1\(\frac{2}{3}\):\(\frac{x}{4}\)=6:0,3
\(\left(x-2\right)^3+\frac{8}{27}=0\)
\(4\frac{1}{3}:\frac{x}{4}=6:0,3\)
(0,25-30%x).\(\frac{1}{3}-\frac{1}{4}=5\frac{1}{6}\)
\(\frac{x-2}{\frac{-2}{9}}=\frac{-2}{x-2}\)
a) Ta có: \(\left(x-2\right)^3+\frac{8}{27}=0\)
\(\Leftrightarrow\left(x-2\right)^3=\frac{-8}{27}\)
\(\Leftrightarrow\left(x-2\right)^3=\left(-\frac{2}{3}\right)^3\)
\(\Leftrightarrow x-2=\frac{-2}{3}\)
hay \(x=\frac{-2}{3}+2=\frac{4}{3}\)
Vậy: \(x=\frac{4}{3}\)
b) Ta có: \(4\frac{1}{3}:\frac{x}{4}=6:0,3\)
\(\Leftrightarrow\frac{13}{3}\cdot\frac{4}{x}=20\)
\(\Leftrightarrow\frac{4}{x}=20:\frac{13}{3}=20\cdot\frac{3}{13}=\frac{60}{13}\)
hay \(x=\frac{13\cdot4}{60}=\frac{13}{15}\)
Vậy: \(x=\frac{13}{15}\)
c) Ta có: \(\left(0,25-30\%x\right)\cdot\frac{1}{3}-\frac{1}{4}=5\frac{1}{6}\)
\(\Leftrightarrow\left(\frac{1}{4}-\frac{3x}{10}\right)\cdot\frac{1}{3}=\frac{31}{6}+\frac{1}{4}=\frac{65}{12}\)
\(\Leftrightarrow\frac{1}{4}-\frac{3x}{10}=\frac{65}{12}:\frac{1}{3}=\frac{65}{12}\cdot3=\frac{65}{4}\)
\(\Leftrightarrow\frac{3x}{10}=\frac{1}{4}-\frac{65}{4}=-16\)
\(\Leftrightarrow3x=-160\)
hay \(x=\frac{-160}{3}\)
Vậy: \(x=\frac{-160}{3}\)
d) Ta có: \(\frac{x-2}{-\frac{2}{9}}=\frac{-2}{x-2}\)
\(\Leftrightarrow\left(x-2\right)^2=-2\cdot\left(-\frac{2}{9}\right)=\frac{4}{9}\)
\(\Leftrightarrow\left[{}\begin{matrix}x-2=\frac{2}{3}\\x-2=-\frac{2}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\frac{2}{3}+2\\x=\frac{-2}{3}+2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\frac{8}{3}\\x=\frac{4}{3}\end{matrix}\right.\)
Vậy: \(x\in\left\{\frac{8}{3};\frac{4}{3}\right\}\)
a/ (x - 2)3 + \(\frac{8}{27}\) = 0
=> (x - 2)3 = 0 - \(\frac{8}{27}\) = \(\frac{-8}{27}\)
=> x - 2 = \(-\frac{2}{3}\)
=> x = \(-\frac{2}{3}+2=\frac{4}{3}\)
b/ \(4\frac{1}{3}:\frac{x}{4}=6:0,3\)
=> \(4\frac{1}{3}:\frac{x}{4}=6:\frac{3}{10}=6.\frac{10}{3}=20\)
=> \(\frac{x}{4}=4\frac{1}{3}:20=\frac{13}{3}.\frac{1}{20}=\frac{13}{60}\)
=> \(x=\frac{13}{60}.4=\frac{13}{15}\)
c/ \(\left(0,25-30\%x\right).\frac{1}{3}-\frac{1}{4}=5\frac{1}{6}\)
