a) 12

b) 19

c) 15

d) 30

a, \(\left|x+3\right|=15\)

TH1 : \(x+3=15\Leftrightarrow x=12\)

TH2 : \(x+3=-15\Leftrightarrow x=-18\)

b, \(\left|x-7\right|+13=15\Leftrightarrow\left|x-7\right|=2\)

TH1 : \(x-7=2\Leftrightarrow x=9\)

TH2 : \(x-7=-2\Leftrightarrow x=5\)

c, \(\left|x-3\right|-16=-4\Leftrightarrow\left|x-3\right|=12\)

TH1 : \(x-3=12\Leftrightarrow x=15\)

TH2 : \(x-3=-12\Leftrightarrow x=-9\)

d, \(26-\left|x+9\right|=-13\Leftrightarrow\left|x+9\right|=39\)

TH1 : \(x+9=39\Leftrightarrow x=30\)

TH2 : \(x+9=-39\Leftrightarrow x=-48\)

`1, -2/9 xx 15/17 + (-2/9) xx 2/17`

`= -2/9 xx (15/17 + 2/17)`

`= -2/9 xx 17/17`

`=-2/9xx1`

`=-2/9`

__

`-5/3 xx 6/5 + (-7/9) xx 3/10`

`= -30/15 + (-21/90)`

`= -2 + (-7/30)`

`=-60/30 +(-7/30)`

`=-67/30`

__

`15/20 xx 7/5 + (-9/7) xx (-6/4)`

`=3/4 xx7/5 + (-9/7) xx(-6/4)`

`= 21/20 + 54/28`

`= 21/20 + 27/14`

`=417/140`

__

`-25/13 xx 5/19 + (-25/13) xx 14/19`

`=-25/13 xx (5/19 +14/19)`

`=-25/13 xx 19/19`

`= -25/13 xx 1`

`=-25/13`

__

`-7/13 xx 13/5 + (-9/7) xx 5/3`

`=-7/5 +(-15/7)`

`=-124/35`

a,\(x+3=15\)

\(=>x=15-3=12\)

b,\(x-7+3=25\)

\(=>x=25+7-3=29\)

c,\(x-3-6=-4\)

\(=>x=-4+6+3=5\)

d,\(26-x+9=-13\)

\(=>26-x=-13-9=-22\)

\(=>26+22=x\)

\(=>x=48\)

x+3=15

    x=15-3

    x=12

Vậy x=12

x-7+3=25

x-7=25-3

x-7=22

   x=22+7

   x=29

Vậy x=29

x-3-6=-4

x-3=-4+6

x-3=2

   x=2+3

   x=5

Vậy x=5

26-x+9=-13

26-x=-13-9

26-x=22

     x=26-22

     x=4

Vậy x=4

\(x+3=15\Leftrightarrow x=15-3=12\)

\(x-7+3=25\Leftrightarrow x-7=25-3=22\Leftrightarrow x=22+7=29\)

\(x-3-6=-4\Leftrightarrow x-3=\left(-4\right)+6=2\Leftrightarrow x=2+3=5\)

\(26-x+9=-13\Leftrightarrow26-x=\left(-13\right)-9=-22\Leftrightarrow x=26-\left(-22\right)=48\)

1: =-2/9(15/17+2/17)=-2/9

2: \(=\dfrac{-6}{3}+\dfrac{-21}{90}\)

=-2-7/30=-67/30

3: \(=\dfrac{3}{4}\cdot\dfrac{7}{5}+\dfrac{9}{7}\cdot\dfrac{3}{2}\)

=21/20+27/14=417/140

4: =-25/13(5/19+14/19)=-25/13

5: =-7/5-45/21=-7/5-15/7=-124/35

1: =-2/9(15/17+2/17)=-2/9

2: =34⋅75+97⋅32=34⋅75+97⋅32

=21/20+27/14=417/140

4: =-25/13(5/19+14/19)=-25/13

5: =-7/5-45/21=-7/5-15/7=-124/35

a) \(\left|x+3\right|=15\)

\(\Rightarrow\orbr{\begin{cases}x=15-3\\x=-15-3\end{cases}\Rightarrow}\orbr{\begin{cases}x=12\\x=-18\end{cases}}\)

b) Đề sai

c) Đề sai

d) \(26-\left|x+9\right|=-13\)

\(\Rightarrow\left|x+9\right|=26-\left(-13\right)\)

\(\Rightarrow\left|x+9\right|=39\)

\(\Rightarrow\orbr{\begin{cases}x=39-9\\x=-39-9\end{cases}\Rightarrow\orbr{\begin{cases}x=30\\x=-48\end{cases}}}\)

Em ơi ở câu b,c ko có x thì sao mà làm

c,

,\(/x-3/-16=-4\\ =>/x-3/=12\\ =>\hept{\begin{cases}x-3=12\\x-3=-12\end{cases}}=>\hept{\begin{cases}x=15\\x=-9\end{cases}}\)

b,

\(/x-7/+13=25\\ =>/x-7/=12\\ =>\hept{\begin{cases}x-7=12\\x-7=-12\end{cases}}=>\hept{\begin{cases}x=19\\x=-5\end{cases}}\)

Ko pk sai đề đâu ~.~

Tìm x thuoc z:

1) \(26-\left|x+9\right|=-13\)

\(\Leftrightarrow\left|x+9\right|=26-\left(-13\right)\)

\(\Leftrightarrow\left|x+9\right|=39\)

\(\Leftrightarrow\left[{}\begin{matrix}x+9=39\\x+9=-39\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=39-9=30\\x=-39-9=-48\end{matrix}\right.\)

Vậy: \(x\in\left\{30;-48\right\}\)

2) \(\left|x+7\right|-13=25\)

\(\Leftrightarrow\left|x+7\right|=25+13=38\)

\(\Leftrightarrow x+7\in\left\{38;-38\right\}\)

\(\Leftrightarrow x\in\left\{31;-45\right\}\)

Vậy:.................

tim x biet

\(1)123-3.\left(x+4\right)=23\)

\(\Leftrightarrow3\left(x+4\right)=123-23\)

\(\Leftrightarrow3\left(x+4\right)=100\)

\(\Leftrightarrow x+4=\frac{100}{3}\)

\(\Leftrightarrow x=\frac{100}{3}-4=\frac{100-12}{3}=\frac{88}{3}\)

Vậy:................

2) Tương tự

a)|x-7|+13=25

   |x-7|       = 25-13

   |x-7|       =  12

     |x|         = 12+7

=> x            = 19

b)|x-3|-16=-4

|x-3|          = -4+16

|x-3|          = 12

|x|              = 12+3

=> x           = 15

c)26-|x+9|=-13

|x+9|          = -13-26

|x+9|           = -39

|x|               = -39 -9

=> x             = 48

\(\frac{5}{14}\times\frac{7}{13}\times\frac{26}{25}=\frac{5\times7\times26}{14\times13\times25}=\frac{5\times7\times13\times2}{7\times2\times13\times5\times5}=\frac{1}{5}\)