\cdot\frac{15+\frac{15}{17}-\frac{15}{144}+\frac{15}{34}}{2+\frac{3}{17}-\frac{2}{144}}\)
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Thực hiện phép tính:
\(\frac{3+0,75-\frac{3}{19}}{\frac{5}{2}+0,625-\frac{5}{38}}\cdot\frac{15+\frac{15}{17}-\frac{15}{144}+\frac{15}{34}}{2+\frac{3}{17}-\frac{2}{144}}+2018\)
\(=\frac{3+\frac{3}{4}-\frac{3}{19}}{\frac{5}{2}+\frac{5}{8}-\frac{5}{38}}.\frac{15+\frac{15}{34}+\frac{15}{17}-\frac{15}{144}}{2+\frac{2}{34}+\frac{2}{17}-\frac{2}{144}}+2018\)
\(=\frac{3\left(1+\frac{1}{4}-\frac{1}{19}\right)}{\frac{5}{2}\left(1+\frac{1}{4}-\frac{1}{19}\right)}.\frac{15\left(1+\frac{1}{34}+\frac{1}{17}-\frac{1}{144}\right)}{2\left(1+\frac{1}{34}+\frac{1}{17}-\frac{1}{144}\right)}+2018\)
\(=\frac{3}{\frac{5}{2}}.\frac{15}{2}+2018\)
\(=\frac{6}{5}.\frac{15}{2}+2018\)
\(=9+2018=2027\)
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\(\frac{3+0,75-\frac{3}{19}}{\frac{5}{2}+0,625-\frac{5}{38}}\) . \(\frac{15+\frac{15}{17}-\frac{15}{144}+\frac{15}{34}}{2+\frac{2}{17}-\frac{2}{144}+\frac{1}{17}}\)+2018
=\(\frac{3+\frac{3}{4}-\frac{3}{19}}{\frac{5}{2}+\frac{5}{8}-\frac{5}{38}}\) . \(\frac{15+\frac{15}{17}-\frac{15}{144}+\frac{15}{34}}{2+\frac{2}{17}-\frac{2}{144}+\frac{2}{34}}\)+2018
=\(\frac{3\left(1+\frac{1}{4}-\frac{1}{19}\right)}{5\left(\frac{1}{2}+\frac{1}{8}-\frac{1}{38}\right)}\) . \(\frac{15\left(1+\frac{1}{17}-\frac{1}{144}+\frac{1}{34}\right)}{2\left(1+\frac{1}{17}-\frac{1}{144}+\frac{1}{34}\right)}\)+2018
=\(\frac{6\left(\frac{1}{2}+\frac{1}{8}-\frac{1}{38}\right)}{5\left(\frac{1}{2}+\frac{1}{8}-\frac{1}{38}\right)}\) . \(\frac{15\left(1+\frac{1}{17}-\frac{1}{144}+\frac{1}{34}\right)}{2\left(1+\frac{1}{17}-\frac{1}{144}+\frac{1}{34}\right)}\)+2018
=\(\frac{6}{5}\) . \(\frac{15}{2}\)+2018
=9+2018
=2027
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Thực hiện phép tính
\(B=\frac{3+0,75-\frac{3}{19}}{\frac{5}{2}+0,625-\frac{5}{38}}.\frac{15+\frac{15}{17}-\frac{15}{144}+\frac{15}{34}}{2+\frac{3}{17}-\frac{2}{144}}+2018\)
\(a.A=[\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}+\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}]+\frac{1890}{2005}+115\)
b.B=\(\left[\frac{1\frac{11}{31}\cdot4\frac{3}{7}-\left(15-6\cdot\frac{1}{3}\cdot\frac{2}{19}\right)}{4\frac{5}{6}+\frac{1}{6}\left(42-5\frac{1}{3}\right)}\cdot\left(-1\frac{19}{93}\right)\right]\cdot\frac{31}{50}\)
Tìm x:
\(\frac{\left(13\frac{2}{9}-15\frac{2}{3}\right)\cdot\left(30^2-5^4\right)}{\left(18\frac{3}{7}-17\frac{1}{4}\right)\cdot\left(25-12\cdot5^2\right)}\cdot x=\frac{\frac{2}{11}+\frac{3}{13}+\frac{4}{15}+\frac{5}{17}}{4\frac{1}{11}+\frac{5}{13}+\frac{9}{15}+\frac{13}{17}}\)
