cứu

a: =>(2x-1)^5=2^5

=>2x-1=2

=>2x=3

=>x=3/2

b: =>3^x=243*27=3^5*3^3=3^8

=>x=8

\(a,\left(2x-1\right)^5=32\\ \Leftrightarrow2x-1=2\\ \Leftrightarrow2x=3\\ \Leftrightarrow x=\dfrac{3}{2}\\ b,\dfrac{1}{27}\cdot3^x=243\\ \Leftrightarrow3^x=6561\\ \Leftrightarrow3^x=3^8\\ \Leftrightarrow x=8\)

a) \(2^x\cdot4=16\)

\(\Rightarrow2^x=16:4\)

\(\Rightarrow2^x=4\)

\(\Rightarrow2^x=2^2\)

\(\Rightarrow x=2\)

b) \(3^x\cdot3=243\)

\(\Rightarrow3^x=243:3\)

\(\Rightarrow3^x=81\)

\(\Rightarrow3^x=3^4\)

\(\Rightarrow x=4\)

- 3⁵= - 243 => 3x-2= - 3 =>  x= cậu tự tính nha!

ta có : -243 = (-3)^5 

=> 3x -2 =-3

<=>3x =-3 +2 

<=>3x = -1 ( âm một)

<=>x = -1÷3 

=> x=-1/3

Vậy x=-1/3

ta có : -243 = (-3)^5 

=> 3x -2 =-3

<=>3x =-3 +2 

<=>3x = -1 ( âm một)

<=>x = -1÷3 

=> x=-1/3

Vậy x=-1/3

(3x - 2)⁵ = -243

=> (3x - 2)⁵ = (-3)⁵

=> 3x - 2 = -3

=> 3x = -1

=> x = -1/3

a)2x.2x+1=128

\(4x^2+1=128\)

\(\Rightarrow4x^2=127\)

\(\Rightarrow x^2=127\div4\)

\(\Rightarrow x^2=3.175\)

mà \(x\in N\) hay\(x^2\in N\)

\(\Rightarrow\)Không có x

b)  3x+1.3x=243

\(\Rightarrow\)3x+3x=243

\(\Rightarrow\)6x=243

\(\Rightarrow\)x=40,5

Mà \(x\in N\)

\(\Rightarrow\)Không có x

\(\left(3x-2\right)^5=-243\)

\(\Leftrightarrow\left(3x-2\right)^5=-3^5\)

\(\Leftrightarrow3x-2=-3\)

\(\Leftrightarrow3x=-1\)

\(\Leftrightarrow x=-\frac{1}{3}\)

\(\left(3x-2\right)^5=-243\)

\(\Leftrightarrow\left(3x-2\right)^2=\left(-3\right)^5\)

\(\Rightarrow3x-2=-3\)

\(\Rightarrow3x=-3+2\)

\(\Rightarrow3x=-1\)

\(\Rightarrow x=-\frac{1}{3}\)

\(\left(3x-2\right)^5=-243\)
\(\Leftrightarrow\left(3x-2\right)^5=-3^5\)
\(\Leftrightarrow3x-2=-3\)
\(\Leftrightarrow3x=-1\)
\(\Leftrightarrow x=\frac{-1}{3}\)
\(\text{Vậy }x=\frac{-1}{3}\)

a,  1170 : x - 13 = 339 . 3 . 10 2

1170:(x - 13) = 339 - 3.100

1170:(x - 13) = 39

x - 13 = 1170:39 = 30 

x = 30+13 = 43

b,  3 x - 9 + 15 = 12 + 243 : 3 2

3(x - 9) + 15 = 12+243:9

3(x - 9)+15 = 12+27

3(x - 9)+15 = 39

3(x - 9) = 24

x  - 9 = 8

x = 17

(2x - 3)²=16

(2x-3)²=4²

=>2x-3=4 hoặc 2x-3=-4

=>2x=7 hoặc 2x=-1

=>x=7/2 hoặc x=-1/2

( 3x - 2 )⁵ = -24³ đề đúng phải là ( 3x - 2 )⁵=-243

`@` `\text {Ans}`

`\downarrow`

`2^x = 16`

`=> 2^x = 2^4`

`=> x = 4`

Vậy, `x = 4.`

____

`2^x*16 = 1024`

`=> 2^x =`\(2^{10}\div2^4\)

`=> 2^x = 2^6`

`=> x = 6`

Vậy, `x = 6`

______

`2^x - 26 = 6`

`=> 2^x = 6 + 26`

`=> 2^x = 32`

`=> 2^x = 2^5`

`=> x = 5`

Vậy, `x = 5`

`3^x*3 = 243`

`=> 3^x * 3 = 3^5`

`=> 3^x = 3^5 \div 3`

`=> 3^x = 3^4`

`=> x = 4`

Vậy, `x = 4.`

a: =>1/3x-2/5x=5

=>-1/15x=5

=>x=-75
b: =>4x=4

=>x=1

c: =>6*3^x-5*3^x=243

=>3^x=243

=>x=5