45 x 8+8 x 55

=(45+55) x 8

=100 x 8

=800

60 x 3+60 x 96+60

=60 x (3+96+1)

=60 x 100

=6000

* 45 x 8 + 8 x 55

= 8 x (45 + 55)

= 8 x 100

= 800

* 60 x 3 + 60 x 96 + 60

= 60 x (3 + 96 + 1)

= 60 x 100

= 6000

(Nhớ k cho mình với nhá!) 

a, 45 x 8 + 8 x 55

=  8 x ( 45 + 55 )

=  8x 100

=   800

b, 60 x 3+ 60 x 96 + 60

= 60 x ( 3 + 96 + 1)

= 60 x 100

= 6 000

Mong các bạn ủng hộ mk nha !! Ai đi qua xin để lại 1 k

            làm ơn hãy k mik

\(\dfrac{60}{x}-\dfrac{60}{x+20}=\dfrac{1}{2}\left(đk:x>0\right)\)

\(\Leftrightarrow\dfrac{120\left(x+20\right)-120x-x\left(x+20\right)}{2x\left(x+20\right)}=0\)

\(\Leftrightarrow120x+2400-120x-x^2-20x=0\)

\(\Leftrightarrow-x^2-20x+2400=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x_1=40\left(n\right)\\x_2=-60\left(l\right)\end{matrix}\right.\)

Vậy \(S=\left\{40\right\}\)

Đề sai rồi bạn

60 + 60 x 60

= 60 + 3600

= 3660

K MK NHA

60 + 60 x 60 =

= 60x(60+1)

=60.61

=3660

\(60+60.60\)

\(=60+3600\)

\(=3660\)

\(chucbnhocgioi!\)

\(nha^{ }\)

x + 60 = 60 + 60

x  + 60 = 120

x        = 120 - 60

x        = 60

Bạn tk mình đi . Mình tk bạn rùi đó

x + 60 = 60 + 60

x + 60 = 120

       x  = 120 - 60

       x  = 60

tk mk mk tk lại

X+60=60+60

X+60=120

X=120-60

X=60

\(\dfrac{120}{7}\)

\(\dfrac{300}{7}\)

60:7x2=120/7

60:7x5=300/7

60 : 7 x 2 = 120/7

60 : 7 x 5 = 300/7

 x - (28 - x) = x - 24x−(28−x)=x−24.

\(\dfrac{60}{x}-\dfrac{60}{x+2}=\dfrac{1}{20}\left(đk:x\ne0,x\ne-2\right)\)

\(\Leftrightarrow\dfrac{60x+120-60x}{x\left(x+2\right)}=\dfrac{1}{20}\)

\(\Leftrightarrow\dfrac{120}{x^2+2x}=\dfrac{1}{20}\Leftrightarrow x^2+2x=2400\)

\(\Leftrightarrow\left(x+1\right)^2=2401\)

\(\Leftrightarrow\left[{}\begin{matrix}x+1=49\\x+1=-49\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=48\\x=-50\end{matrix}\right.\)(thỏa đk)

Ta có: \(\dfrac{60}{x}-\dfrac{60}{x+2}=\dfrac{1}{20}\)

\(\Leftrightarrow x\left(x+2\right)=1200x+2400-1200x\)

\(\Leftrightarrow x^2+2x-2400=0\)

\(\Delta=2^2-4\cdot1\cdot\left(-2400\right)=9604\)

Vì \(\Delta>0\) nên phương trình có hai nghiệm phân biệt là:

\(\left\{{}\begin{matrix}x_1=\dfrac{-2-98}{2}=-50\left(nhận\right)\\x_2=\dfrac{-2+98}{2}=48\left(nhận\right)\end{matrix}\right.\)