B=((3+0,75)-3/19)/(5/+0,625-5/38) × (15+15/17-15/144+15/34)/(2+3/17-2/144)+2018
2,Thực hiện phép tính(tính nhanh nếu có thể)
a,frac{2}{3}+frac{1}{3}cdotleft(-frac{2}{5}right)
b,0,75cdot1frac{7}{9}-1frac{2}{5}:frac{-21}{20}
c,frac{-2}{17}+frac{15}{23}+frac{15}{-17}-frac{-4}{19}+frac{8}{23}
d,2019^0cdotleft(6-2frac{4}{5}right)cdot3frac{1}{8}-1frac{3}{5}:25phần trăm
e,left(frac{7}{8}-frac{1}{2}right)cdot2frac{2}{3}-frac{3}{7}cdotleft(2,5^2right)
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2,Thực hiện phép tính(tính nhanh nếu có thể)
a,\(\frac{2}{3}+\frac{1}{3}\cdot\left(-\frac{2}{5}\right)\)
b,\(0,75\cdot1\frac{7}{9}-1\frac{2}{5}:\frac{-21}{20}\)
c,\(\frac{-2}{17}+\frac{15}{23}+\frac{15}{-17}-\frac{-4}{19}+\frac{8}{23}\)
d,\(2019^0\cdot\left(6-2\frac{4}{5}\right)\cdot3\frac{1}{8}-1\frac{3}{5}:25\)phần trăm
e,\(\left(\frac{7}{8}-\frac{1}{2}\right)\cdot2\frac{2}{3}-\frac{3}{7}\cdot\left(2,5^2\right)\)
a) \(\frac{2}{3}+\frac{1}{3}\cdot\left(-\frac{2}{5}\right)\\ =\frac{2}{3}+\frac{-2}{15}\\ =\frac{10}{15}+\frac{-2}{15}\\ =\frac{8}{15}\)
b) \(0,75\cdot1\frac{7}{9}-1\frac{2}{5}:\frac{-21}{20}\\ =\frac{3}{4}\cdot\frac{16}{9}-\frac{7}{5}\cdot\frac{-20}{21}\\ =\frac{4}{3}-\frac{-4}{3}\\ =\frac{4}{3}+\frac{4}{3}\\ =\frac{4}{3}\cdot2\\ =\frac{8}{3}\)
c) \(\frac{-2}{17}+\frac{15}{23}+\frac{15}{-17}-\frac{-4}{19}+\frac{8}{23}\\ =\frac{-2}{17}+\frac{15}{23}+\frac{-15}{17}+\frac{4}{19}+\frac{8}{23}\\ =\left(\frac{-2}{17}+\frac{-15}{17}\right)+\left(\frac{15}{23}+\frac{8}{23}\right)+\frac{4}{19}\\ =\left(-1\right)+1+\frac{4}{19}\\ =0+\frac{4}{19}\\ =\frac{4}{19}\)
d) \(2019^0\cdot\left(6-2\frac{4}{5}\right)\cdot3\frac{1}{8}-1\frac{3}{5}:25\%\\ =1\cdot\left(\frac{30}{5}-\frac{14}{5}\right)\cdot\frac{25}{8}-\frac{8}{5}:\frac{1}{4}\\ =1\cdot\frac{16}{5}\cdot\frac{25}{8}-\frac{8}{5}\cdot4\\ =\frac{16}{5}\cdot\frac{25}{8}-\frac{32}{5}\\ =\frac{50}{5}-\frac{32}{5}\\ =\frac{18}{5}\)
e) \(\left(\frac{7}{8}-\frac{1}{2}\right)\cdot2\frac{2}{3}-\frac{3}{7}\cdot\left(2,5^2\right)\\ =\left(\frac{7}{8}-\frac{4}{8}\right)\cdot\frac{8}{3}-\frac{3}{7}\cdot6,25\\ =\frac{3}{8}\cdot\frac{8}{3}-\frac{3}{7}\cdot\frac{25}{4}\\ =1-\frac{75}{28}\\ =\frac{28}{28}-\frac{75}{28}\\ =\frac{-47}{28}\)
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a, \(\frac{2}{3}+\frac{1}{3}.\left(\frac{-2}{5}\right)\)
= \(\frac{2}{3}+\frac{-2}{15}=\frac{8}{15}\)
b, \(0,75.1\frac{7}{9}-1\frac{2}{5}:\frac{-21}{20}\)
= \(\frac{3}{4}.\frac{16}{9}-\frac{7}{5}.\frac{-20}{21}\)
= \(\frac{4}{3}-\left(\frac{-4}{3}\right)=\frac{8}{3}\)
c, \(\frac{-2}{17}+\frac{15}{23}+\frac{15}{-17}+\frac{4}{19}+\frac{8}{23}\)
= \(\left(\frac{-2}{17}+\frac{-15}{17}\right)+\left(\frac{15}{23}+\frac{8}{23}\right)+\frac{4}{19}\)
