Tìm x:
a) 5(2x - 1) + 4(8 - 3x)= -5
b) 3x(12x - 4) - 9x(4x - 3)= 30
Tìm x:
a) 3x ( 12x - 4 ) - 9x( 4x - 3 ) = 30
b) x( 5 - 2x) + 2x( x - 1) = 15
`@` `\text {Ans}`
`\downarrow`
`a)`
`3x ( 12x - 4 ) - 9x( 4x - 3 ) = 30`
`=> 3x (12x-4) - 3*3x (4x - 3) = 30`
`=> 3x [12x - 4 - 3(4x-3)] = 30`
`=> 3x (12x - 4 - 12x + 9) = 30`
`=> 3x (-4+9)=30`
`=> 3x*5=30`
`=> 3x=6`
`=> x=2`
Vậy, `x=2`
`b)`
`x( 5 - 2x) + 2x( x - 1)`
`=> x(5-2x) + 2x^2 - 2x=15`
`=> 5x - 2x^2 + 2x^2 - 2x =15`
`=> 3x = 15`
`=> x=5`
Vậy, `x=5.`
a: =>36x^2-12x-36x^2+27x=30
=>15x=30
=>x=2
b: =>5x-2x^2+2x^2-2x=15
=>3x=15
=>x=5
Tìm X a) 3x . ( 12x-4) - 9x . (4x-3)= 30 b) 6 . ( 2x+1) - 5 . ( X-2) = 10
a) \(3x\cdot\left(12x-4\right)-9x\cdot\left(4x-3\right)=30\)
\(\Leftrightarrow36x^2-12x-36x^2+27x=30\)
\(\Leftrightarrow15x=30\)
\(\Leftrightarrow x=\dfrac{30}{15}\)
\(\Leftrightarrow x=2\)
b) \(\left(2x+1\right)-5\left(x-2\right)=10\)
\(\Leftrightarrow2x+1-5x+10=10\)
\(\Leftrightarrow-3x+11=10\)
\(\Leftrightarrow-3x=10-11\)
\(\Leftrightarrow-3x=-1\)
\(\Leftrightarrow x=\dfrac{1}{3}\)
tìm x
a , 3x(12x-4)-9x(4x-3)=30
b, x(5-2x)+2x(x-1)=15
Tìm x, biết :
a) 3x.(12x - 4) - 9x.(4x - 3) = 30
b) x.(5 - 2x) + 2x.( x - 1) = 15
a, 3x.(12x-4)-9x(4x-3)=30
=>36x2-12x-36x2+27x=30
=>5x=30
=> x=6
b,x.(5-2x)+2x.(x-1)=15
=> 5x-2x2+2x2-2x=15
=>3x=15
=>x=5
tk mk nha bn
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a) 3x . (12x - 4) - 9x(4x - 3) = 30
3x . 12x - 12x - 9x.4x + 27x = 30
(3x . 12x - 9x . 4x) - (12x - 27x) = 30
(36x2 -36x2) + 15x = 30
=> 15x = 30
=> x = 30 : 15
=> x = 2
b) x.(5 - 2x) + 2x.(x - 1) = 15
5x - 2x2 + 2x2 - 2x = 15
(5x - 2x) - (2x2 - 2x2) = 15
=> 3x = 15
=> x = 15 : 3 = 5
Tìm x,biết
a)3x(12x-4)-9x(4x-3)=30
b)x(5-2x)+2x(x-1)=15
P(x) = 2x3 – 5x2 + 8x – 3
Nghiệm hữu tỷ nếu có của đa thức P(x) trên là:
(– 1); 1; (–1/2); 1/2 ; (–3/2); 3/2 ; –3…
Sau khi kiểm tra ta thấy x = 1/2 là nghiệm nên đa thức chứa nhân tử ( x – 1/2) hay (2x – 1). Do đó ta tìm cách tách các hạng tử của đa thức để xuất hiện nhân tử chung (2x – 1).
2x3 - 5x2 + 8x – 3 = 2x3- x2 – 4x2 + 2x + 6x – 3
= x2( 2x – 1) – 2x( 2x – 1) + 3(2x – 1)
= ( 2x – 1)(x2 – 2x + 3).
