chờ mk chút

\(a,6x^2-3xy=3x\left(2x-y\right)\)

\(b,12xz-5y=y\left(12x-5\right)\)

\(c,64x^2-49=\left(8x\right)^2-7^2=\left(8x-7\right)\left(8x+7\right)\)

\(d,25y^2-16z^2=\left(5y\right)^2-\left(4z\right)^2=\left(5y-4z\right)\left(5y+4z\right)\)

\(e,4-25y^2=2^2-\left(5y\right)^2=\left(2-5y\right)\left(2+5y\right)\)

\(f,25x^2-10x+1=\left(5x\right)^2-5x\cdot2\cdot1+1=\left(5x-1\right)^2\)

\(g,16-8y+y^2=4^2-4\cdot2\cdot y+y^2=\left(4-y\right)^2\)

\(h,1-6x+9x^2=1^2-6\cdot2\cdot x+\left(3x\right)^2=\left(1-3x\right)^2\)

M= x(12z - 5y)

\(M=12xz-5xy=x\left(12z-5y\right)\)

\(N=64^2-49=64^2-7^2=\left(64-7\right)\left(64+7\right)\)

\(P=25y^2-16z^2=\left(5y\right)^2-\left(4z\right)^2=\left(5y-4z\right)\left(5y+4z\right)\)

\(Q=4-25y^2=2^2-\left(5y\right)^2=\left(2-5y\right)\left(2+5y\right)\)

\(R=25x^2-10x+1=\left(5x-1\right)^2\)

\(O=16-8y+y^2=\left(4-y\right)^2\)

\(X=1-6x+9x^2=\left(1-3x\right)^2\)

Bài 2 :

Câu a : \(10x^3y^3-15x^2y^4+20x^3=5x^2\left(2xy^3-3y^4+4x\right)\)

Câu b : \(9x^3-18x^2y+9xy^2=9x\left(x^2-2xy+y^2\right)=9x\left(x-y\right)^2\)

Câu c : \(9x^2+6x+1-25y^2=\left(3x+1\right)^2-\left(5y\right)^2=\left(3x+5y+1\right)\left(3x-5y+1\right)\)

Câu d : \(x^2-3x-18=\left(x^2+3x\right)-\left(6x+18\right)=x\left(x+3\right)-6\left(x+3\right)=\left(x+3\right)\left(x-6\right)\)

\(\text{a) }-x^2+10x-25\\ =-\left(x^2-10x+25\right)\\ =-\left(x-5\right)^2\)

\(\text{b) }-x^2-6x-9\\ =-\left(x^2+6x+9\right)\\ =-\left(x+3\right)^2\)

\(\text{c) }-4x^2+20xy-25y^2\\ =-\left(4x^2-20xy+25y^2\right)\\ =-\left(2x-5y\right)^2\)

\(d\text{) }!!!\)

Sửa đề

x² - 25y² - 6x + 9

= (x² - 6x + 9) - 25y²

= (x - 3)² - (5y)²

= (x - 3 - 5y)(x - 3 + 5y)

= (x - 5y - 3)(x + 5y - 3)