\(a,2Fe+3Cl_2\xrightarrow{t^o}2FeCl_3\\ FeCl_3+3NaOH\to Fe(OH)_3\downarrow+3NaCl\\ 2Fe(OH)_3\xrightarrow{t^o}Fe_2O_3+3H_2O\\ Fe_2O_3+3CO\xrightarrow{t^o}2Fe+3CO_2\\ Fe+H_2SO_4\to FeSO_4+H_2\\ FeSO_4+BaS\to BaSO_4\downarrow+FeS\\ FeS+2HCl\to FeCl_2+H_2\\ FeCl_2+2AgNO_3\to Fe(NO_3)_2+2AgCl\downarrow\)

\(b,2Al_2O_3\xrightarrow[criolit]{đpnc}4Al+3O_2\\ 2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2\\ Al_2(SO_4)_3+6NaOH\to 2Al(OH)_3\downarrow+3Na_2SO_4\\ Al(OH)_3+3HNO_3\to Al(NO_3)_3+3H_2O\\ 2Al(NO_3)_3+3Mg\to 3Mg(NO_3)_2+2Al\\ Al+NaOH+H_2O\to NaAlO_2+\dfrac{3}{2}H_2\)

dễ

a, Fe + HCl(dư) ---> FeCl3

FeCl3 + NaOH ---> Fe(OH)3 + naCl

Fe(OH)3 ---> (nhiệt phân)  Fe2O3 + h2O

fe2o3 + h2------> fe + h2o

b,   al2o3 + h2 -------> al + h2o 

Al+ h2SO4 -----------> AL2(SO4)3 + H2

AL2(SO4)3 + BACL2  ----------> alcl3 + baso4

alcl3 + naoh ------> nacl + al(oh)3

TỰ CÂN BẰNG NHA

a,1   2Fe+3Cl2->2FeCl3

   2    FeCl3+NaOH->Fe(OH)3+NaCl

    3   2Fe(OH)3->Fe2O3+3H2O(nhiệt phân)

     4   Fe2O3+3CO->2Fe+3CO2

b,1 2Al2O3->4Al+3O2( điện phân nóng chảy)

          2  2Al+3H2SO4(loãng)->Al2(SO4)3+3H2

          3  Al2(SO4)3+3BaCl2->2AlCl3+3BaSO4

          4  AlCl3+3NaOH->Al(OH)3+3NaCl 

tick nha

lớp 9 ạ

(1) \(4Al+3O_2\xrightarrow[]{t^\circ}2Al_2O_3\)

(2) \(Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\)

(3) \(AlCl_3+3AgNO_3\rightarrow Al\left(NO_3\right)_3+3AgCl\downarrow\)

(4) \(Al\left(NO_3\right)_3+3LiOH\rightarrow Al\left(OH\right)_3\downarrow+3LiNO_3\)

(5) \(2Al\left(OH\right)_3\xrightarrow[]{t^\circ}Al_2O_3+3H_2O\uparrow\)

(6) \(Al_2O_3+2NaOH\rightarrow2NaAlO_2+H_2O\)

4Al+3O₂----t^o--->2Al₂O₃

Al₂O₃ +3H₂SO₄----->Al₂(SO₄)₃+3H₂O

Al₂(SO₄)₃+3BaCl₂------>2AlCl₃+3BaSO₄

2AlCl₃+3Ca(OH)₂---->2Al(OH)₃+3CaCl₂

Al(OH)₃+3HNO₃---->Al(NO₃)₃+3H₂O

2Al(NO₃)₃+3Mg----->3Mg(NO₃)₂+2Al

2Al+3H₂SO₄------->Al₂(SO₄)₃+3H₂

Al₂(SO₄)₃+3Ca(OH)₂------>2Al(OH)₃+3CaSO₄

2Al(OH)₃-----t^o----->Al₂O₃+3H₂O

2Al₂O₃----\(\dfrac{t^o}{criolit}\)---->4Al+3O₂

2Al+2H₂O+2NaOH------>2NaAlO₂+3H₂

4Al+3O₂\(\underrightarrow{t^o}\) 2Al₂O₃

Al₂O₃+H₂SO₄ —> Al₂(SO₄)₃+3H₂O

Al₂(SO₄)₃+3BaCl₂–>3BaSO₄\(\downarrow\)+2AlCl₃

AlCl₃+3NaOH—>Al(OH)₃\(\downarrow\)+3NaCl

Al(OH)₃+HNO₃ —>Al(NO₃)₃+NO₂\(\uparrow\)+H₂O

2Al(NO₃)₃+3Mg—>3Mg(NO₃)₂+2Al\(\downarrow\)

