\(\dfrac{8}{9}+\left(\dfrac{-7}{9}\right)+\left(\dfrac{-8}{13}\right)+\dfrac{7}{29}+\dfrac{2019}{2020}\)

\(\dfrac{8}{9}+\dfrac{-7}{29}+\dfrac{-8}{13}+\dfrac{7}{29}+\dfrac{2019}{2020}\)

\(=\dfrac{8}{9}-\dfrac{8}{13}+\dfrac{2019}{2020}\)

\(=\dfrac{32}{117}+\dfrac{2019}{2020}=\dfrac{300863}{236340}\)

a: \(A=21\cdot100-11\cdot100+90\cdot100+100\cdot125\cdot16\)

\(=100\left(21-11+90\right)+100\cdot2000\)

\(=100\left(10+90+2000\right)=2100\cdot100=210000\)

b: \(=\dfrac{5\cdot2^{30}\cdot3^{18}-2^{29}\cdot3^{20}}{5\cdot2^{28}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}}\)

\(=\dfrac{2^{29}\cdot3^{18}\left(5\cdot2-3^2\right)}{2^{28}\cdot3^{18}\left(5\cdot3-7\cdot2\right)}=2\)

mình bày cho

bạn lên mạng là biết

a) Ta có: \(14-\left(5-8\right)^3+\left(-3\right)\cdot5\)

\(=14+27-15=26\)

b) Ta có: \(-7\cdot15+7\cdot\left(-35\right)+\left(-1\right)^{2019}\)

\(=-7\left(15+35\right)-1=-350-1=-351\)

c) Ta có: \(-18\cdot32+\left(-18\right)\cdot45+77\cdot\left(-32\right)-77\cdot50\)

\(=-18\left(32+45\right)+77\left(-32-50\right)\)

\(=-18\cdot77+77\cdot\left(-82\right)=77\left(-18-82\right)=77\cdot\left(-100\right)=-7700\)

d) Ta có: \(104-4\cdot\left[-5\cdot8+\left(7-10\right)^3\right]\)

\(=104-4\left[-40-27\right]=104-4\cdot\left(-67\right)=104+268=372\)

\(\left(19\frac{5}{8}:\frac{7}{12}-13\frac{1}{4}:\frac{7}{12}\right).\frac{4}{5}\)

\(=\left(\frac{157}{8}:\frac{7}{12}-\frac{53}{4}:\frac{7}{12}\right).\frac{4}{5}\)

\(=\left[\left(\frac{157}{8}-\frac{53}{4}\right):\frac{7}{12}\right].\frac{4}{5}\)

\(=\left[\frac{51}{8}:\frac{7}{12}\right].\frac{4}{5}\)

\(=\frac{153}{14}.\frac{4}{5}\)

\(=\frac{306}{35}\)

\(\left(\frac{-2}{5}+\frac{3}{7}\right)-\left(\frac{4}{9}+\frac{12}{20}-\frac{13}{35}\right)+\frac{7}{35}\)

\(=\frac{1}{35}-\frac{212}{315}+\frac{7}{35}\)

\(=\frac{1}{35}+\frac{-212}{315}+\frac{7}{35}\)

\(=\frac{9}{315}+\frac{-212}{315}+\frac{63}{315}\)

\(=\frac{-140}{315}=\frac{-4}{9}\)

\(\left(4\frac{5}{57}-3\frac{4}{51}+8\frac{13}{29}\right)-\left(3\frac{5}{57}-6\frac{16}{29}\right)\)

\(=\left(\frac{233}{57}-\frac{157}{51}+\frac{245}{29}\right)-\left(\frac{176}{57}-\frac{190}{29}\right)\)

\(=\frac{1941}{323}-\frac{-5726}{1653}\)

\(=\frac{14011}{1479}\)

a) 29^57 < 29^75

b) 1011^22 < 1101^22

c) ( 2021 + 2018 )^2019 < ( 2020 + 2019 )^2020

d) 2^5000 > 7^2000

Chúc bạn học tốt @!!!

Nếu có thể thì t.i.c.k cho mình nha ! Thank

Đại ca toàn học giỏi nhất hành tinh đây

a) 29⁵⁷và 29⁷⁵

 ^=> 29⁵⁷<29⁷⁵

 -29.(85-47)-85.(47-29)

=-29.38-85.18

=-1102-1503

=-2605

-15.(23-29)+23-(15-29)

=-15.(-6)+23-(-14)

=90+23+14

=113+14

=127

 -13.(55-29)+23.(15-29)

=-13.26+23.(-14)

=-338+(-322)

=-660

-10.(2+4)-5.(4-3)

=-10.6-5.1

=-60-5

=-65

1/ 45. 18 - 5. 9. 28

= 45. 18 - (5. 9) . 28

= 45.18 - 45 .28

= 45. ( 18 - 28)

= 45. ( -10)

= -450

2/ 54 - 6. (12 + 9)

= 54 - 6. 9 + 6. 12

= 54 - 54 + 6. 12

= 0 + 6. 12

= 72

a)= 2021.2021-2020.(2021+1)
  = 2021.(2020+1)-2020.(2021+1)
  = (2021.2020)+2021-(2020.2021)-2020
  = 1

b) B= (1+2-3-4)+(5+6-7-8)+(9+10-11-12)...........+(2017+2018-2019-2020)+2021
    B= -4+(-4)+....................(-4)+2021
    B= -4x505+2021
    B= -2020 + 2021
    B = 1