a) 16= 2^4

24=2^3 *3

ƯCLN (16, 24 ) = 2

Ưc = { 1,2 }

b) 180=2^2 *3^2 *5

234=2*3^2*13

ƯCLN = 2* 3^2= 18

ƯC= {1,2,3,6,9,18}

c)60=2^2*3*5

90= 2*3^2*5

135=3^3*5

Ucln = 2* 3*5 = 30

tk nhé

a: UCLN(16;42)=2

UC(16;42)={1;2}

b: UCLN(16;42;86)=2

UC(16;42;86)={1;2}

c: UCLN(25;75)=25

UC(25;75)={1;5;25}

d: UCLN(25;55;75)=5

UC(25;55;75)={1;5}

a: UCLN(16;42)=2

UC(16;42)={1;2}

b: UCLN(16;42;86)=2

UC(16;42;86)={1;2}

c: UCLN(25;75)=25

UC(25;75)={1;5;25}

d: UCLN(25;55;75)=5

UC(25;55;75)={1;5}

a) 16=2 mũ4

24=3.2 mũ 2

Suy ra ƯCLN (16,24) =2 mũ 2 =4

a) ƯCLN (16, 24) = 8, ƯC (16, 24) = {1; 2; 4; 8};

b) Ta có 180 = 22 .  32 . 5; 234 = 2 . 32 . 13;

ƯCLN (180, 234) = 2 .  32 = 18, ƯC (180, 234) = {1; 2; 3; 6; 9; 18};

c) Ta có 60 = 22 .  3 . 5; 90 = 2 . 32 . 5; 135 = 33 . 5. Do đó

ƯCLN (60, 90, 135) = 3 . 5 = 15; ƯC (60, 90, 135) = {1; 3; 5; 15}.

b)180 =3 mũ 2 nhân 2 mũ 2 nhân 5

234=13 nhân 3 mũ 2 nhân 2

suy ra ƯCLN(180,234)=3 mũ 2 nhân 2=18

Ta có 16 = 24 và 24 = 23.3 ⇒ ƯCLN (16, 24) = 23 = 8.

ƯC(16 ; 24) = Ư(8) = {1 ; 2 ; 4 ; 8}.

\(a,ƯCLN\left(540,168\right)=12\\ \RightarrowƯC\left(540,168\right)=Ư\left(12\right)=\left\{-12;-6;-4;-3;-2;-1;1;2;3;4;6;12\right\}\\ b,ƯCLN\left(735,350\right)=35\\ \RightarrowƯC\left(735,350\right)=Ư\left(35\right)=\left\{-35;-7;-5;-1;1;5;7;35\right\}\)

\(a.540=2^2.3^3.5\)

\(168=2^3.3.7\)

\(ƯCLN\left(540;168\right)=2^2.3=12\)

\(ƯC\left(540;168\right)=\left\{12;24;36;...\right\}\)

\(b.735=3.5.7^2\)

\(350=2.5^2.7\)

\(ƯCLN\left(735;350\right)=5.7=35\)

\(ƯC\left(735;350\right)=\left\{35;70;105;...\right\}\)

a) 72 và 60.     ===> Lưu ý: VD: 2^2 = 2 mũ 2

72 = 3^2.2^3

60 = 5.3.2^2

ƯCLN (72,60) = 3.2^2 = 12

ƯC = Ư(12) = {1,2,3,4,6,12}

b) 90; 180 và 315

90 = 5.3^2.2

180 = 5.3^2.2^2

315 = 5.3^2.7

ƯCLN  (90,180,315) = 5.3^2 = 125

ƯC = Ư(125) = { 1,125 }