3(x²-2x+1-y²⁾ 

=3((x-1)²-y²)

3.(x-1-y)(x-1+y)

tik nha 3:)

a) 3x^2 -6x + 3 - 3y^2

=3.(x²-2x+1-y²)

=3.[(x-1)²-y²]

=3.(x-1+y)(x-1-y)

a) xz-yz+5y-5x=\(z\left(x-y\right)+5\left(y-x\right)\)=\(z\left(x-y\right)-5\left(x-y\right)\)=\(\left(z-5\right)\left(x-y\right)\)

b) \(3x^2-6x+3-3y^2\)=\(3\left(x^2-2x+1-y^2\right)\)=\(3\left(\left(x-1\right)^2-y^2\right)\)=\(3\left(x-1-y\right)\left(x-1+y\right)\)

=(xz -yz)+(5y-5x)

= z(x-y)+5(y-z)

=(x-y)(z+5)

mk ko chắc răng đáp số cuối là đúng

\(=3\left(x^3-y^2\right)\)

Sửa: \(3x^2-3y^2=3\left(x^2-y^2\right)=3\left(x-y\right)\left(x+y\right)\)

3(x³-y²)

\(3x^2-6x+3=0\Leftrightarrow x^2-2x+1=0\Leftrightarrow\left(x-1\right)^2=0\Leftrightarrow x=1\)

\(x^4y-3x^3y^2+3x^2y^3+xy^4=xy\left(x^3-3x^2y+3xy^2+y^3\right)\)

\(x^2+3x+3y+xy=x^2+xy+3x+3y=x.\left(x+y\right)+3.\left(x+y\right)\) \(=\left(x+3\right)\left(x+y\right)\)

\(x^2+5x^2+6x=x^2+x+5x^2+5x=x\left(x+1\right)+5x\left(x+1\right)\) \(=\left(x+5x\right)\left(x+1\right)=6x\left(x+1\right)\)

a)\(x^2+3x+3y+xy\)

\(=x\left(x+y\right)+3\left(x+y\right)\)

\(=\left(x+3\right)\left(x+y\right)\)

x^2+3x+3y+xy = (x^2+3x)+(3y+xy) = x.(x+3)+y.(3+x) = (x+3).(x+y)

x^2+5x^2+6x = 6x^2+6x = 6x.(x+1)

\(x^3-3x^2+6x-4\)

\(=x^3-2x^2+4x-x^2+2x-4\)

\(=\left(x^3-2x^2+4x\right)-\left(x^2-2x+4\right)\)

\(=x\left(x^2-2x+4\right)-\left(x^2-2x+4\right)\)

\(=\left(x-1\right)\left(x^2-2x+4\right)\)

x^3 - 3x^2 + 6x - 4 

<=> x^3-3x^2+3x-1+3x-3

<=>(x-1)^3+3(x-1)

<=>(x-1)+((x-1)^2+3)

<=>(x-1)+(x^2-2x+4)