=> \(\left(0,25-30\%x\right).\frac{1}{3}=5\frac{1}{6}+\frac{1}{4}=\frac{65}{12}\)
=> \(0,25-\frac{30}{100}x=\frac{65}{12}:\frac{1}{3}=\frac{65}{12}.3=\frac{65}{4}\)
=> \(\frac{3}{10}x=0,25-\frac{65}{4}=\frac{1}{4}-\frac{65}{4}=-\frac{64}{4}=-16\)
=> \(x=-16:\frac{3}{10}=-16.\frac{10}{3}=-\frac{160}{3}\)
\(1\frac{2}{3}:\frac{x}{4}=6:0,3\)
\(1\frac{2}{3}:\frac{x}{4}=6:0,3\)
\(\frac{5}{3}:\frac{x}{4}=20\)
\(\Rightarrow\frac{x}{4}=\frac{5}{3}:20\)
\(\Rightarrow\frac{x}{4}=\frac{1}{12}\Rightarrow x=\frac{4}{12}=\frac{1}{3}\)
Tìm x, biết
\(a,1\frac{2}{3}:\frac{x}{4}=6:0,3\)
\(b,2\frac{2}{3}:x=1\frac{7}{9}:2\frac{2}{3}\)
Tìm x,biết
A,\(1\frac{1}{2}:\frac{x}{4}=6:0,3\)
B,\(2\frac{2}{3}:x=1\frac{7}{9}:2\frac{2}{3}\)
a) \(-\frac{3}{7}+x=\frac{1}{3}\)
b) \(-\frac{5}{8}+x=\frac{-2^2}{3}\)
c) \(4\frac{1}{3}:\frac{x}{4}=6:0,3\)
a) \(\frac{-3}{7}+x=\frac{1}{3}\)
\(\Leftrightarrow x=\frac{1}{3}+\frac{3}{7}\)
\(\Leftrightarrow x=\frac{16}{21}\)
b) \(\frac{-5}{8}+x=\frac{-2^2}{3}\)
\(\Leftrightarrow x=\frac{-4}{3}+\frac{5}{8}\)
\(\Leftrightarrow x=-\frac{17}{24}\)
c) \(4\frac{1}{3}:\frac{x}{4}=6:0,3\)
\(\Leftrightarrow\frac{8}{3}:\frac{x}{4}=20\)
\(\Leftrightarrow\frac{32}{3x}=20\)
\(\Leftrightarrow3x=\frac{8}{5}\)
\(\Leftrightarrow x=\frac{8}{15}\)
\(4\frac{1}{3}:\frac{x}{4}=6:0,3\)
\(\frac{13}{3}:\frac{x}{4}=6:0,3\)
\(\frac{13}{3}:\frac{x}{4}=20\)
\(\frac{x}{4}=\frac{13}{3}:20\)
\(\frac{x}{4}=\frac{13}{3.20}\)
\(\frac{x}{4}=\frac{13}{60}\)
\(60x=13.4\)
\(60x=52\)
\(x=\frac{52}{60}\)
\(x=\frac{13}{15}\)
Vậy \(x=\frac{13}{15}\)
Tìm x trong các tỉ lệ thức sau:
a) \(\left(\frac{1}{3}.x\right):\frac{2}{3}=1\frac{3}{4}:\frac{2}{5}\)
b) 4,5 : 0,3 = 2,25 : (0,1 .x)
c) 8 : \(\left(\frac{1}{4}.x\right)=2:0,02\)
d) 3 : \(2\frac{1}{4}=\frac{3}{4}:\left(6.x\right)\)
\(\frac{1}{3}x:\frac{2}{3}=1\frac{3}{4}:\frac{2}{5}\)
\(\Rightarrow\frac{1}{3}x:\frac{2}{3}=\frac{35}{8}\)
\(\Rightarrow\frac{1}{3}x=\frac{35}{12}\)
\(\Rightarrow x=\frac{35}{4}\)
a) \(\left(\frac{1}{3}\cdot x\right):\frac{2}{3}=1\frac{3}{4}:\frac{2}{5}\)
