Viết PTHH thưc hiện chuỗi hóa sau:
a) Al->Al2O3-> Al(NO3)3->Al(OH)3->Al2O3->AlCl3->Al
Viết PTHH thể hiện chuỗi hóa học sau : Al ---> Al(NO3)3 ---> Al2O3 ---> Al ---> Ba(AlO2)2 Mình Cần Gấp
\(1.Al+4HNO_3\rightarrow Al\left(NO_3\right)_3+NO\uparrow+2H_2O\)
\(2.4Al\left(NO_3\right)_3\underrightarrow{t^0}2Al_2O_3+12NO\uparrow+3O_2\)
\(3.2Al_2O_3\underrightarrow{đpnc}4Al+3O_2\)
\(4.2Al+Ba\left(OH\right)_2+2H_2O\rightarrow Ba\left(AlO_2\right)_2+3H_2\)
viết PTHH hoàn thành dãy biến hóa sau: Al->Al2O3->Al(SO4)->AlCl3->Al(OH)3->Al2O3->Al/NaAlO2
\(2Al+3O_2\underrightarrow{^{^{t^o}}}2Al_2O_3\)
\(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)
\(Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_4\)
\(AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\)
\(2Al\left(OH\right)_3\underrightarrow{^{^{t^o}}}Al_2O_3+3H_2O\)
\(2NaOH+Al_2O_3\rightarrow2NaAlO_2+H_2O\)
Hoàn thành chuỗi phản ứng hóa học sau: Al =Al2O3 =AlCl3 =Al(Oh)3 =Al2O3 =Al = Al2cl3
\(4Al+3O_2\underrightarrow{^{^{t^0}}}2Al_2O_3\)
\(Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\)
\(AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\)
\(2Al\left(OH\right)_3^{ }\underrightarrow{^{^{t^0}}}Al_2O_3+3H_2O\)
\(2Al_2O_3\underrightarrow{^{^{đpnc}}}4Al+3O_2\)
\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)
Bài 3: Hoàn thành chuỗi phản ứng sau:
a. Al → Al2O3→Al2(SO4)3→Al(OH)3 →Al2O3→Al →NaAlO2
b.Al→AlCl3→Al(NO3)3→Al(OH)3→Al2(SO4)3→AlCl3→Al
c. Fe→FeCl2→Fe(OH)2→FeSO4→Fe(NO3)2→Fe→Fe3O4→Fe
d.Fe→FeCl3→Fe→Fe3O4→FeSO4.
Bài 3: Hoàn thành chuỗi phản ứng sau:
a. Al → Al2O3→Al2(SO4)3→Al(OH)3 →Al2O3→Al →NaAlO2
b.Al→AlCl3→Al(NO3)3→Al(OH)3→Al2(SO4)3→AlCl3→Al
c. Fe→FeCl2→Fe(OH)2→FeSO4→Fe(NO3)2→Fe→Fe3O4→Fe
d.Fe→FeCl3→Fe→Fe3O4→FeSO4.
Hãy viết pthh theo sơ đồ chuyển hóa sau:
a)Al>AlCl3>Al(OH)3>Al2O3>Al
b)Fe>FeCl3>Fe(OH)3>Fe2O3>Fe
a)
\(Al+\dfrac{3}{2}Cl_2\rightarrow AlCl_3\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ 2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\\ Al_2O_3\xrightarrow[criolic]{đpnc}2Al+\dfrac{3}{2}O_2\)
b)
\(Fe+\dfrac{3}{2}Cl_2\rightarrow FeCl_3\\ FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3+3NaCl\\ 2Fe\left(OH\right)_3\underrightarrow{t^o}Fe_2O_3+3H_2O\\ Fe_2O_3+3H_2\underrightarrow{t^o}2Fe+3H_2O\)
viết PTHH thực hiện chuỗi biến hóa sau
a, Al2O3->Al->Al(NO3)3->Al(OH)3->Al2O3->Al2(SO4)3->AlCl3->AL->Cu
b, Fe->FeCl3->Fe(OH)3->Fe2O3->Fe->FeCl2->Fe(NO3)2->FeCO3->FeSO4
c, Mg->MgO->MgCl2->Mg(OH)2->MgSO4->MgCl2->Mg(NO3)2->MgCO3
d, Cu(OH)2->CuO->CuSO4->CuCl2->Cu(NO3)2->Cu->CuO
a.
2Al2O3 \(\underrightarrow{t^o}\)4Al + 3O2\(\uparrow\)
Al + 6HNO3 \(\rightarrow\) Al(NO3)3\(\downarrow\) + 3NO2 + 3H2O
Al(NO3)3 + NaOH \(\rightarrow\) Al(OH)3\(\downarrow\) + NaNO3
2Al(OH)3 \(\xrightarrow[criolit]{đpnc}\) Al2O3 + 3H2O
Al2O3 + 3H2SO4 \(\rightarrow\) Al2(SO4)3 + 3H2O
Al2(SO4)3 + 3BaCl2 \(\rightarrow\) 3BaSO4\(\downarrow\) + 2AlCl3
2AlCl3 \(\xrightarrow[criolit]{đpnc}\) 2Al + 3Cl2\(\uparrow\)
2Al + 3CuSO4 \(\rightarrow\) 3Cu + Al2(SO4)3
phương trình hóa học biểu diễn dãy chuyển hóa sau Al2->Al2O3-> AlCl3 ->Al(no3)3-> Al(OH)3-> Al2O3-> NaAlO2
(1) \(4Al+3O_2\xrightarrow[]{t^\circ}2Al_2O_3\)
(2) \(Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\)
(3) \(AlCl_3+3AgNO_3\rightarrow Al\left(NO_3\right)_3+3AgCl\downarrow\)
(4) \(Al\left(NO_3\right)_3+3LiOH\rightarrow Al\left(OH\right)_3\downarrow+3LiNO_3\)
(5) \(2Al\left(OH\right)_3\xrightarrow[]{t^\circ}Al_2O_3+3H_2O\uparrow\)
(6) \(Al_2O_3+2NaOH\rightarrow2NaAlO_2+H_2O\)
Viết PTHH thực hiện dãy biến đổi sau:
Al → Al2O3 → AlCl3 → Al(OH)3 → Al2O3 → Al
4Al+3O2--->2Al2O3
Al2O3+6HCl---->2Alcl3+3H2O
AlCl3+3NaOH--->3NaCl+Al(OH)3
2Al(OH)3--->Al2O3+3H2O
Al2O3+3H2--->2Al+3H2O
4Al+3O2-->2Al2O3
Al2O3+6HCl-->2AlCl3+3H2O
AlCl3+3KOH-->3KCl+Al(OH)3
2Al(OH)3-->Al2O3+3H2O
2Al2O3-->4Al+3O2
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