c: =>(x+2)(x+3)(x-5)(x-6)=180

=>(x^2-3x-10)(x^2-3x-18)=180

=>(x^2-3x)^2-28(x^2-3x)=0

=>x(x-3)(x-7)(x+4)=0

=>\(x\in\left\{0;3;7;-4\right\}\)

c: =>(x-3)(x+2)(2x+1)(3x-1)=0

=>\(x\in\left\{3;-2;-\dfrac{1}{2};\dfrac{1}{3}\right\}\)

2) \(\left(x+3\right)\left(5x-15\right)+2x-6=0\)

\(\Leftrightarrow\left(x+3\right).5.\left(x-3\right)+2\left(x-3\right)=0\)

\(\Leftrightarrow\left(x-3\right)\left[5\left(x+3\right)+2\right]=0\)

\(\Leftrightarrow\left(x-3\right)\left(5x+17\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\5x+17=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-\dfrac{17}{5}\end{matrix}\right.\)

câu 1 phải là \(\left(x-5\right)\left(x+9\right)+6x=30\)

\(\Leftrightarrow\left(x-5\right)\left(x+9\right)+6x-30=0\)

\(\Leftrightarrow\left(x-5\right)\left(x+9\right)+6\left(x-5\right)=0\)

\(\Leftrightarrow\left(x-5\right)\left(x+9+6\right)=0\)

\(\Leftrightarrow\left(x-5\right)\left(x+15\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-5=0\\x+15=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=-15\end{matrix}\right.\)

tìm hả bn

`3x - 6/20=5x - 9 /30`

`=> 3x-5x= -9/30 + 6/20`

`=> -2x= 0`

`=>x=0:(-2)`

`=>x=0`

\(a,\left(x-2\right)^2-\left(x-3\right)\left(x^2+3x+9\right)+6\left(x+1\right)^2=15\)\(\Leftrightarrow x^3-6x^2+12x-8-x^3+27+6\left(x^2+2x+1\right)=15\)\(\Leftrightarrow-6x^2+12x+19+6x^2+12x+6=15\)

\(\Leftrightarrow24x=-10\)

\(\Leftrightarrow x=-\dfrac{5}{12}\)

Vậy:....

\(b,\left(5x+1\right)^2-\left(5x+3\right)\left(5x-3\right)=30\)

\(\Leftrightarrow25x^2+10x+1-25^2+9=30\)

\(\Leftrightarrow10x=20\)

\(\Rightarrow x=2\)

Vậy :....

\(c,\left(x+3\right)\left(x^2-3x+9\right)-x\left(x-2\right)\left(x+2\right)=15\)\(\Leftrightarrow x^3+27-x\left(x^2-4\right)=15\)

\(\Leftrightarrow x^3+27-x^3+4x=15\)

\(\Leftrightarrow4x=15-27=-12\)

\(\Leftrightarrow x=-3\)

vậy : .....

1 , <=>  25x^2 + 10x + 1 - ( 25x^2 - 9) = 30 

      <=> 25x^2 + 10x + 1 - 25x^2 + 9 = 30 

      <=> 10x + 10                 = 30 

     <=> 10 ( x + 1)                 = 30

       <=>  x + 1                      = 3 

        <=>  x                           = 2 

2, ( x + 3)(x^2 - 3x + 9 ) - x(x+2)(x-2) = 15 

<=> x^3 - 27 - x(x^2 - 4)                      = 15

<=> x^3 - 27 - x^3 + 4x                        = 15 

<=> 4x -27                                          = 15 

<=> 4x                                                = 15 + 27

<=> 4x                                                 =42

<=> x                                                     = 42/4 = 21/2 

******************

 (x+2)^2= 9 
=> (x+2)^2= 3^2=(-3)^2
TH1: x+2=3
=> x=3-2=1
TH2: x+2=-3
=> x=(-3)-2=-5

Bài làm :

\(a,\left(x+2\right)^2-9=0\)

\(\Leftrightarrow\left(x+2\right)^2=9\)

\(\Leftrightarrow\left(x+2\right)^2=3^2\)

\(\Leftrightarrow\orbr{\begin{cases}x+2=3\\x+2=-3\end{cases}}\Rightarrow\orbr{\begin{cases}x=1\\x=-5\end{cases}}\)

Vậy x = 1 hoặc x = -5 .

\(b,\left(5x+1\right)^2-\left(5x-3\right)\left(5x+3\right)=30\)

\(\Leftrightarrow25x^2+10x+1-\left(25x^2-3^2\right)=30\)

\(\Leftrightarrow25x^2+10x+1-25x^2+9=30\)

\(\Leftrightarrow\left(25x^2-25x^2\right)+10x=30-9-1\)

\(\Leftrightarrow10x=20\)

\(\Leftrightarrow x=2\)

Vậy x = 2 .

\(c,\left(x-1\right)\left(x^2+x+1\right)+x\left(x+2\right)\left(2-x\right)=5\)

\(\Leftrightarrow x^3+x^2+x-x^2-x-1+\left(x^2+2x\right)\left(2-x\right)=5\)

\(\Leftrightarrow x^3-1+2x^2-x^3+4x-2x^2=5\)

\(\Leftrightarrow\left(x^3-x^3\right)+\left(2x^2-2x^2\right)+4x=5+1\)

\(\Leftrightarrow4x=6\)

\(\Leftrightarrow x=\frac{3}{2}\)

Vậy x = 3/2 .

Học tốt nhé

( x + 2 )² - 9 = 0

<=> ( x + 2 )² - 3² = 0

<=> ( x + 2 - 3 )( x + 2 + 3 ) = 0

<=> ( x - 1 )( x + 5 ) = 0

<=> x = 1 hoặc x = -5

( 5x + 1 )² - ( 5x - 3 )( 5x + 3 ) = 30

<=> 25x² + 10x + 1 - ( 25x² - 9 ) = 30

<=> 25x² + 10x + 1 - 25x² + 9 = 30

<=> 10x + 10 = 30

<=> 10x = 20

<=> x = 2

( x - 1 )( x² + x + 1 ) + x( x + 2 )( 2 - x ) = 5

<=> x³ - 1 + x( 4 - x² ) = 5

<=> x³ - 1 + 4x - x³ = 5

<=> 4x - 1 = 5

<=> 4x = 6

<=> x = 6/4 = 3/2

1) 2(3x+5)-6=9 

  2(3x+5)    =9+6

  2(3x+5)    =15

    3x+5     = 15:2

   3x+5    = \(\frac{15}{2}\)

  3x      = \(\frac{15}{2}-5\)

  3x        =\(\frac{5}{2}\)

   x        = \(\frac{5}{2}:3\)

   x       = \(\frac{5}{6}\)

2) 5x+3(4+2x)=25

   5x+12+6x=25

   5x+6x      =-12+25

   11x          =13

      x           =13:11

      x           =\(\frac{13}{11}\)

3) 3(4x+1)+2(x-1)=105

   12x+3+2x-2=105

   12x+2x      = -3+2+105

    14x           =104

       x            = 104:14

       x            = \(\frac{52}{7}\)

4) \(30-[2\left(x-3\right)-2]=14\)

                 \(2\left(x-3\right)-2\)=\(30-14\)

                 \(2\left(x-3\right)-2=16\)

                 \(2\left(x-3\right)=16+2\)

                  \(2\left(x-3\right)=18\)

                  \(x-3=18:2\)

                  \(x-3=9\)

                  \(x=9+3\)

                  \(x=12\)

     k mình nha !!!!!!