720 : [ 41 - ( 2x-5)] = 2^3 .5

=> 720 :[ 41- (2x-5)] = 40

=> 41 - (2x-5) = 18

=> 2x -5 = 23

=> 2x = 28

=> x=14

720:[41-(2x-5)]=2³.5

720:[41-(2x-5)]=8.5

720:[41-(2x-5)]=40

      [41-(2x-5)]=720:40

      [41-(2x-5)]=18

            2x-5  = 41-18

              2x-5= 23

              2x  = 23+5

               2x = 28

                x =28:2

                x = 14

a) \(\left[\left(4x+28\right).3+55\right]:5=35\)

\(\Leftrightarrow\left(4x+28\right).3+55=35.5\)

\(\Leftrightarrow\left(4x+28\right).3+55=175\)

\(\Leftrightarrow\left(4x+28\right).3=175-55\)

\(\Leftrightarrow\left(4x+28\right).3=120\)

\(\Leftrightarrow4x+28=120:3\)

\(\Leftrightarrow4x+28=40\)

\(\Leftrightarrow4x=40-28\)

\(\Leftrightarrow4x=12\)

\(\Leftrightarrow x=12:4\)

\(\Leftrightarrow x=3\)

Vậy \(x=3\)

b) \(\left(12x-4^3\right).8^3=4.8^4\)

\(\Leftrightarrow12x-4^3=4.8^4:8^3\)

\(\Leftrightarrow12x-4^3=4.8^{4-3}\)

\(\Leftrightarrow12x-4^3=4.8\)

\(\Leftrightarrow12x-4^3=32\)

\(\Leftrightarrow12x-64=32\)

\(\Leftrightarrow12x=32+64\)

\(\Leftrightarrow12x=96\)

\(\Leftrightarrow x=96:12\)

\(\Leftrightarrow x=8\)

Vậy \(x=8\)

c) \(720:\left[41-\left(2x-5\right)\right]=2^3.5\)

\(\Leftrightarrow720:\left[41-\left(2x-5\right)\right]=8.5\)

\(\Leftrightarrow720:\left[41-\left(2x-5\right)\right]=40\)

\(\Leftrightarrow41-\left(2x-5\right)=720:40\)

\(\Leftrightarrow41-\left(2x-5\right)=18\)

\(\Leftrightarrow2x-5=41-18\)

\(\Leftrightarrow2x-5=23\)

\(\Leftrightarrow2x=23+5\)

\(\Leftrightarrow2x=28\)

\(\Leftrightarrow x=28:2\)

\(\Leftrightarrow x=14\)

Vậy \(x=14\)

Tìm x thuoc z:

1) \(26-\left|x+9\right|=-13\)

\(\Leftrightarrow\left|x+9\right|=26-\left(-13\right)\)

\(\Leftrightarrow\left|x+9\right|=39\)

\(\Leftrightarrow\left[{}\begin{matrix}x+9=39\\x+9=-39\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=39-9=30\\x=-39-9=-48\end{matrix}\right.\)

Vậy: \(x\in\left\{30;-48\right\}\)

2) \(\left|x+7\right|-13=25\)

\(\Leftrightarrow\left|x+7\right|=25+13=38\)

\(\Leftrightarrow x+7\in\left\{38;-38\right\}\)

\(\Leftrightarrow x\in\left\{31;-45\right\}\)

Vậy:.................

tim x biet

\(1)123-3.\left(x+4\right)=23\)

\(\Leftrightarrow3\left(x+4\right)=123-23\)

\(\Leftrightarrow3\left(x+4\right)=100\)

\(\Leftrightarrow x+4=\frac{100}{3}\)

\(\Leftrightarrow x=\frac{100}{3}-4=\frac{100-12}{3}=\frac{88}{3}\)

Vậy:................

2) Tương tự

9. (x + 28) = 0

x + 28 = 0: 9

x + 28 = 0

x = 0 – 28

x = -28

Vậy x = -28. 

720:[41-(2x-5)]=2³.5

720:[41-(2x-5)]=8.5

720:[41-(2x-5)]=40

41-(2x-5)=720:40

41-(2x-5)=18

2x-5=41-18

2x-5=23

2x=23+5

2x=28

x=28:2

x=14

Vậy x=14

 b) 720:[41 -(2x-5)]= 8 . 5

720:[41-(2x-5)]=40

[41-(2x-5)]=720 : 40

[41-(2x-5)]=18 

2x-5=41-18

2x-5=23

2x=23+5

2x=28

x=28:2

x=14

Vậy x=14

chắc vại ;-;

a) 12 ( 2x - 6 ) - 43= 5³

12 ( 2x - 6 ) - 43= 125

12 ( 2x - 6 ) =125+43

12 ( 2x - 6 ) =168

2x - 6=168:12

2x - 6=14

2x=14+6

2x=20

x=20:2

x=10

b) 7 ( 25 - 3x ) = 3⁴ - 2⁵

 7 ( 25 - 3x ) = 49

25 - 3x =49:7

25 - 3x =7

3x=25-7

3x=18

x=18:3

x=6

c) ( 3x - 5 ) + 3⁴ + 6⁰ = 5³

( 3x - 5 ) + 81 + 1 = 125

( 3x - 5 ) + 81=125-1

( 3x - 5 ) + 81=124

3x - 5=124-81

3x - 5=43

3x=43+5

3x=48

x=48:3

x=16

d) 3x + 2x ( 2³ . 5 - 3² . 4 ) + 5² = 4⁴

3x + 2x ( 8 . 5 - 9 . 4 ) + 25 = 256

3x + 2x.4 + 25 = 256

3x + 2x.4=256-25

3x + 2x.4=231

(3+2).x.4=231

5x.4=231

5x=231:4

5x=57,75

x=57,75:5

x=11,55

e) 720 : [ 41 - (2x - 5 ) ] = 2³ .5

720 : [ 41 - ( 2x - 5 ) ] =40

41 - ( 2x - 5 )=720:40

41 - ( 2x - 5 )=18

 2x - 5=41-18

 2x - 5=23

2x=23+5

2x=28

x=28:2

x=14

720 : [(5 - 2x) - (-41)] = 2³ . 5

720 : [(5 - 2x) + 41] = 8 . 5

720 : [(5 - 2x) + 41] = 40

(5 - 2x) + 41 = 720 : 40

(5 - 2x) + 41 = 18

5 - 2x = 18 - 41

5 - 2x = -23

2x = 5 - (-23) = 5 + 23

2x = 28

x = 28 : 2 = 14

=> x = 14

(12x-4³).8³=4.8⁴

=> 12x-4³=4.8⁴:8³

=> 12x-64=4.8

=> 12x-64=32

=> 12x=32+64

=> 12x=96

=> x=8

720:[41-(2x-5)]=2³.5

=> 720:[41-(2x-5)]=40

=> 41-(2x-5)=720:40

=> 41-(2x-5)=18

=> 2x-5=41-18

=> 2x=23+5

=> 2x=28

=> x=14