a) 3/35 - (3/5 + x) = 2/7

=> 3/5 + x= 3/35- 2/7

=> 3/5 +x = -1/5

=> x = -1/5 -3/5

=> x = -4/5

b) 3/7 +1/7 : x = 3/14

=> 1/7 : x= 3/14 -3/7

=> 1/7 : x = -3/14

=> x = 1/7 : -3/14 

=> x = -2/3

c) (5x-1).(2x-1/3)=0

=> \(\left[{}\begin{matrix}5x-1=0\\2x-\dfrac{1}{3}=0\end{matrix}\right.\)

=> \(\left[{}\begin{matrix}5x=0+1=1\\2x=0+\dfrac{1}{3}=\dfrac{1}{3}\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=\dfrac{1}{5}\\x=\dfrac{1}{3}:2=\dfrac{1}{6}\end{matrix}\right.\)

Học tốt :D

a)x=-4/5

b)x=-2/3

c)\(\left\{{}\begin{matrix}5x-1=0\\2x-\dfrac{1}{3}=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}5x=1\\2x=\dfrac{1}{3}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{1}{5}\\x=\dfrac{1}{6}\end{matrix}\right.\)

Vậy.........

mik lười mong bn thông cảm

a) \(\dfrac{3}{35}-\left(\dfrac{3}{5}+x\right)=\dfrac{2}{7}\\ \Rightarrow\dfrac{3}{5}+x=-\dfrac{1}{5}\\ \Rightarrow x=-\dfrac{4}{5}\)

b) \(\dfrac{3}{7}+\dfrac{1}{7}:x=\dfrac{3}{14}\\ \Rightarrow\dfrac{1}{7}:x=-\dfrac{3}{14}\\ \Rightarrow x=-\dfrac{2}{3}\)

c) \(\left(5x-1\right)\left(2x-\dfrac{1}{3}\right)=0\\ \Leftrightarrow\left\{{}\begin{matrix}5x-1=0\\2x-\dfrac{1}{3}=0\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}5x=1\\2x=\dfrac{1}{3}\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{1}{5}\\x=\dfrac{1}{6}\end{matrix}\right.\)

\(1)\frac{12}{7}\times \frac{7}{4}+\frac{35}{11}:\frac{245}{121}\)

\(=3+\frac{35}{11}\times \frac{121}{245}\)

\(=3+\frac{11}{7}\)

\(= 3\frac{1}{7}(=\frac{22}{7})\)

ms cs 1 câu nên mk chưa cho k đâu

Bài 1

= \(\frac{22}{7}\)

bài 3

x = 4

y = 3

k mik nhé

-(1/3)-1/15-1/35-...-1/x.(x+2)=20/-21

=>1/3+1/15+1/35+...+1/x(x+2)=20/21

=>1/2 * (2/3 + 2/15 + 2/35 + ... + 2/x(x+2) )=20/21

=>\(\dfrac{2}{1\cdot3}+\dfrac{2}{3.5}+\dfrac{2}{5.7}+...+\dfrac{2}{x\left(x+2\right)}=\dfrac{20}{21}:\dfrac{1}{2}\)

=>\(1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{x}-\dfrac{1}{x+2}=\dfrac{40}{41}\)

=>\(1-\dfrac{1}{x+2}=\dfrac{40}{41}\)

=>\(\dfrac{1}{x+2}=1-\dfrac{40}{41}=\dfrac{1}{41}\)

=>x+2=41=>x=39

(1/3)-1/15-1/35-...-1/x.(x+2)=20/-21

=>1/3+1/15+1/35+...+1/x(x+2)=20/21

=>1/2 * (2/3 + 2/15 + 2/35 + ... + 2/x(x+2) )=20/21

=>1−13+13−15+15−17+...+1x−1x+2=40411−13+13−15+15−17+...+1x−1x+2=4041

=>

Bài 1: 

a: \(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{1}{3}=\dfrac{1}{2}\\x-\dfrac{1}{3}=-\dfrac{1}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{6}\\x=-\dfrac{1}{6}\end{matrix}\right.\)

= \(\dfrac{44}{105}\) <  \(\dfrac{x}{210}\) <\(\dfrac{158}{105}\) = \(\dfrac{88}{210}< \dfrac{x}{210}< \dfrac{316}{210}\) 
=> x = 89 -> 315

=> x = 89 -> 315

loại trừ bớt đi rùi tìm x 

\(\frac{3}{5.7}+\frac{3}{7.9}+...+\frac{3}{x.\left(x+2\right)}=\frac{24}{35}\)

\(\frac{3}{2}.\left(\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{x.\left(x+2\right)}\right)=\frac{24}{35}\)

\(\frac{3}{2}.\left(\frac{1}{5}-\frac{1}{x+2}\right)=\frac{24}{35}\)

\(\frac{3}{10}-\frac{3}{2x+4}=\frac{24}{35}\)

\(\frac{3}{2x+4}=\frac{-27}{70}\)

tự làm nốt

\(\frac{3}{35}+\frac{3}{63}+\frac{3}{99}+....+\frac{3}{x\left(x+2\right)}=\frac{24}{35}\)

\(\Leftrightarrow3\left(\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+....+\frac{1}{x\left(x+2\right)}\right)=\frac{24}{25}\)

\(\Leftrightarrow3\left(\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}+...+\frac{1}{x\left(x+2\right)}\right)=\frac{24}{35}\)

\(\Leftrightarrow3\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+....+\frac{1}{x}-\frac{1}{x+2}\right)=\frac{24}{35}\)

\(\Leftrightarrow3\left(\frac{1}{5}-\frac{1}{x+2}\right)=\frac{24}{35}\)

\(\Leftrightarrow\frac{3}{5}-\frac{3}{x+2}=\frac{24}{35}\)

\(\Leftrightarrow\frac{3}{x+2}=\frac{3}{5}-\frac{24}{35}\)

\(\Leftrightarrow\frac{3}{x+2}=\frac{21-24}{35}\)

\(\Leftrightarrow\frac{3}{x+2}=\frac{3}{-35}\)

\(\Rightarrow x+2=-35\Leftrightarrow x=-35-2\Leftrightarrow x=-37\)

Vậy \(x=-37\)

a: =>31-x=60

=>x=-29

b: =>(x-140):35=280-270=10

=>x-140=350

=>x=490

c: =>(1900-2x):35=48

=>1900-2x=1680

=>2x=220

=>x=110

d: =>\(2^{2x-1}=2^9\cdot2=2^{11}\)

=>2x-1=11

=>x=6

e: =>(x+2)^5=4^5

=>x+2=4

=>x=2

f: =>3x-4=0 hoặc x-1=0

=>x=4/3 hoặc x=1

g: =>(2x-1)^2=49

=>2x-1=7 hoặc 2x-1=-7

=>x=-3 hoặc x=4

h: =>x(x+1)/2=78

=>x(x+1)=156

=>x=12

a)35+5*x=70

5*x=70-35

5*x=35

x=35/5

x=7

b) 35 - 5 * x = 20 

       - 5 * x = 20 - 35

       -5 * x = -15

            x = \(\frac{-15}{-5}\)

           x =   \(\frac{15}{5}\)

          x = 3