2Al+3H₂SO₄–>Al₂(SO₄)₃+3H₂\(\uparrow\)

Al₂(SO₄)₃+6NaOH—>2Al(OH)₃+3Na₂SO₄

2Al(OH)₃\(\underrightarrow{t^o}\)Al₂O₃+3H₂O

2Al₂O₃\(\xrightarrow[criolit]{đien.phan.nong.chay}\)

4Al+3O₂

2Al+2NaOH+2H₂O—>2NaAlO₂+3H₂

\(\begin{array}{l} 4Al+3O_2\xrightarrow{t^o} 2Al_2O_3\\ Al_2O_3+3H_2SO_4\to Al_2(SO_4)_3+3H_2O\\ Al_2(SO_4)_3+3BaCl_2\to 3BaSO_4\downarrow+2AlCl_3\\ AlCl_3+3NaOH\to Al(OH)_3\downarrow+3NaCl\\ Al(OH)_3+3HNO_3\to Al(NO_3)_3+3H_2O\\ 2Al(NO_3)_3+3Mg\to 3Mg(NO_3)_2+2Al\\ 2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2\uparrow\\ Al_2(SO_4)_3+6NaOH\to 2Al(OH)_3\downarrow+3Na_2SO_4\\ 2Al(OH)_3\xrightarrow{t^o} Al_2O_3+3H_2O\\ 2Al_2O_3\xrightarrow{\text{đpnc, Criolit}} 4Al+3O_2\uparrow\\ 2Al+2NaOH+2H_2O\to 2NaAlO_2+3H_2\uparrow\end{array}\)

a, \(2Al+3O_2\underrightarrow{t^o}2Al_2O_3\)

\(Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\)

\(AlCl_3+3NaOH\rightarrow3NaCl+Al\left(OH\right)_3\)

\(2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\)

\(Al_2O_3\underrightarrow{đpnc}2Al+\dfrac{3}{2}O_2\)

\(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)

\(Al_2\left(SO_4\right)_3+3Mg\rightarrow3MgSO_4+2Al\)

b, \(2Fe+3Cl_2\underrightarrow{t^o}2FeCl_3\)

\(FeCl_3+3NaOH\rightarrow3NaCl+Fe\left(OH\right)_3\)

\(2Fe\left(OH\right)_3\underrightarrow{t^o}Fe_2O_3+3H_2O\)

\(Fe_2O_3+3H_2\underrightarrow{t^o}2Fe+3H_2O\)

\(Fe+2HCl\rightarrow FeCl_2+H_2\)

\(Mg+FeCl_2\rightarrow MgCl_2+Fe\)

\(Fe+H_2SO_4\rightarrow FeSO_4+H_2\)

a. 

\(\left(1\right)Fe+2HCl--->FeCl_2+H_2\)

\(\left(2\right)FeCl_2+2NaOH--->2NaCl+Fe\left(OH\right)_2\)

\(\left(3\right)4Fe\left(OH\right)_2+O_2+2H_2O\overset{t^o}{--->}4Fe\left(OH\right)_3\)

\(\left(4\right)2Fe\left(OH\right)_3\overset{t^o}{--->}Fe_2O_3+3H_2O\)

\(\left(5\right)Fe_2O_3+6HCl--->2FeCl_3+3H_2O\)

b.

\(\left(1\right)4Al+3O_2\overset{t^o}{--->}2Al_2O_3\)

\(\left(2\right)Al_2O_3+6HCl--->2AlCl_3+3H_2O\)

\(\left(3\right)AlCl_3+3NaOH--->Al\left(OH\right)_3+3NaCl\)

\(\left(4\right)2Al\left(OH\right)_3\overset{t^o}{--->}Al_2O_3+3H_2O\)

\(\left(5\right)Al_2O_3+3H_2SO_4--->Al_2\left(SO_4\right)_3+3H_2O\)