rút gọn p/s
a, \(\dfrac{2929-101}{2.1919+404}\)
b, \(\dfrac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(-100\right)^0}\)
Những câu hỏi liên quan
Rút gọn phân số
\(y=\frac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.1}\) ; \(\frac{2929-101}{2.1919+404}\) ; \(\frac{-1997.1996+1}{-1995.\left(-1997\right)+1996}\)
Rút gọn phân số :
a)\(\frac{6.9-2.17}{6.3-11.9}\)
b)\(\frac{3.13-13.18}{15.40-80}\)
c)\(\frac{\left(-5\right)^3.40.43}{135.\left(-2\right)^{14}.\left(-100\right)^0}\)
d)\(\frac{2929-101}{2.1919+404}\)
Can you help me ?
\(\dfrac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(-100\right)^0}\)
\(\dfrac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(-100\right)^0}=\dfrac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.1}=\dfrac{\left(-15\right).40.64}{135.\left(-2\right)^{14}}=\dfrac{\left(-5\right).3.5.8.64}{15.9.\left(-2\right)^{14}}=\dfrac{8.\left(-5\right).\left(-2\right)^6}{9.\left(-2\right)^{14}}=\dfrac{\left(-2\right)^3.5}{9.\left(-2\right)^8}=\dfrac{5}{9.\left(-2\right)^5}\)
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rút gọn phân số\(a,\frac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(-100\right)^0}\)
\(\frac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(-100\right)^0}=\frac{\left(-5\right)^3.40.4^3}{5.27.4^7}=\frac{\left(-5\right)^3.2}{3^3.4^3}=\frac{\left(-5\right)^3}{3^3.2^5}\)
có gì sai bỏ qua
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giúp mk nhé
\(\dfrac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(100\right)^0}\)
\(\dfrac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(100\right)^0}=\dfrac{\left(-5\right)^3.2^3.5.2^6}{3^2.5.2^{14}}\)
* giải thích : \(100^0\)= 1 nên mik ko viết nữa
\(\left(-2\right)^{14}=\left(2\right)^{14}\)
ta có : \(\dfrac{\left(-5\right)^3.2^9.5}{3^2.2^{14}.5}=\dfrac{-125}{9.32}=\dfrac{-125}{288}\)
tik mik nhé
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1 Rút gọn phân số
a)\(\frac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(-100\right)^0}\)
= ((-5)^3 . 5 . 2^3 . 2^6] / ( 5. 3^3 . 2^14 .1)
= ( (-5
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rút gọn:
\(\frac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(-100\right)^0}\)
giải chitieet hộ mk nha
\(\frac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(-100\right)^0}=\frac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}}=\frac{40.\left(-15\right).64}{135.\left(-2\right)^{14}}=\frac{5.8.3.\left(-5\right).64}{15.9.\left(-2\right)^{14}}=\frac{8.\left(-5\right).\left(-2\right)^6}{9.\left(-2\right)^{14}}=\frac{\left(-2\right)^3.5}{9.\left(-2\right)^8}=\frac{5}{9.\left(-2\right)^5}\)
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a)frac{-135}{540}b)frac{25.13}{26.35}c)frac{6.9-2.17}{63.3-119}d)frac{3.13-13.18}{15.40-80}e)frac{-5^3.40.4^4}{135.left(-2right)^{14}.left(-100right)^0}f)frac{2929-101}{2.1919+404}g)frac{-1997.1996+1}{left(-1995right).left(-1997right)+1996}h)frac{2.3+4.6+14.21}{3.5+6.10+21.35}i)frac{3.7.13.37.39-10101}{505050-70707}k)frac{18.34+left(-18right).124}{-36.17+9.left(-52right)}
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a)\(\frac{-135}{540}\)
b)\(\frac{25.13}{26.35}\)
c)\(\frac{6.9-2.17}{63.3-119}\)
d)\(\frac{3.13-13.18}{15.40-80}\)
e)\(\frac{-5^3.40.4^4}{135.\left(-2\right)^{14}.\left(-100\right)^0}\)
f)\(\frac{2929-101}{2.1919+404}\)
g)\(\frac{-1997.1996+1}{\left(-1995\right).\left(-1997\right)+1996}\)
h)\(\frac{2.3+4.6+14.21}{3.5+6.10+21.35}\)
i)\(\frac{3.7.13.37.39-10101}{505050-70707}\)
k)\(\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\)
15 tháng 3 2021 lúc 12:19
Rút gọn phân số:a) dfrac{2929-101}{2.1149+404}b) dfrac{6.9-2.17}{63.3-119}c) dfrac{3.13-13.18}{15.40-80}d) dfrac{-1997-1996+1}{left(-1995right).left(-1997right)+1996}e) dfrac{2.3+4.6+14.21}{3.5+6.10+21.35}g) dfrac{left(-5right)^3.40.4^3}{135.left(-3right)^{14}.left(-100right)^0} h) dfrac{18.34+left(-18right).124}{-36.17+9.left(52right)}j) dfrac{9.11+32.9}{23.15+12.23}k) dfrac{12.13+24.26+36.39}{24.26+48.52+72.78}
Đọc tiếp
Rút gọn phân số:
a) \(\dfrac{2929-101}{2.1149+404}\)
b) \(\dfrac{6.9-2.17}{63.3-119}\)
c) \(\dfrac{3.13-13.18}{15.40-80}\)
d) \(\dfrac{-1997-1996+1}{\left(-1995\right).\left(-1997\right)+1996}\)
e) \(\dfrac{2.3+4.6+14.21}{3.5+6.10+21.35}\)
g) \(\dfrac{\left(-5\right)^3.40.4^3}{135.\left(-3\right)^{14}.\left(-100\right)^0}\)
h) \(\dfrac{18.34+\left(-18\right).124}{-36.17+9.\left(52\right)}\)
j) \(\dfrac{9.11+32.9}{23.15+12.23}\)
k) \(\dfrac{12.13+24.26+36.39}{24.26+48.52+72.78}\)
b) \(\dfrac{6\cdot9-2\cdot17}{63\cdot3-119}\)
\(=\dfrac{2\left(3\cdot9-17\right)}{7\cdot\left(3\cdot9-17\right)}\)
\(=\dfrac{2}{7}\)
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