\(3^{2x}+3^{2x+1}=324\)

\(\Rightarrow3^{2x}+3^{2x}.3=324\)

\(\Rightarrow3^{2x}\left(1+3\right)=324\)

\(\Rightarrow3^{2x}.4=324\)

\(\Rightarrow3^{2x}=324:4=81=3^4\)

\(\Rightarrow2x=4\)

\(\Rightarrow x=4:2=2\)

3^2x + 3^{2x + 1} = 324

=> 3^2x + 3^2x.3 = 324

=> 3^2x.(1 + 3) = 324

=> 3^2x.4 = 324

=> 3^2x = 324 : 4

=> 3^2x = 81

=> 3^2x = 3⁴

=> 2x = 4

=> x = 2

3^2x+3^2x+1=324

<=>3^2x+3^2x.3=324

<=>3^2x.(3+1)=324

<=>3^2x.4=324

<=>3^2x=81

<=>3^2x=3⁴

<=>2x=4

<=>x=2

vậy x=2

k mik nhé

hok tốt

9^x+1-5.3^2x=324

=>9^x.9-(3²)^x.5=324

=>9^x.9-9^x.5=324

=>9^x(9-5)=324

=>9^x.4=324

=>9^x=324:4

=>9^x=81

=>9^x=9²

=>x=2

vậy x=2

\(a,\Rightarrow\left(4x-1\right)^2=25=5^2=\left(-5\right)^2\\ \Rightarrow\left[{}\begin{matrix}4x-1=5\\4x-1=-5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-1\end{matrix}\right.\\ b,\Rightarrow2^x\left(1+2^3\right)=144\\ \Rightarrow2^x=144:9=16=2^4\Rightarrow x=4\\ c,\Rightarrow3^{2x+3}=3^{2\left(x+3\right)}\\ \Rightarrow2x+3=2x+6\Rightarrow0x=3\left(vô.lí\right)\\ \Rightarrow x\in\varnothing\)

a) 2x = 16 <=>x=8

b) 3x+1 = 9x <=>9x-3x=1

<=>6x=1 <=>x=1/6

c) 23x+2 = 4x+5 <=>23x-4x=5-2

<=>19x=3 <=>x=3/19

d) 32x-1 = 243 <=>32x=244

<=>x=61/8

a/ 2x=16

x=8

b/ 3x+1=9x

3x-9x=-1

-6x=-1

x=1/6

c/ 23x+2=4x

23x-4x=-2

19x=-2

x=-2/19

d/ 32x-1=243

32x=244

x=61/8

Thiếu đề không bạn? Tui nghĩ đề vậy nè:

\(9^{x+1}-5.3^{2x}=324\)

\(\Leftrightarrow9.9^x-5.9^x=324\)

\(\Leftrightarrow4.9^x=324\)

\(\Leftrightarrow9^x=81\)

\(\Leftrightarrow9^x=9^2\)

\(\Leftrightarrow x=2\)

Vậy .........

đủ đề mà

uk đè thiếu không bạn

a: Ta có: \(2^{x-1}=32\)

\(\Leftrightarrow x-1=5\)

hay x=6

b: Ta có: \(3^{2x+1}=81\)

\(\Leftrightarrow2x+1=4\)

\(\Leftrightarrow2x=3\)

hay \(x=\dfrac{3}{2}\)

c: Ta có: \(2^x-26=6\)

\(\Leftrightarrow2^x=32\)

hay x=5

d: Ta có: \(27\cdot3^x=243\)

\(\Leftrightarrow3^x=9\)

hay x=2

a) 5^{x + 1} - 2.5^x = 75

<=> 5^x.5 - 2.5^x = 75

<=> 5^x.3 = 75

<=> 5^x = 25

<=> 5^x = 5²

<=> x = 2

Vậy x = 2

b) 9^{x + 1} -  5.3^2x = 324

<=> (3²)^{x + 1} - 5.3^2x = 324

<=> 3^{2x + 2} - 5.3^2x = 324

<=> 3^2x.3² - 5.3^2x = 324

<=> 3^2x . 4 = 324

<=> 3^2x = 81

<=> 3^2x = 3⁴

<=> 2x = 4

<=> x = 2

Vậy x = 2

UIUYI

\(9^{x+1}-5.3^{2x}=324=>9^x.9-5.\left(3^2\right)^x=324=>\left(3^2\right)^x.9-5.\left(3^2\right)^x=324\)

\(=>3^{2x}.\left(9-5\right)=324=>3^{2x}=\frac{324}{4}=81=3^4=>2x=4=>x=2\)

vậy x=2

tick nhé