tìm x biết
3x =81
Tìm x biết:
(3x+4)^2-(3x-1)×(3x+1)=49
X^2-81=0
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câu sau : x^2 -9^2 = 0<=> (x-9)^2=0 <=>x-9=0 <=> x=9
X^2-81=0
=>X^2-9^2=0
=>(X-9)^2=0
=>X-9=0
=>X=9
Tìm x biết x + 2x + 3x + ⋯ + 10x = -165.
x+2x+3x+...+10x=-165
x.(1+2+3+..+10)=-165
x.55=-165
x=-3
k
x+ 2x+ 3x+ ... + 10x= -165
x. (1+ 2+ 3+ ... + 10)= -165
x. 55= -165
x= -165: 55
=> x= -3
Bạn xem có đúng không?
x + 2x + 3x + ... + 10x = -165
55x = -165
suy ra x = -165 : 55 = -3
Tìm x biết x + 2x + 3x + ⋯ + 10x = -165.
x.(1+2+3+...+10) = -165
x. (11.10 : 2) = -165
x. 55 = -165
x= -165:55=-3
Tìm x, biết:
( 12x-5 )( 4x-1 ) + ( 3x-7 )( 1-16x ) = 81
\(\left(12x-5\right)\left(4x-1\right)+\left(3x-7\right)\left(1-16x\right)=81\)
\(\text{⇔}48x^2-32x+5-48x^2-7+115x=81\)
\(\text{⇔}83x-2=81\)
\(\text{⇔}83x=83\)
\(\text{⇔}x=1\)
Vậy: x=1
Ta có: \(\left(12x-5\right)\left(4x-1\right)+\left(3x-7\right)\left(1-16x\right)=81\)
\(\Leftrightarrow48x^2-12x-20x+5+3x-48x^2-7+112x=81\)
\(\Leftrightarrow83x=83\)
hay x=1
Tìm x, biết
(12x-5) (4x-1)+(3x-7) (1-16x)=81
\(\left(12x-5\right)\left(4x-1\right)+\left(3x-7\right)\left(1-16x\right)=81\)
\(\Leftrightarrow48x^2-32x+5+48x^2+115x-7=81\)
\(\Leftrightarrow83x=83\)
\(\Leftrightarrow x=1\)
\(\Leftrightarrow48x^2-12x-20x+5+3x-48x^2-7+112x=81\\ \Leftrightarrow83x=83\Leftrightarrow x=1\)
\(\left(12x-5\right)\left(4x-1\right)+\left(3x-7\right)\left(1-16x\right)=81\)
\(48x^2-12x-20x+5+3x-48x^2-7+112x=81\)
\(83x-2=81\)
\(83x=83\)
\(x=1\)
Tìm x, biết:
(12x – 5)(4x – 1) + (3x – 7)(1 – 16x) = 81
Rút gọn vế trái:
VT = (12x – 5)(4x – 1) + (3x – 7)(1 – 16x)
= 12x.(4x – 1) + (–5).(4x – 1) + 3x.(1 – 16x) + (–7).(1 – 16x)
= 12x.4x+ 12x.(–1) + (–5).4x + (–5).(–1) + 3x.1 + 3x.(–16x) + (–7).1 + (–7).(–16x)
= 48x2 – 12x – 20x + 5 + 3x – 48x2 – 7 + 112x
= (48x2 – 48x2) + (– 12x – 20x + 3x + 112x) + (5 – 7)
= 83x – 2
Vậy ta có:
83x – 2 = 81
83x = 81 + 2
83x = 83
x = 83 : 83
x = 1.
Tìm x biết (12x-5). (4x-1)+(3x-7. (1-16x)=81
(12x - 5)(4x - 1) + (3x - 7)(1 - 16x) = 81
<=> 48x2 - 12x - 20x + 5 + 3x - 48x2 - 7 + 112x = 81
<=> 48x2 - 48x2 - 12x - 20x + 3x + 112x = 81 - 5 + 7
<=> 83x = 83
<=> x = 1
Tìm x, biết: (12x − 5)(4x − 1) + (3x − 7)(1 − 16x) = 81.
\(\Rightarrow48x^2-32x+5-48x^2+115x-7=81\)
\(\Rightarrow83x=83\Rightarrow x=1\)
Tìm x, biết 3 x = 1/81.
A. x = 4 B. x = -4
C. x = 3 D. x = -3