=6x^2 - 4x - 9x +6

=(6x^2 -4x) - (9x-6)

=2x(3x -2) - 3(3x-2)

=(3x-2) (2x - 3)

\(=6x^2+3x+10x+5=3x\left(2x+1\right)+5\left(2x+1\right)=\left(3x+5\right)\left(2x+1\right)\)

6x2+3x+10x+5=3x(2x+1)+5(2x+1)=(3x+5)(2x+1)

a) Ta có : 6x² - 13x + 6 = 6x² - 9x - 4x + 6 = 3x(2x - 3) - 2(2x - 3) = (3x - 2)(2x - 3)

b) Ta có: 6x² + 7x - 3 = 6x² + 9x - 2x - 3 = 3x(2x + 3) - (2x + 3) = (3x - 1)(2x + 3)

\(a,6x^2-13x+6\)

\(=6x^2-9x-4x+6\)

\(=3x\cdot\left(2x-3\right)-x\cdot\left(2x-3\right)\)

\(=\left(2x-3\right)\cdot\left(3x-x\right)\)

\(=\left(2x-3\right)\cdot2x\)

\(b,6x^2+7x-3\)

\(=6x^2-2x+9x-3\)

\(=2x\cdot\left(3x-1\right)+3\cdot\left(3x-1\right)\)

\(=\left(3x-1\right)\cdot\left(2x+3\right)\)

\(a,6x^2-13x+6=6x^2-9x-4x+6\)

\(=3x\left(2x-3\right)-2\left(2x-3\right)=\left(2x-3\right)\left(3x-2\right)\)

\(b,6x^2+7x-3=6x^2-2x+9x-3\)

\(=2x\left(3x-1\right)+3\left(3x-1\right)=\left(3x-1\right)\left(2x+3\right)\)

Ta có: \(6x^4-13x^2+6\)

\(=6x^4-9x^2-4x^2+6\)

\(=3x^2\left(2x^2-3\right)-2\left(2x^2-3\right)\)

\(=\left(2x^2-3\right)\left(3x^2-2\right)\)

\(6x^4-13x^2+6=6x^4-4x^2-9x^2+6\)

                         \(=2x^2\left(3x^2-2\right)-3\left(3x^2-2\right)\)

                         \(=\left(2x^2-3\right)\left(3x^2-2\right)\)

Ta có:\(6x^4-13x^2+6\)

\(=6x^4-9x^2-4x^2+6\)

\(=3x^2\left(2x^2-3\right)-2\left(2x^2-3\right)\)

\(=\left(2x^2-3\right)\left(3x^2-2\right)\)

         \(6x^2+13x-15\)

\(=6x^2+18x-5x-15\)

\(=6x.\left(x+3\right)-5.\left(x+3\right)\)

\(=\left(x+3\right).\left(6x-5\right)\)

\(6x^2+13x-15\)

\(=6x^2+18x-5x-15\)

\(=6x\left(x+3\right)-5\left(x+3\right)\)

\(=\left(x+3\right)\left(6x-5\right)\)

\(6x^2+13x-15\)

\(\Rightarrow6x^2+18x-5x-15x\)

\(\Rightarrow6x\times\left(x+3\right)-5\times\left(x+3\right)\)

\(\Rightarrow\left(x+3\right)\times\left(6x-5\right)\)

Code : Breacker

\(P\left(x\right)=6x^3+13x^2+4x-3\)

\(=\left(6x^3+6x^2\right)+\left(7x^2+7x\right)-\left(3x-3\right)\)

\(=6x^2\left(x+1\right)+7x\left(x+1\right)-3\left(x+1\right)\)

\(=\left(6x^2+7x-3\right)\left(x+1\right)\)

\(=\left[\left(6x^2-2x\right)+\left(9x-3\right)\right]\left(x+1\right)\)

\(=\left[2x\left(3x-1\right)+3\left(3x-1\right)\right]\left(x+1\right)\)

\(=\left(3x-1\right)\left(2x+3\right)\left(x+1\right)\)

THAM KHẢO NHÉ BẠN, MÌNH KO VT ĐC TRONG NÀY NÊN PHẢI RA WORD VÍT R COPY VÀO Á:

$7x^2-13x+6=0\iff 7x^2-7x-6x+6=0$

$\iff 7x\left(x-1\right)-6\left(x-1\right)=0\iff \left(7x-6\right)\left(x-1\right)=0$

x=1;x=67

`#040911`

`7x^2 - 13x + 6`

`= 7x^2 - 7x - 6x + 6`

`= (7x^2 - 7x) - (6x - 6)`

`= 7x(x - 1) - 6(x - 1)`

`= (7x - 6)(x - 1)`

\(7x^2-13x+6=7\left(x-1\right)\left(x-\dfrac{6}{7}\right)\)

\(x^3+6x^2-13x-42\)

\(x^3+6x^2-13x-42\)

\(=\left(x+7\right)\left(x-3\right)\left(x+2\right)\)

b, \(2x^3-x^2+3x+6\)

\(=2x^3+2x^2-3x^2-3x+6x+6\)

\(=2x^2\left(x+1\right)-3x\left(x+1\right)+6\left(x+1\right)\)

\(=\left(x+1\right)\left(2x^2-3x+6\right)\)

\(x^3+6x^2-13x-42\)

\(=x^3+7x^2-x^2-7x-6x-42\)

\(=x^2\left(x+7\right)-x\left(x+7\right)-6\left(x+7\right)\)

\(=\left(x+7\right)\left(x^2-x-6\right)\)

\(=\left(x+7\right)\left(x-3\right)\left(x+2\right)\)

e) \(=x^2\left(x+1\right)-2x\left(x+1\right)+3\left(x+1\right)=\left(x+1\right)\left(x^2-2x+3\right)\)

g) \(=x^2\left(3x-1\right)-x\left(3x-1\right)+4\left(3x-1\right)=\left(3x-1\right)\left(x^2-x+4\right)\)

h) \(=3x^2\left(2x+1\right)-x\left(2x+1\right)+\left(2x+1\right)=\left(2x+1\right)\left(3x^2-x+1\right)\)

i) \(=2x^2\left(2x+1\right)+2x\left(2x+1\right)+\left(2x+1\right)=\left(2x+1\right)\left(2x^2+2x+1\right)\)