Áp dụng t/c dtsbn ta có
\(\dfrac{x}{12}=\dfrac{y}{13}=\dfrac{3x+2y}{3.12+2.13}=\dfrac{124}{62}=2\)
\(\dfrac{x}{12}=2\Rightarrow x=24\\ \dfrac{y}{13}=2\Rightarrow y=26\)
\(\dfrac{x}{12}=\dfrac{y}{13}=\dfrac{3x+2y}{3.12+2.13}=\dfrac{124}{62}=2\)
\(\left\{{}\begin{matrix}x=12.2=24\\y=13.2=26\end{matrix}\right.\)