= \(\left(-1\right)+1+\frac{4}{19}=0+\frac{4}{19}=\frac{4}{19}\)
d, \(\left(6-2\frac{4}{5}\right).3\frac{1}{8}-1\frac{3}{5}:25\%\)
=> \(\left(6-\frac{14}{5}\right).\frac{25}{8}-\frac{8}{5}:25\%\)
= \(\frac{16}{5}.\frac{25}{8}-\frac{8}{5}.25:100\)
= 10 - 0,4 = 9,6
e, \(\left(\frac{7}{8}-\frac{1}{2}\right).2\frac{2}{3}-\frac{3}{7}.\left(2,5^2\right)\)
=> \(\frac{3}{8}.\frac{8}{3}-\frac{3}{7}.6,25\)
= \(1-\frac{75}{28}=\frac{-47}{28}\)
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(3+0,75-3/19)/(5/2+0,625 -5/38)×(15+15/17-15/144+15/34)/(2+3/17-2/144)+2018
tính giá trị biểu thứcAfrac{-378.132+189.64}{15+18+21+......+45+48}B1,4.frac{15}{14}-left(frac{4}{5}+frac{2}{5}right):2frac{1}{5}-frac{frac{73}{77}+frac{73}{165}+frac{73}{285}}{frac{25}{24}+frac{15}{180}+frac{20}{285}}Cfrac{7+frac{7}{12}-frac{7}{144}+frac{7}{60}}{5+frac{6}{12}-frac{5}{144}}.frac{frac{3}{4}-frac{3}{16}+frac{3}{64}-frac{3}{256}}{1-frac{1}{4}+frac{1}{16}-frac{1}{34}}-frac{1}{20}
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tính giá trị biểu thức
\(A=\frac{-378.132+189.64}{15+18+21+......+45+48}\)
\(B=1,4.\frac{15}{14}-\left(\frac{4}{5}+\frac{2}{5}\right):2\frac{1}{5}-\frac{\frac{73}{77}+\frac{73}{165}+\frac{73}{285}}{\frac{25}{24}+\frac{15}{180}+\frac{20}{285}}\)
\(C=\frac{7+\frac{7}{12}-\frac{7}{144}+\frac{7}{60}}{5+\frac{6}{12}-\frac{5}{144}}.\frac{\frac{3}{4}-\frac{3}{16}+\frac{3}{64}-\frac{3}{256}}{1-\frac{1}{4}+\frac{1}{16}-\frac{1}{34}}-\frac{1}{20}\)
tính nhanhfrac{19}{37}+left(1-frac{19}{37}right)frac{7}{13}cdotfrac{5}{14}cdotfrac{39}{15}2frac{3}{7}cdotfrac{1}{2}-frac{1}{2}cdotfrac{3}{7}+frac{1}{3}frac{9}{5}:frac{17}{15}+frac{8}{5}:frac{17}{15}frac{2017}{2018}cdotfrac{1}{2019}+frac{2017}{2018}:frac{2019}{2018}+frac{1}{2018}frac{637cdot527-189}{526cdot637+448}frac{4}{5cdot7}+frac{4}{7cdot9}+frac{4}{9cdot11}+...+frac{4}{23cdot25}dấu . là dấu nhân nha mọi người
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tính nhanh
\(\frac{19}{37}+\left(1-\frac{19}{37}\right)\)
\(\frac{7}{13}\cdot\frac{5}{14}\cdot\frac{39}{15}\)
\(2\frac{3}{7}\cdot\frac{1}{2}-\frac{1}{2}\cdot\frac{3}{7}+\frac{1}{3}\)
\(\frac{9}{5}:\frac{17}{15}+\frac{8}{5}:\frac{17}{15}\)
\(\frac{2017}{2018}\cdot\frac{1}{2019}+\frac{2017}{2018}:\frac{2019}{2018}+\frac{1}{2018}\)
\(\frac{637\cdot527-189}{526\cdot637+448}\)
\(\frac{4}{5\cdot7}+\frac{4}{7\cdot9}+\frac{4}{9\cdot11}+...+\frac{4}{23\cdot25}\)
dấu . là dấu nhân nha mọi người
\(\frac{19}{37}+\left(1-\frac{19}{37}\right)\)
\(=\frac{19}{37}+1-\frac{19}{37}\)
\(=\left(\frac{19}{37}-\frac{19}{37}\right)+1\)
\(=0+1=1\)
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