Chứng minh rằng: \(2009^{2008}+2011^{2010}⋮2010\)
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Chứng minh rằng: \(2009^{2008}+2011^{2010}\) chia hết cho 2010.
Nó có chia hết à ???
Ta thấy 2009 chia 2010 dư -1
=> 2009 ^ 2008 chia 2010 dư 1 (1)
Lại có 2011 chia 2010 dư 1
=> 2011^2010 chia 2020 dư 1 (2)
Từ (1)(2) => 2009^2008-2011^2020 chia 2010 dư 2 (sai )
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2009^2008+2011^2010 chia hết cho 2010 2009^2008+2011^2010
=2009^2008+2011^2010
=2009^2008+2011^2010+1-1
=(2009^2008+ 1) + (2011^2010– 1)
= (2009 + 1)(2009^2007- …) + (2011 – 1)(2011^2009 + …)
= 2010(2009^2008 - …) + 2010(2011^2009+ …) chia hết cho 2010
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2009^2008+2011^2010 chia hết cho 2010 2009^2008+2011^2010
=2009^2008+2011^2010
=2009^2008+2011^2010+1-1
=(2009^2008+ 1) + (2011^2010– 1)
= (2009 + 1)(2009^2007- …) + (2011 – 1)(2011^2009 + …)
= 2010(2009^2008 - …) + 2010(2011^2009+ …) chia hết cho 2010
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Xem thêm câu trả lời
a) Chứng tỏ rằng: 1/41+1/42+1/43+...+1/80 > 7/12
b) So sánh: A=2008/2009+2009/2010+2010/2011 VÀ B=2008+2009+2010/2009+2010+2011
\(\frac{1}{41}+\frac{1}{42}+\frac{1}{43}+.....+\frac{1}{80}\)
\(=\left(\frac{1}{41}+\frac{1}{42}+\frac{1}{43}+\frac{1}{44}+.....+\frac{1}{60}\right)+\left(\frac{1}{61}+\frac{1}{62}+......+\frac{1}{80}\right)\)
\(>\left(\frac{1}{60}+\frac{1}{60}+\frac{1}{60}+.....+\frac{1}{60}\right)+\left(\frac{1}{80}+\frac{1}{80}+\frac{1}{80}+.....+\frac{1}{80}\right)\)
\(=\frac{1}{3}+\frac{1}{4}\)
\(=\frac{7}{12}\)
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\(B=\frac{2008+2009+2010}{2009+2010+2011}=\frac{2008}{2009+2010+2011}+\frac{2009}{2009+2010+2011}+\frac{2010}{2009+2010+2011}\)
\(< \frac{2008}{2009}+\frac{2009}{2010}+\frac{2010}{2011}=A\)
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Chứng minh rằng: \(2009^{2008}+2011^{2010}\)chia hết cho 2010
From: exoplanet
To: Nguyễn Ngọc Phương Thảo
\(2009^{2008}+2011^{2010}=\left(2009^{2008}+1\right)+\left(2011^{2010}-1\right)\)
\(=\left(2009+1\right)\left(2009^{2007}+a\right)+\left(2011-1\right)\left(2011^{2009}-b\right)\)
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chứng minh rằng : \(2009^{2008}+2011^{2010}\) chia hết cho 2010
Cho M=3^2012-3^2011+3^2010-3^2009+3^2008 \(M=3^{2012}-2^{2011}+3^{2010}-3^{2009}+3^{2008}\)
Chứng minh rằng M chia hết cho 10
chứng minh rằng : \(2009^{2008}+2011^{2010}\) chia hết cho 2010
Chứng minh rằng: \(2009^{2008}+2011^{2010}\)chia hết cho \(2010\)
so sanh
A=2008/2009+2009/2010+2010+2011
B=2008+2009+2010/2009+2010+2011
Dễ thấy:
\(\frac{2008}{2009}>\frac{2008}{2009+2010+2011}\)
\(\frac{2009}{2010}>\frac{2009}{2009+2010+2011}\)
\(\frac{2010}{2011}>\frac{2010}{2009+2010+2011}\)
=>\(\frac{2008}{2009}+\frac{2009}{2010}+\frac{2010}{2011}>\frac{2008}{2009+2010+2011}+\frac{2009}{2009+2010+2011}+\frac{2010}{2009+2010+2011}\)
Hay \(\frac{2008}{2009}+\frac{2009}{2010}+\frac{2010}{2011}>\frac{2008+2009+2010}{2009+2010+2011}\)
Vậy A > B
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So sánh A và B biết: A= \(\dfrac{2008+2008+2010}{2009+2010+2011}\) và B= \(\dfrac{2008}{2009}\)+ \(\dfrac{2009}{2010}\)+ \(\dfrac{2010}{2011}\)
A = \(\dfrac{2008}{2009+2010+2011}+\dfrac{2009}{2009+2010+2011}+\dfrac{2010}{2009+2010+2011}\)
Ta có:
\(\dfrac{2008}{2009}>\dfrac{2008}{2009+2010+2011}\)
\(\dfrac{2009}{2010}>\dfrac{2009}{2009+2010+2011}\)
\(\dfrac{2010}{2011}>\dfrac{2010}{2009+2010+2011}\)
Từ 3 điều trên suy ra : A < B
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