A=\(\dfrac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\dfrac{11.3^{29}-3^{29}.3}{2^2.3^{28}}=\dfrac{3^{29}.\left(11-3\right)}{2^2.3^{28}}=\dfrac{3^{29}.2^3}{2^2.3^{28}}=3.2=6\)

\(A=\dfrac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}=\dfrac{11\cdot3^{29}-3^{30}}{2^2\cdot3^{28}}\)

\(=\dfrac{3^{29}\cdot2^3}{3^{28}\cdot2^2}=3\cdot2=6\)

a) \(A=\dfrac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)

\(A=\dfrac{11.3^{29}-3^{30}}{2^2.3^{28}}\)

\(A=\dfrac{11.3^{29}-3^{29}.3}{2^2.3^{28}}\)

\(A=\dfrac{3^{29}.\left(11-3\right)}{2^2.3^{28}}\)

\(A=\dfrac{3^{29}.8}{2^2.3^{28}}\)

\(A=\dfrac{3.8}{4}=6\)

vậy \(A=6\)

b) \(B=\dfrac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

\(B=\dfrac{3^2.\left(2^2\right)^2.\left(2^{16}\right)^2}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)

\(B=\dfrac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)

\(B=\dfrac{3^2.2^{36}}{11.2^{35}-2^{35}.2}\)

\(B=\dfrac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)

\(B=\dfrac{3^2.2^{36}}{2^{35}.9}\)

\(B=\dfrac{3^2.2}{9}\)

\(B=\dfrac{9.2}{9}\)

\(B=2\)

vậy \(B=2\)

là ơn giúp với 

help me 

help me !

help me 

6

ai trả lời thì trả lời chi tiết đi

mình đang cần gấp

\(=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)

\(=\frac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{14.2}}\)

\(=\frac{11.3^{29}-3.3^{29}}{2^2.3^{28}}\)

\(=\frac{\left(11-3\right).3^{29}}{2^2.3^{28}}\)

\(=\frac{8.3^{29}}{4.3^{28}}\)

\(=6\)

45³ = (9.5)³ = 3⁶.5³

20⁴ = (4.5)⁴ = 2⁸.5⁴

18² = (9.2)² = 3⁴.2²

180⁵ = (4.9.5)⁵ = 2¹⁰.3¹⁰.5⁵

\(=\dfrac{3^6.5^3.2^8.5^4.3^4.2^2}{2^{10}.3^{10}.5^5}=\dfrac{2^{10}.3^{10}.5^7}{2^{10}.3^{10}.5^5}=5^2=25\)

\(B=\dfrac{11.3^{29}-3^{30}}{4.3^{28}}=\dfrac{3^{29}\left(11-3\right)}{3^{28}.4}=\dfrac{3.8}{4}=6\)