hết cỡ rồi ông tướng

\(\frac{1.3.5.7.9.....39}{21.22.23.24....40}\)

nhân cả tử và mẫu với 2,4,6,8,...,40 ta được:

\(\frac{\left(1.3.5.7.9.....39\right).\left(2.4.6.8.10.....40\right)}{\left(21.22.23....39.40\right).\left(2.4.6.8.10....40\right)}\)

\(=\frac{1..3.4.5.6.....39.40}{\left(21.22.23....40\right)\left(1.2.2.2.2.3.2.4...2.19.2.20\right)}\)

\(=\frac{1.2.3.4.5.6.7...39.40}{\left(1.2.3.4.5....39.40\right)2^{20}}\)

\(=\frac{1}{2^{20}}\)

A=\(\frac{1.2.3.....20.\left(21.22.23.....39\right)}{\left(21.22.23.....39\right).40}\)

A=\(\frac{1.2.3.....20}{40}\)

A=\(1.3.4.5.....18.19\)

+2.20/40.

A=1.3.4.5.....18.19+1.

A= tự bấm máy là ra.

tk mk nha các bn.

-chúc ai tk mk học giỏi-

ukm ko có j

\(\frac{39}{75}=\frac{39:3}{75:3}=\frac{13}{25}\)

\(\frac{48}{78}=\frac{48:6}{78:6}=\frac{8}{13}\)

\(\frac{120}{90}=\frac{120:30}{90:30}=\frac{4}{3}\)

_HT_

39/75 = 13/25

48/78= 8/13

120/90= 4/3

CM: \(\dfrac{1\cdot3\cdot5\cdot7\cdot\cdot\cdot39}{21\cdot22\cdot23\cdot\cdot\cdot40}=\dfrac{1}{2^{20}}\)

Biến đổi vế trái:

\(\dfrac{1\cdot3\cdot5\cdot7\cdot\cdot\cdot39}{21\cdot22\cdot23\cdot\cdot\cdot40}=\dfrac{1\cdot3\cdot5\cdot7\cdot\cdot\cdot19}{22\cdot24\cdot26\cdot\cdot\cdot40}\)

\(=\dfrac{1\cdot3\cdot5\cdot7\cdot\cdot\cdot19}{2\cdot11\cdot2^3\cdot3\cdot2\cdot13\cdot2^2\cdot7\cdot2\cdot15\cdot2^5\cdot2\cdot17\cdot2^2\cdot9\cdot2\cdot19\cdot2^3\cdot5}\)

\(=\dfrac{1\cdot3\cdot5\cdot7\cdot\cdot\cdot19}{\left(3\cdot5\cdot7\cdot\cdot\cdot19\right)2^{20}}\)

\(=\dfrac{1}{2^{20}}\)

\(\frac{1.3.5.7...39}{21.22.23...40}=\frac{\left(2.4.6.8...40\right).\left(1.3.5.7...39\right)}{\left(2.4.6.8...40\right).\left(21.22.23...40\right)}=\frac{1.2.3.4...40}{^{2^{20}.1.2.3.4...40}}=\frac{1}{2^{20}}\)

\(\frac{1.3.5.7....39}{21.22.23....40}=\frac{\left(2.4.6....40\right).\left(1.3.5.7....39\right)}{\left(2.4.6....40\right).\left(21.22.23...40\right)}=\frac{1.2.3.4....40}{2^{20}.1.2.3.4....40}=\frac{1}{2^{20}}\)

\(\dfrac{26}{39}=\dfrac{26:13}{39:13}=\dfrac{2}{3}\)
\(\dfrac{38}{57}=\dfrac{38:19}{57:19}=\dfrac{2}{3}\)

\(\dfrac{26}{39}=\dfrac{26:13}{39:13}=\dfrac{2}{3}\)

\(\dfrac{38}{57}=\dfrac{38:19}{57:19}=\dfrac{2}{3}\)

`26/39=(26:13)/(39:13)=2/3`

`38/57=(38:19)/(57:19)=2/3`