2x = 27
tìm x
a) x: 27=3,6
b)\(\dfrac{2x+1}{-27}\) =\(\dfrac{-3}{2x+1}\)
a/\(x:27=3,6\)
\(\Rightarrow x=97,2\)
b/\(\dfrac{2x+1}{-27}=\dfrac{-3}{2x+1}\)
\(\Rightarrow\left(2x+1\right)^2=81\)
\(\Rightarrow\left[{}\begin{matrix}2x+1=9\\2x+1=-9\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=8\\2x=-10\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=4\\x=-5\end{matrix}\right.\)
Vậy \(x\in\left\{4;-5\right\}\)
a,x:27=3,6
x=3,6:27
x\(\approx\)0,13
\(\Rightarrow\)x=0,1(3)
BÀI 1 TÌM STN X BIẾT :
a ) 3*(2x-5)+125=134
b) (2x+5)+(2x+3)+(2x+1)=27
c) 28*x+72:x=24*99+24
d) 27*(x-27)-27=0
mng giúp vs mik tik luôn vs cả ai muốn mk tik thì vào tcn của mik r tl mk tik cho nhé
a) \(3\left(2x-5\right)+125=134\)
\(\Leftrightarrow3\left(2x-5\right)=9\)
\(\Leftrightarrow2x-5=3\)
\(\Leftrightarrow2x=8\Leftrightarrow x=4\)
b) \(\left(2x+5\right)+\left(2x+3\right)+\left(2x+1\right)=27\)
\(\Leftrightarrow6x+9=27\)
\(\Leftrightarrow6x=18\Leftrightarrow x=3\)
d) \(27\left(x-27\right)-27=0\)
\(\Leftrightarrow27\left(x-27\right)=27\)
\(\Leftrightarrow x-27=1\Leftrightarrow x=28\)
3.(x+5)-2x=27
3.x+3.5-2x=27
3x+15-2x=27
x.(3-2)+15=27
x. 1 +15=27
x +15=27
x =27-15
x =12
tìm x trong các tỉ lệ thức sau:
a,x:27=-2 : 3,6
b,2x+1/-27= -3/2x+1
Lời giải:
a.
$x:27=-2:3,6=\frac{-5}{9}$
$x=27.\frac{-5}{9}=-15$
b.
$\frac{2x+1}{-27}=\frac{-3}{2x+1}$
$\Rightarrow (2x+1)^2=(-27)(-3)=81=9^2=(-9)^2$
$\Rightarrow 2x+1=9$ hoặc $2x+1=-9$
$\Rightarrow x=4$ hoặc $x=-5$
\(27\sqrt{5+2x}+27\sqrt{4-2x}\ge\left(4x+1\right)^2\)
ĐKXĐ: \(-\frac{5}{2}\le x\le2\)
Ta có \(VT=27\left(\sqrt{5+2x}+\sqrt{4-2x}\right)\ge27\sqrt{5+2x+4-2x}=81\)
Xét vế phải với hàm \(f\left(x\right)=\left(4x+1\right)^2\) trên \(\left[-\frac{5}{2};2\right]\)
\(f\left(-\frac{1}{4}\right)=0\) ; \(f\left(-\frac{5}{2}\right)=81\) ; \(f\left(2\right)=81\)
\(\Rightarrow0\le f\left(x\right)\le81\Rightarrow VP\le81\)
\(\Rightarrow VT\ge VP\) \(\forall x\in\left[-\frac{5}{2};2\right]\)
Vậy nghiệm của BPT là \(-\frac{5}{2}\le x\le2\)
( 2x - 27 ) + 17 = x - 27
( 2x - 27 ) + 17 = x - 27
2x - 27 + 17 = x - 27
2x - x = 27 - 27 + 17
x = 17
=> 2x-27+17 = x-27
=> 2x-10 = x-27
=> 2x-10+27 = x
=> 2x+17 = x
=> x-2x = 17
=> -x = 17
=> x=-17
Vậy x=-17
Tk mk nha
( 2x - 27 ) + 17 = x - 27
2x - 27 + 17 = x - 17
2x - x = -17 - 17 + 27
x = -34 + 27
x = -7
\(\dfrac{\sqrt{27+x^2+x}}{2+\sqrt{5-\left(x^2+x\right)}}=\dfrac{\sqrt{27+2x}}{2+\sqrt{5-2x}}\)
Giải PT:
\(\dfrac{\sqrt{27+x^2+x}}{2+\sqrt{5-\left(x^2+x\right)}}=\dfrac{\sqrt{27+2x}}{2+\sqrt{5-2x}}\)
(2x+27):(2X+1)
tim x thoa man 9-(27-2x)=-/-27/-15
9-(27-2x)=-|-27|-15
9-(27-2x)=-42
27-2x = 51
2x = 27 - 51
2x = -24
x = -24 : 2
x = -12
a:35-x=25-(-13) b:27+(35-27)=(x+758)-758
c:x(39+x)=2x-27 d:2x-1257=(16-25)-1257
cần gấp