\(124+\left(13-16\right)=162-\left(x+162\right).\)

\(124+13-16=162-\left(x+162\right)\)

\(121=162-\left(x+162\right)\)

\(41=x+162\)

\(x=41-162=\left(-121\right)\)

124 + ( 13 – 16 ) = 162 – ( x + 162 )

124 + (-3)            = 162 - ( x + 162 )

121                      = 162 - ( x + 162 )

\(\Rightarrow\)162 - ( x + 162 ) = 121

         162 - x - 162      = 121

         ( 162 - 162 ) - x  = 121

               0      - x         = 121

                  - x              = 121

\(\Rightarrow\)           x              = -121

x=-121

k nhé!!!

a) \(\left(x-7\right)-\left(5-x\right)=12-\left(-8+x\right)\)

\(\Leftrightarrow x-7-5+x=12+8-x\)

\(\Leftrightarrow2x-12=20-x\)

\(\Leftrightarrow2x+x=12+20\)

\(\Leftrightarrow3x=32\)

\(\Leftrightarrow x=\frac{32}{3}\)

b) 124 + ( 13 - 16 ) = 162 - ( x + 162 )

<=> 124 - 3 = 162 - x - 162

<=> 121 = -x

<=> x = -121

mn giải đáp án ra giúp mik nha,mik cảm ơn nhiều!Thank you!

mn bt câu nào làm câu đó ạ,mik làm ơn

Mn giúp mik thì mn mún j mik cx giúp đc ạ

Chỉ cần mn giúp mik thôi là mik vui lắm rồi.

1014 : ( 124 - x ) = 13

             124 - x  = 1014 : 13

             124 - x  = 78

                     x  = 124 - 78

                     x  =        46

1014:(124-x)=13

124-x=1014:13=78

x=124-78

x=46

Bạn vào thanh công cụ để gõ công thức nhé

Bạn vào biểu tượng dấu Σ xong rồi vào {:} để gõ hệ phương trình nhé

Áp dụng t/c dtsbn ta có

\(\dfrac{x}{12}=\dfrac{y}{13}=\dfrac{3x+2y}{3.12+2.13}=\dfrac{124}{62}=2\)

\(\dfrac{x}{12}=2\Rightarrow x=24\\ \dfrac{y}{13}=2\Rightarrow y=26\)

\(\dfrac{x}{12}=\dfrac{y}{13}=\dfrac{3x+2y}{3.12+2.13}=\dfrac{124}{62}=2\)

\(\left\{{}\begin{matrix}x=12.2=24\\y=13.2=26\end{matrix}\right.\)

\(\dfrac{x-187}{13}+\dfrac{x-170}{15}+\dfrac{x-149}{17}+\dfrac{x-124}{19}=10\)

`<=>(x-187)/13+(x-170)/15+(x-149)/17+(x-124)/19-10=0`

`<=>(x-187)/13-1+(x-170)/15-2+(x-149)/17-3+(x-124)/19-4=0`

`<=>(x-200)/13+(x-200)/15+(x-200)/17+(x-200)/19=0`

`<=>(x-200)(1/13+1/15+1/17+1/19)=0`

`<=>x-200=0(1/13+1/15+1/17+1/19>0)`

`<=>x=200`

\(=>\left(\dfrac{x-187}{13}-1\right)+\left(\dfrac{x-170}{15}-2\right)+\left(\dfrac{x-149}{17}-3\right)+\left(\dfrac{x-124}{19}-4\right)=0\)\(< =>\left(\dfrac{x-187}{13}-\dfrac{13}{13}\right)+\left(\dfrac{x-170}{15}-\dfrac{30}{15}\right)+\left(\dfrac{x-149}{17}-\dfrac{51}{17}\right)+\left(\dfrac{x-124}{19}-\dfrac{76}{19}\right)=0\)

\(< =>\left(\dfrac{x-200}{13}\right)+\left(\dfrac{x-200}{15}\right)+\left(\dfrac{x-200}{17}\right)+\left(\dfrac{x-200}{19}\right)=0\)

\(< =>\left(x-200\right)\left(\dfrac{1}{13}+\dfrac{1}{15}+\dfrac{1}{17}+\dfrac{1}{19}\right)=0\)

\(< =>x-200=0\)

<=>x=200

=>\(\left(\dfrac{x-187}{13}-1\right)+\left(\dfrac{x-170}{15}-2\right)+\left(\dfrac{x-149}{17}-3\right)+\left(\dfrac{x-124}{19}-4\right)=0\)

=>x-200=0

=>x=200

1: \(=-24\left(45-5\right)=-24\cdot40=-960\)

2: \(=-134\left(1-51+48\right)=-134\cdot\left(-2\right)=268\)

3: \(=124\left(1-52+47\right)=124\cdot\left(-3\right)=-372\)