thấy sai sai bạn ạ

\(x^2+2x-10=0\)

\(\Leftrightarrow x^2+2x+1-9=0\)

\(\Leftrightarrow\left(x+1\right)^2-9=0\\\)

\(\Leftrightarrow\left(x+1\right)^2=9\)

\(\Leftrightarrow\left(x+1\right)^2=\pm\sqrt{9}\)

\(\Leftrightarrow\left(x+1\right)^2=\left(\pm3\right)^2\)

\(\Leftrightarrow\left[{}\begin{matrix}x+1=3\\x+1=-3\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3-1\\x=-3-1\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-4\end{matrix}\right.\)

Vậy S={2;-4}

\(x^2\) + 2\(x\) - 10 = 0

\(x^2\) + 2\(x\) + 1 - 11 = 0

(\(x^2\) + 2\(x\) + 1) - 11 = 0

(\(x\) + 1)² - 11 = 0

(\(x\) + 1)² = 11

\(\left[{}\begin{matrix}x+1=\sqrt{11}\\x+1=-\sqrt{11}\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=\sqrt{11}-1\\x=-\sqrt{11}-1\end{matrix}\right.\)

\(x^3-x=0\Rightarrow x\left(x^2-1\right)=0\)

TH1: \(x=0\)

TH2: \(x^2-1=0\Rightarrow x^2=1\Rightarrow x=\sqrt{1}\)hoặc \(x=-\sqrt{1}\)

x + 1 : 0,75 = 1,4 : 0,25

<=> \(x+\dfrac{4}{3}=5,6\)

<=> \(x=\dfrac{64}{15}\)

\(x.2-5.x=0\)

\(\Rightarrow-3x=0\)

\(\Rightarrow x=0\)

Vậy \(x=0\)

\(2x-5x=0\)

\(=>2x=5x\)

\(=>x=0\)

Trả lời đúng , mình sẽ cho 5 vote

\(\Rightarrow x-\left(-x+x+3\right)-\left(x+3-x+2\right)=0\\ \Rightarrow x-3-5=0\\ \Rightarrow x=8\)

Sai rồi bạn ơi, bằng -2 mới đúng,bn thử lại coi

\(\frac{x+2}{x-5}< 0\) <=> x+2 và x-5 trái dấu

Mà x+2 > x-5

Nên x+2 > 0 và x-5 < 0

=>x > -2 và x < 5

Vậy -2 <x <5

x.(x-5)+x-5=o

=> x.(x-5)+(x-5)=0

=>(x-5)(x+1)=0

=> x-5=0    =>x=5

     x+1=0        x=-1

x ( x - 5 ) + x -  5 = 0

x ( x - 5 ) + ( x - 5 ) = 0

(x - 5 ) ( x + 1 ) = 0

\(\Rightarrow\orbr{\begin{cases}x-5=0\\x+1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=-1\end{cases}}}\)

Vậy...

\(x.\left(x-5\right)+x-5=0\)

\(\Leftrightarrow x.\left(x-5\right)+\left(x-5\right)=0\)

\(\Leftrightarrow\left(x-5\right).\left(x+1\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-5=0\\x+1=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=5\\x=-1\end{cases}}\)

\(...\Rightarrow x+x+\dfrac{x}{43}+\dfrac{x}{8}=14+148+\dfrac{10}{30}+\dfrac{5}{95}\)

\(\Rightarrow\left(1+1+\dfrac{1}{43}+\dfrac{1}{8}\right)x=162+\dfrac{1}{3}+\dfrac{1}{19}\)

\(\Rightarrow\left(\dfrac{2.43.8}{43.8}+\dfrac{1.8}{43.8}+\dfrac{1.43}{43.8}\right)x=\dfrac{162.3.19}{3.19}+\dfrac{1.19}{3.19}+\dfrac{1.3}{19.3}\)

\(\Rightarrow\left(\dfrac{688}{344}+\dfrac{8}{344}+\dfrac{43}{344}\right)x=\dfrac{9234}{57}+\dfrac{19}{57}+\dfrac{3}{57}\)

\(\Rightarrow\dfrac{739}{344}x=\dfrac{9256}{57}\)

\(\Rightarrow x=\dfrac{9256}{57}:\dfrac{739}{344}=\dfrac{9256}{57}.\dfrac{344}{739}=\dfrac{\text{3184064}}{\text{42123}}\)