[(4X+48)3+55] CHIA 5 =35
[(4x+28).3+55]:5=35
⇒ ( 4x + 28 ) . 3 + 55 = 35 . 5
⇒ ( 4x + 28 ) . 3 + 55 = 175
⇒ ( 4x + 28 ) . 3 = 175 - 55
⇒ ( 4x + 28 ) .3 = 120
⇒ 4x + 28 = 120 : 3
⇒ 4x + 28 = 40
⇒ 4x = 40 - 28
⇒ 4x = 12
⇒ x = 12: 4
⇔ x = 3.
Vậy x= 3.
\(\left[\left(4x+28\right)\times3+55\right]\div5=35\)
\(\left(4x+28\right)\times3+55=175\)
\(12x+84+55=175\)
\(12x=175-55-84\)
\(12x=36\)
\(x=3\)
`@` `\text {Ans}`
`\downarrow`
`b)`
\([(4x+28).3+55] \div 5=35\)
`=> (4x + 28) * 3 + 55 = 35 * 5`
`=> (4x + 28)*3 + 55 = 175`
`=> (4x + 28)*3 = 175 - 55`
`=> (4x + 28)*3 =120`
`=> 4x + 28 = 120 \div 3`
`=> 4x + 28 = 40`
`=> 4x = 40 - 28`
`=> 4x = 12`
`=> x = 12 \div 4`
`=>x = 3`
Vậy, `x = 3.`
=>[12x+84+55]=175
=>12x=175-84-55=120-84=36
=>x=36/12=3
<=>[12x+84+55]:5=35
<=>[12x+139]:5=35
<=>12x+139=35.5
<=>12x=175-139
<=>x=3
[(4x+28).3+55] :5= 35
mik tính đc 11 bn nha
b, [(4x+28) .3+ 55]/5= 35
[(4x + 28).3 + 55] : 5 = 35
=> (4x + 28).3 + 55 = 175
=> (4x + 28).3 = 120
=> 4x + 28 = 40
=> 4x = 12
=> x = 3
vậy_
bài1:
a)128-3(x+4)=23
b)[(4x+28).3+55]:5=35
c)(12-4^3).8^3=4.8^4
d)720:[41-(2x-5)]=2^3.5
e)2^x+2^x+1=48
f)(x-2)^2=(x-2)^4
128-3(x+4)=23
3(x+4)=128-23
3(x+4)=105
x+4=105:3
x+4=35
x=35-4
x=31
Vậy x=31
Học tốt
[(4x+28).3+55]:5=35
[(4x+28).3+55]:5=35
[(4x+28).3+55]=35.5
[(4x+28).3+55]=175
(4x+28).3=175-55
(4x+28).3=120
4x+28=120:3
4x+28=40
4x=40-28
4x=12
x=12:4
x=3
k cho mik nhoa bn nha!
[ ( 4x + 28 ) . 3 + 55 ] :5 = 35
( 4x + 28 ) . 3 + 55 = 175
( 4x + 28 ) . 3 = 120
( 4x + 28 ) = 40
4x = 12
x = 3
cảm ơn các bạn giờ thì mình đã biết mình sai ở chỗ nào rồi cảm ơn
Tìm số tự nhiên x, biết:
a, 128 – 3( x + 4 ) = 23
b, [( 4x + 28 ).3 + 55] : 5 = 35
a) \(128-3\left(x+4\right)=23\)
\(\Rightarrow3\left(x+4\right)=128-23\)
\(\Rightarrow3\left(x+4\right)=105\)
\(\Rightarrow x+4=35\)
\(\Rightarrow x=35-4\)
\(\Rightarrow x=31\)
b) \(\left[\left(4x+28\right)\cdot3+55\right]:5=35\)
\(\Rightarrow\left(4x+28\right)\cdot3+55=35\cdot5\)
\(\Rightarrow\left(4x+28\right)\cdot3+55=175\)
\(\Rightarrow\left(4x+28\right)\cdot3=120\)
\(\Rightarrow4x+28=40\)
\(\Rightarrow4x=12\)
\(\Rightarrow x=3\)
a, \(128-3\left(x+4\right)=23\)
\(=>3\left(x+4\right)=128-23\)
\(=>3\left(x+4\right)=105\)
\(=>x+4=105:3\)
\(=>x+4=35\)
\(=>x=35-4\)
\(=>x=31\)
b, \(\left[\left(4x+28\right).3+55\right]:5=35\)
\(=>\left(4x+28\right).3+55=35.5\)
\(=>\left(4x+28\right).3+55=175\)
\(=>\left(4x+28\right).3=175-55\)
\(=>\left(4x+28\right).3=120\)
\(=>4x+28=120:3\)
\(=>4x+28=40\)
\(=>4x=40-28\)
\(=>4x=12\)
\(=>x=12:4\)
\(=>x=3\)
\(#WendyDang\)
a) 128 - 3 (x + 4) =23
3.( x + 4) = 128 -23
3. ( x + 4) = 105
x + 4 = 105 :3
x + 4 = 35
x = 35 -4
x = 31
[ ( 4x + 28 ). 3 + 55 ] ÷ 5 = 35
Giúp mk vs mj đang gấp
\(\left[\left(4x+28\right).3+55\right]:5=35\)
\(\Rightarrow\left(4x+28\right).3+55=35.5\)
\(\Rightarrow\left(4x+28\right).3+55=175\)
\(\Rightarrow\left(4x+28\right).3=175-55\)
\(\Rightarrow\left(4x+28\right).3=120\)
\(\Rightarrow4x+28=120:3\)
\(\Rightarrow4x+28=40\)
\(\Rightarrow4x=40-28\)
\(\Rightarrow4x=12\)
\(\Rightarrow x=12:4\)
\(\Rightarrow x=3\)
[ ( 4x + 28 ). 3 + 55 ] ÷ 5 = 35
( 4x + 28 ). 3 + 55 = 35.5
( 4x + 28 ). 3 + 55 = 175
( 4x + 28 ). 3 = 175 - 55
( 4x + 28 ). 3 = 120
4x + 28 = 120 : 3
4x + 28 = 40
4x = 40 - 28
4x = 12
x = 12 : 4
x = 3
[[48+28].3+55]:5=35
dấu chấm là dấu nhân nhé lớp 6 dấu nhân thành dấu chấm