Hoặc chia P(x) cho (x – 1) ta được thương đúng là: x2 – 2x + 3
P(x) = 2x3 – 5x2 + 8x – 3 = ( 2x – 1)(x2 – 2x + 3)
Vậy P(x) = 2x3 – 5x2 + 8x – 3 = ( 2x – 1)(x2 – 2x + 3)
Tìm x, biết:
a) 3x(12x – 4) – 9x(4x – 3) = 30
b) x(5 – 2x) + 2x(x - 1) = 15
a) 3x(12x – 4) – 9x(4x – 3) = 30
36x2 – 12x – 36x2 + 27x = 30
15x = 30
x = 2
b) x(5 – 2x) + 2x(x – 1) = 15
5x – 2x2 + 2x2 – 2x = 15
3x = 15
x = 5
a) 3x(12x – 4) – 9x(4x – 3) = 30
36x2 – 12x – 36x2 + 27x = 30
15x = 30 x = 2
b) x(5 – 2x) + 2x(x – 1) = 15
5x – 2x2 + 2x2 – 2x = 15
3x = 15
x = 5
a) 3x(12x – 4) – 9x(4x – 3) = 30
36x2 – 12x – 36x2 + 27x = 30
15x = 30
x = 2
b) x(5 – 2x) + 2x(x – 1) = 15
5x – 2x2 + 2x2 – 2x = 15
3x = 15
x = 5
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Tìm x biết :
a) 3x(12x - 4 ) - 9x( 4x - 3 ) = 30
b) x( 5 - 2x ) + 2x ( x - 1 ) = 15
a) \(3x\left(12x-4\right)-9x\left(4x-3\right)=0\)
\(\Leftrightarrow3x\left(12x-4-12x+9\right)=0\)
\(\Leftrightarrow3x\cdot5=0\)
\(\Leftrightarrow x=0\)
b) \(x\left(5-2x\right)+2x\left(x-1\right)=15\)
\(\Leftrightarrow5x-2x^2+2x^2-2x=15\)
\(\Leftrightarrow3x=15\)
\(\Leftrightarrow x=5\)
a) 3x(12-4)-9x(4x-3)=0
=> 3x(12x-4-12x+9)=0
=>3x .5=0
=>x-0
b) 5x-2x^2+2x^2-2x=15
=>5x-2x=15
=>3x=15
=>x=5
a) 3x(12x-4)-9x(4x-3)=30
\(\Leftrightarrow\)3x(12x-4)-3.3x(4x-3)=30
\(\Leftrightarrow\)3x(12x-4-12x+9)=30
\(\Leftrightarrow\)3x.5=30
\(\Leftrightarrow\)3x=7
\(\Leftrightarrow\)x=\(\dfrac{7}{3}\)
b)x(5-2x)+2x(x-1)=15
\(\Leftrightarrow\)5x-2x2+2x2-2x=15
\(\Leftrightarrow\)3x=15
\(\Leftrightarrow\)x=5
Tìm x, biết:
a) 3x ( 12x – 4 ) – 9x ( 4x – 3 ) = 30
b) x ( 5 – 2x ) + 2x ( x – 1 ) = 15
a) 3x (12x – 4) – 9x (4x – 3) = 30
=> 36x2 – 12x – 36x2 + 27x = 30
=> 15x = 30
Vậy x = 2.
b) x (5 – 2x) + 2x (x – 1) = 15
=> 5x – 2x2 + 2x2 – 2x = 15
=> 3x = 15
=> x = 5
a) 3x (12x – 4) – 9x (4x – 3) = 30
=> 36x2 – 12x – 36x2 + 27x = 30
=> 15x = 30
Vậy x = 2.
b) x (5 – 2x) + 2x (x – 1) = 15
=> 5x – 2x2 + 2x2 – 2x = 15
=> 3x = 15
=> x = 5
a) 3x(12x - 4 ) -9x (4x -3 ) = 30
<=> 36x² - 12x - 36x²+27x = 30
<=> 15x = 30
<=> x=2
b) x(5-2x)+2x(x-1)=15
<=> 5x - 2x² + 2x² - 2x = 15
<=> 3x = 15
<=> x = 5.
Tìm x, biết:
a) 3x (12x - 4) - 9x (4x - 3) = 30;
b) x (5 - 2x) + 2x (x - 1) = 15.
Nhập 3x(12x-4)-9x(4x-3)=30 bấm Shift+Calc. Đáp án=2
Hjhj! mik chỉ biết vậy thôi!
Nhập x(5-2x)+2x(x-1)=15
Bấm Shift+Calc
Đáp án=5