\(=\left(\frac{1}{3}\cdot x\right):\frac{2}{3}=\frac{35}{8}\)
\(\Rightarrow\frac{1}{3}\cdot x=\frac{35}{8}\cdot\frac{2}{3}\)
\(\Rightarrow x=\frac{35}{12}:\frac{1}{3}=\frac{35}{4}\)
b) \(4,5:0,3=2,5:\left(0,1\cdot x\right)\)
\(=15=2,5:\left(0,1\cdot x\right)\)
\(\Rightarrow0,1\cdot x=2,25:15\)
\(\Rightarrow x=\frac{3}{20}:0,1=\frac{3}{2}=1,5\)
c) \(8:\left(\frac{1}{4}\cdot x\right)=2:0,02\)
\(8:\left(\frac{1}{4}\cdot x\right)=100\)
\(\Rightarrow\frac{1}{4}\cdot x=8:100\)
\(\Rightarrow x=\frac{2}{25}:\frac{1}{4}=\frac{8}{25}=0,32\)
d) \(3:2\frac{1}{4}=\frac{3}{4}:\left(6\cdot x\right)\)
\(=\frac{4}{3}=\frac{3}{4}:\left(6:x\right)\)
\(\Rightarrow6\cdot x=\frac{3}{4}:\frac{4}{3}\)
\(\Rightarrow x=\frac{9}{16}:6=\frac{3}{32}=0,09375\)
Tính
A) \(\frac{15}{34}+\frac{7}{21}+\frac{19}{34}-1\frac{15}{17}+\frac{2}{3}\)
B) \(\left(-2\right)^3\times\left(\frac{3}{4}-0,25\right):\left(2\frac{1}{4}-1\frac{1}{6}\right)\)
Tìm x
A) \(4\frac{1}{3}:\frac{\chi}{4}=6:0,3\)
B) \(\left(2^3:4\right)\times2^{\left(\chi+1\right)}=64\)
Tính:
b) \(\left(-2\right)^3.\left(\frac{3}{4}-0,25\right):\left(2\frac{1}{4}-1\frac{1}{6}\right)\)
\(=\left(-2\right)^3.\left(\frac{3}{4}-\frac{1}{4}\right):\left(\frac{9}{4}-\frac{7}{6}\right)\)
\(=\left(-8\right).\frac{1}{2}:\frac{13}{12}\)
\(=\left(-4\right):\frac{13}{12}\)
\(=-\frac{48}{13}.\)
Tìm x
a) \(4\frac{1}{3}:\frac{x}{4}=6:0,3\)
⇒ \(\frac{13}{3}:\frac{x}{4}=20\)
⇒ \(\frac{x}{4}=\frac{13}{3}:20\)
⇒ \(\frac{x}{4}=\frac{13}{60}\)
⇒ \(x.60=4.13\)
⇒ \(x.60=52\)
⇒ \(x=52:60\)
⇒ \(x=\frac{13}{15}\)
Vậy \(x=\frac{13}{15}.\)
b) \(\left(2^3:4\right).2^{x+1}=64\)
⇒ \(\left(8:4\right).2^{x+1}=64\)
⇒ \(2.2^{x+1}=64\)
⇒ \(2^{x+1}=64:2\)
⇒ \(2^{x+1}=32\)
⇒ \(2^{x+1}=2^5\)
⇒ \(x+1=5\)
⇒ \(x=5-1\)
⇒ \(x=4\)
Vậy \(x=4.\)
Chúc bạn học tốt!
1) Tìm x Biết
x-\(\frac{1}{3}\)=\(\frac{3}{4}\)
\(\frac{-1,25}{x}=\frac{1}{-8}\)
\(4\frac{1}{3}\div\frac{x}{4}=6:0,3\)
\((x-\frac{4}{9})^2=\frac{1}{4}\)
\(9^x\times81^x=3^{2010}\)
tặng 3 tym cho những người trả lời nhanh nhất trong vòng 2 ngày