a. \(\left(2x-3\right)\left(x+1\right)+\left(2x-3\right)\left(3x-7\right)=0\)

\(\Leftrightarrow\left(2x-3\right)\left(x+1+3x-7\right)=0\)

\(\Leftrightarrow\left(2x-3\right)\left(4x-6\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-3=0\\4x-6=0\end{matrix}\right.\)\(\Leftrightarrow x=\dfrac{3}{2}\)

b. \(\left(x-4\right)\left(3x-2\right)+x^2-16=0\)

\(\Leftrightarrow\left(x-4\right)\left(3x-2\right)+\left(x-4\right)\left(x+4\right)=0\)

\(\Leftrightarrow\left(x-4\right)\left(3x-2+x+4\right)=0\)

\(\Leftrightarrow\left(x-4\right)\left(4x+2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-4=0\\4x+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-\dfrac{1}{2}\end{matrix}\right.\)

(2x-3)(x+1)+(2x+3)(3x-7)=0

<=> (2x-3)(x+1)-(2x-3)(3x-7)=0

<=> (2x-3)(x+1-3x+7)=0

<=> (2x-3)(-2x+8)=0

<=> 2x-3=0 => x=3/2

Hoặc -2x+8=0 => x= 4

Vậy x thuộc{3/2;4}

(3x+2)(x-1)-3(x+1)(x-2)=4

​<=>3x²​-3x+2x-2+(-3x-3)(x-2)=4

​<=>3x²​-x-2-3x²+6x-3x+6=4

​<=>2x+6=4

​<=>2x=-2

​<=>x=-1

a: \(\left(x+\dfrac{1}{4}\right)+\left(3x-4\right)+2\left(x-3\right)=1\)

=>\(x+\dfrac{1}{4}+3x-4+2x-6=1\)

=>\(6x-\dfrac{39}{4}=1\)

=>\(6x=1+\dfrac{39}{4}=\dfrac{43}{4}\)

=>\(x=\dfrac{43}{4}:6=\dfrac{43}{24}\)

b: \(2\left(x-3\right)=3\left(x+2\right)-x+1\)

=>\(2x-6=3x+6-x+1\)

=>2x-6=2x+7

=>-6=7(vô lý)

c: \(x\left(x+3\right)+x\left(x-2\right)=2x\left(x-1\right)\)

=>\(x^2+3x+x^2-2x=2x^2-2x\)

=>3x-2x=-2x

=>3x=0

=>x=0

d: \(\left(x-1\right)\cdot3x-2\left(x+2\right)-2x=x\left(x-1\right)\)

=>\(3x^2-3x-2x-4-2x=x^2-x\)

=>\(3x^2-7x-4-x^2+x=0\)

=>\(2x^2-6x-4=0\)

=>\(x^2-3x-2=0\)

=>\(x=\dfrac{3\pm\sqrt{17}}{2}\)

Đăng từng câu đio

,(8x-3).(3x+2)-(4x+7).(x+4)=(2x+1).(5x-1)-33 đúng không bạn

Tuyet Anh Nguyen

1.a)(3x-2)(4x+5)=0 
12x^2+7x-10=0>>x1=2/3,x2=-5/4 
b)4x^3+2x^2+4x+2=0>>x=-1 
c)0,23x^2-4,21x-13,8=0>>x1=21,14,x2=-2,8... 
d)10x^3-13x^2-178x-35=0>>x1=5,x2=-1/5 
b2/a)2x^3+5x^2-3x=0>>x1=1/2,x2=-3 
b)(3x-1)(x^2-7x+12)=0>>x1=1/3,x2=4,x3=... 
b3/ 
a)x^2+x-2=0>>x1=1,x2=-2 
b)x1=-1,x2=-6 
b4/a)0,5x^2-1,5x-1,5x^2+x+4,5x-3=0>>-x... 
b)3x/7-1=3x/7-x>>x=1 
c)2x^2-13x+15=0>>x1=5,x2=3/2

P/s: Tham khảo nha

a)0

b)-1

c)-2,8......

k cho tui

\(x-\frac{3}{2}=3x+\frac{1}{4}\)

\(x-3x=\frac{1}{4}+\frac{3}{2}\)

\(-2x=\frac{7}{4}\)

\(x=\frac{7}{4}:\left(-2\right)\)

\(x=-\frac{7}{8}\)

Tìm x : 

\(x-\frac{3}{2}=3x+\frac{1}{4}\)

\(\Leftrightarrow x-3x=\frac{1}{4}+\frac{3}{2}\)

\(\Leftrightarrow1x-3x=\frac{1}{4}+\frac{6}{4}\)

\(\Leftrightarrow-2x=\frac{7}{4}\)

\(\Leftrightarrow x=\frac{7}{4}:\left(-2\right)\)

\(\Leftrightarrow x=\frac{7}{4}.\frac{-1}{2}\)

\(\Leftrightarrow x=-\frac{7}{8}\)

nhận xét 3 >0

=> /3x+1/= 3x+1

/4-x/= 4-x

ta có 3x+1 + 4 -x = 3

=> 2x + 5 = 3

=> 2x = -2

=> x= -1

cam on ban Nguyen Quang Tung

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