Lần sau bạn nên viết đề rõ hơn nhé!

Đề: Tính nhanh: \(\frac{10^3+2\cdot5^3+5^3}{55}\)

ta có: \(\frac{10^3+2\cdot5^3+5^3}{55}=\frac{5^3\left(2^3+2+1\right)}{5\cdot11}=\frac{5^3\cdot11}{5\cdot11}=5^2=25\)

Học tốt nhé ^3^

Ta có : \(\frac{10^3+2.5^3+5^3}{55}=\frac{2^3.5^3+2.5^3+5^3}{5.11}=\frac{5^3\left(2^3+2+1\right)}{5.11}=\)\(\frac{5^3.11}{5.11}=5^2=25\)

Vậy \(\frac{10^3+2.5^3+5^3}{5.11}\)=25.

a)\(\frac{10^3+2.5^3+5^3}{55}\)=\(\frac{5^3.2^3+2.5^3+5^3}{5.11}\)=\(\frac{5^3.\left(2^3+2+1\right)}{5.11}\)=\(5^2\)=\(25\)

b) \(2^x+2^{x+3}=144\)

\(\Rightarrow2^x+2^x.2^3=144\)

\(\Rightarrow2^x.\left(1+2^3\right)=144\)

\(\Rightarrow2^x=16=2^4\)

\(\Rightarrow x=4\)

c) \(2\left(x-5\right)+3\left(x-7\right)=10\)

\(\Rightarrow2x-10+3x-21=10\)

\(\Rightarrow5x-31=10\)

\(\Rightarrow5x=41\)

\(\Rightarrow x=\frac{41}{5}=8,2\)

\(\frac{10^3+2.5^3+5^3}{55}\)

\(=\frac{\left(2.5\right)^3+2.5^3+5^3}{5.11}\)

=\(\frac{2^3.5^3+2.5^3+5^3}{5.11}\)

=\(\frac{5^3.\left(2^3+2+1\right)}{5.11}\)

=\(\frac{5^3.\left(8+2+1\right)}{5.11}\)

=\(\frac{5^3.11}{5.11}\)

=\(5^2\)

=25

Chúc bn học tốt !

= 25 nha bạn 

các bạn tick mình cho tròn 220 điểm hỏi đáp với

\(=\frac{5^3.\left(2^3+2+1\right)}{55}=\frac{5^2.5.11}{5.11}=5^2=25\)

\(\frac{10^3+2\times5^3+5^3}{55}\)= \(\frac{1000+2\times125+125}{55}\)= \(\frac{1000+250+125}{55}\)= \(\frac{1250+125}{55}\)= \(\frac{1375}{55}\)= 25.

\(\frac{10^3+2.5^3+5^3}{55}=\frac{1000+2.125+125}{55}=\frac{1375}{55}=25\)

chìu mk lm nha

Giờ mk có việc rồi

Nhớ tick cho mk nha !!!!!