10.(17 - x) - 64 = 36
<=> 10.(17 - x) = 100
<=> 17 - x = 10
<=> x = 7
@Van Dong Pham

\(10\left(17-x\right)-64=36\)

\(10\left(17-x\right)=36+64\)

\(10\left(17-x\right)=100\)

\(17-x=100:10\)

\(17-x=10\)

\(x=17-10\)

\(x=7\left(tm\right)\)

Vậy ...............

\(10\left(17-x\right)-64=36\)

\(\Leftrightarrow10\left(17-x\right)=36+64\)

\(\Leftrightarrow10\left(17-x\right)=100\)

\(\Leftrightarrow17-x=100\div10\)

\(\Leftrightarrow17-x=10\)

\(\Leftrightarrow x=17-10\)

\(\Leftrightarrow x=7\)

Vậy \(x=7\)

10(17 - x) - 64 = 36
<=> 10(17 - x) = 100
<=> 17 - x = 10
<=> x = 7
@Van Dong Pham

\(10\left(17-x\right)-64=36\)

\(10\left(17-x\right)=36+64\)

\(10\left(17-x\right)=100\)

\(17-x=100:10\)

\(17-x=10\)

\(x=17-10\)

\(x=7\left(tm\right)\)

Vậy ...............

Ta có :10.(17-x)-64=36

=> 10.(17-x)=36+64

=> 10.(17-x)=100

=> 17-x=10

=> x=7

Vậy x=7

mai mình thi rồi, các bạn giúp mình với

Chờ tí

Câu 4: 

d) Ta có: \(\dfrac{-2}{17}+\dfrac{3}{19}+\dfrac{-15}{17}+\dfrac{16}{19}+\dfrac{5}{6}\)

\(=\left(-\dfrac{2}{17}-\dfrac{15}{17}\right)+\left(\dfrac{3}{19}+\dfrac{16}{19}\right)+\dfrac{5}{6}\)

\(=-1+1+\dfrac{5}{6}=\dfrac{5}{6}\)

Câu 3:

a) \(\dfrac{12}{36}=\dfrac{12:12}{36:12}=\dfrac{1}{3}\)

\(\dfrac{-16}{20}=\dfrac{-16:4}{20:4}=\dfrac{-4}{5}\)

b) \(\dfrac{21}{105}=\dfrac{21:21}{105:21}=\dfrac{1}{5}\)

\(\dfrac{35}{150}=\dfrac{35:5}{150:5}=\dfrac{7}{30}\)

Câu 4: 

a) \(\dfrac{3}{10}+\dfrac{5}{10}=\dfrac{3+5}{10}=\dfrac{8}{10}=\dfrac{4}{5}\)

b) Ta có: \(\left(-27\right)\cdot36+64\cdot\left(-27\right)+23\cdot\left(-100\right)\)

\(=\left(-27\right)\cdot\left(64+36\right)+23\cdot\left(-100\right)\)

\(=-27\cdot100-23\cdot100\)

\(=100\left(-27-23\right)\)

\(=-50\cdot100=-5000\)

c) \(\dfrac{5}{8}+\dfrac{3}{12}=\dfrac{15}{24}+\dfrac{6}{24}=\dfrac{21}{24}=\dfrac{7}{8}\)

d) Ta có: \(\dfrac{-2}{17}+\dfrac{3}{19}+\dfrac{-15}{17}+\dfrac{16}{19}+\dfrac{5}{6}\)

\(=\left(-\dfrac{2}{17}+\dfrac{-15}{17}\right)+\left(\dfrac{3}{19}+\dfrac{16}{19}\right)+\dfrac{5}{6}\)

\(=-1+1+\dfrac{5}{6}\)

\(=\dfrac{5}{6}\)

a,,83+17x=100

\(\Rightarrow\)17x=100-83

\(\Rightarrow17x=17\)

\(\Rightarrow\)x=1

Vậy x=1

b,100-64:(x-1)=36

\(\Rightarrow\)64:(x-1)=100-36

\(\Rightarrow\)64:(x-1)=64

\(\Rightarrow\)x-1=1

\(\Rightarrow\)x=2

Vậy x=2

Ta có: \(36.17+36.54+64.71\)

\(=36.\left(17+54\right)+64.71\)

\(=36.71+64.71\)

\(=71.\left(36+64\right)\)

\(=71.100=7100\)

\(=36.\left(17+54\right)+64.71\)

\(=36.71+64.71\)

\(=\left(36+64\right).71\)

\(=100.71\)

\(=7100\)

\(k\) \(mk\) \(nha\)

bài giải này bạn ơi

36 x 17 + 36 x 54 + 64 x 71 = 36 x (17 + 54) + 64 x 71 = 71 x (36 + 64) =7100

  17 . 64 + 36 . 17 = ?

= 17 . ( 64 + 36 )

= 17 .      100

= 1700

Chúc bạn học tốt !

a) (x.7 + 8) : 5 = 10

x.7 + 8 = 10.5

x.7 + 8 = 50

x.7 = 50 - 8

x.7 = 42

x = 42 : 7

x = 6

b) (x + 5).19 : 13 = 57

(x + 5).19 = 57 . 13

(x + 5).19 = 741

x + 5 = 741 : 19

x + 5 = 39

x = 39 - 5

x = 34

c) 4.(36 - 4.x) = 64

36 - 4x = 64 : 4

36 - 4x = 16

4x = 36 - 16

4x = 20

x = 20 : 4

x = 5

d) 7,6 : 19 . x = 3,2

0,4 . x = 3,2

x = 3,2 : 0,4

x = 8

e) (x : 2 + 50) : 5 = 12

x : 2 + 50 = 12 . 5

x : 2 + 50 = 60

x : 2 = 60 - 50

x : 2 = 10

x = 10 . 2

x = 20

g) 280 : (17 + 3.x) = 4

17 + 3x = 280 : 4

17 + 3x = 70

3x = 70 - 17

3x = 53

x = 53/3

h) 6.(28 - 8.x) = 72

28 - 8x = 72 : 6

28 - 8x = 12

8x = 28 - 12

8x = 16

x = 16 : 8

x = 2

i) (x - 15) : 3 : 12 = 6

(x - 15) : 3 = 6 . 12

(x - 15) : 3 = 72

x - 15 = 72 . 3

x - 15 = 216

x = 216 + 15

x = 231

a)16. x² = 64

x² = 64 : 16

x² = 4

x² = 2²

⇒ x = 2

b) (5.x - 2) - 64 = -36

(5.x - 2) = -36 + 64

5.x - 2 = 28

5.x = 28 + 2

5.x = 30

x = 30 : 5

x = 6

c) (2x - 10).(5 - x) = 0

TH1: 2x - 10 = 0

         2x = 0 + 10

         2x = 10

           x = 10 : 2

           x = 5

TH2: 5 - x = 0

              x = 5 - 0

              x = 5

⇒ Vậy x = 5.

cứu tui

\(16.x^2=64\)

\(=>x^2=64:16\)

\(=>x^2=4\)

\(=>x=2\) hoặc \(x=-2\)

_______

\(\left(5x-2\right)-64=-36\)

\(=>5x-2=\left(-36\right)+64\)

\(=>5x-2=28\)

\(=>5x=28+2\)

\(=>5x=30\)

\(=>x=30:5\)

\(=>x=6\)

_______

\(\left(2x-10\right).\left(5-x\right)=0\)

TH1: \(2x-10=0\)

\(=>2x=0+10\)

\(=>2x=10\)

\(=>x=10:2\)

\(=>x=5\)

TH2: \(5-x=0\)

\(x=5-0\)

\(x=5\)

\(=>x=5\)