8^20+4^20\4^25+64^5
\(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}\)
\(=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=2^{10}=1024\)
8^20+4^20/4^25+64^5
\(=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=2^{10}\)
B=8^20+4^20/4^25+64^5
\(B=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}}{2^{30}}=2^{10}=1024\)
8^20+4^20 phần 4^25+64^5 = ?
Tính M=8^20+4^20/4^25+64^5
\(M=\frac{8^{20}+4^{20}}{4^{25}+64^5}\)
\(=\frac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}\)
\(=\frac{2^{60}+2^{40}}{2^{50}+2^{30}}\)
\(=\frac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}\)
\(=2^{10}=1024\)
#)Giải :
\(M=\frac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}=\frac{2^{40}.2^{20}+2^{40}.1}{2^{30}.2^{20}+2^{30}.1}=\frac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=\frac{2^{40}}{2^{30}}=2^{10}=1024\)
Ta có 1 cách đơn giản và easy hơn
\(\frac{4^{20}\left(2^{20}+1\right)}{4^{15}+4^{10}+1}=1024\)
8^20 trừ 4^20 phần 4^25 trừ 64^5 bằng mấy?
\(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}\)
ta có : \(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}\)
\(=\dfrac{2^{40}}{2^{30}}=2^{10}=1024\)
\(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}\)
\(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{10}+2^{10}}{1+1}=1024\)
\(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}\)
\(=\dfrac{2^{40}.\left(2^{20}+1\right)}{2^{30}.\left(2^{20}+1\right)}=\dfrac{2^{40}}{2^{30}}=\dfrac{2^{30}+2^{10}}{2^{30}}=2^{10}=1024\)
M =\(\dfrac{8^{20^{ }}+4^{20}}{4^{25}+64^5}\)
\(M=\dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}.\left(2^{20}+1\right)}{2^{30}.\left(2^{20}+1\right)}=2^{10}=1024\)