\(E=5.4-4.3+5-0,3.20=20-12+5-6=7\)

=5x4-4x3+5-6

=20-12-1

=7

\(=20-12+5-6\)

\(=7\)

= 20 - 12 + 5 - 6

= 7

\(5\sqrt{16}-4\sqrt{9}-\sqrt{25}-0,3\sqrt{400}\)

\(=5.4-4.3+5-0,3.20\)

\(=20-12+5-6\)

\(=7\)

\(5.\sqrt{16}-4.\sqrt{9}+\sqrt{25}-0,3.\sqrt{400}\)

\(=5.4-4.3+5-\frac{3}{10}.20\)

\(=20-12+5-6\)

\(=8+5-6\)

\(=13-6\)

\(=7\)

=5*4-4*3+5-0.3*20

=20-12+5-6

=8+5-6

=13-6

=7

Ta có : \(5\sqrt{16}-4\sqrt{9}+\sqrt{25}\)-0,3\(\sqrt{400}\)

= 5.4 - 4.3 + 5 - 0,3.20

= 20-12+5-6

= 9

a) ĐKXĐ: x <= 2

pt --> 4 - 2x = 25 <=> x = -21/2 (thỏa)

??

Đề kiểu gì vậy ?

b) ĐKXĐ: x >= -1

pt <=> 8sqrt(x + 1)=16 <=> sqrt(x+1)=2 --> x + 1 = 4 <=> x = 3

a, ĐKXĐ: \(x\le2\)

\(\sqrt{4-2x}=5\\ \Leftrightarrow4-2x=25\\ \Leftrightarrow2x=-21\\ \Leftrightarrow x=-10,5\left(tm\right)\)

b, ĐKXĐ: \(x\ge-1\)

\(\sqrt{25\left(x+1\right)}+\sqrt{9x+9}=16\\ \Leftrightarrow5\sqrt{x+1}+\sqrt{9\left(x+1\right)}=16\\ \Leftrightarrow5\sqrt{x+1}+3\sqrt{x+1}=16\\ \Leftrightarrow8\sqrt{x+1}=16\\ \Leftrightarrow\sqrt{x+1}=2\\ \Leftrightarrow x+1=4\\ \Leftrightarrow x=3\)

c, \(\sqrt{4x^2+12x+9}=4\Leftrightarrow4x^2+12x+9=16\\ \Leftrightarrow4x^2+12x-7=0\\ \Leftrightarrow\left(4x^2-2x\right)+\left(14x-7\right)=0\\ \Leftrightarrow2x\left(2x-1\right)+7\left(2x-1\right)=0\\ \Leftrightarrow\left(2x-1\right)\left(2x+7\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-\dfrac{7}{2}\end{matrix}\right.\)

a: \(\Leftrightarrow4-2x=25\)

hay \(x=-\dfrac{21}{2}\)

c: \(\Leftrightarrow\left|2x+3\right|=4\)

\(\Leftrightarrow\left[{}\begin{matrix}2x+3=4\\2x+3=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-\dfrac{7}{2}\end{matrix}\right.\)

\(5\sqrt{16}-4\sqrt{9}+\sqrt{25}-\sqrt{400}\)

\(=5.4-4.3+5-20\)

\(=20-12+5-20\)

\(=-7\)

5√16−4√9+√25−√400

=5.4−4.3+5−20

=20−12+5−20

=8+5-20

=13-20

=-7