làm hết chỗ này dến sáng mai  giù giễ nhưng lâu lắm 

thì cứ làm đi đúng k

1: =>(4x+5):3-11=41

=>(4x+5):3=52

=>4x+5=156

=>4x=151

hay x=151/4

2: \(\Leftrightarrow2^x\cdot\left(2^3+1\right)=144\)

\(\Leftrightarrow2^x=16\)

hay x=4

a) \(\left(4x+5\right):3-121:11=4\)

\(\Leftrightarrow\left(\dfrac{4x}{3}+\dfrac{5}{3}\right)-11=4\)

\(\Leftrightarrow\dfrac{4x}{3}+\dfrac{5}{3}-11=4\)

\(\Leftrightarrow\dfrac{4x}{3}+\dfrac{5}{3}-\dfrac{33}{3}=4\)

\(\Leftrightarrow\dfrac{4x}{3}+\dfrac{5-33}{3}=4\)

\(\Leftrightarrow\dfrac{4x}{3}-\dfrac{28}{3}=4\)

\(\Leftrightarrow\dfrac{4x}{3}=4+\dfrac{28}{3}\)

\(\Leftrightarrow\dfrac{4x}{3}=\dfrac{12}{3}+\dfrac{28}{3}\)

\(\Leftrightarrow\dfrac{4x}{3}=\dfrac{12+28}{3}\)

\(\Leftrightarrow\dfrac{4x}{3}=\dfrac{40}{3}\)

\(\Leftrightarrow4x=\dfrac{40}{3}.3\)

\(\Leftrightarrow4x=40\)

\(\Leftrightarrow x=\dfrac{40}{4}=10\)

Vậy \(x=10\)

c) ( 2x + 1 )³ =125

=> (2x+1)³=5³

=> 2x+1=5

=> 2x=4

=> x=2

vậy x=2

a, 11/12 - ( 2/5 + x ) = 2/3

<=> \(\frac{2}{5}+x=\frac{11}{12}-\frac{2}{3}=\frac{1}{4}\)

=> x=\(\frac{1}{4}-\frac{11}{12}=-\frac{2}{3}\)

b, 2x . ( x - 1/7 ) = 0

<=>\(\left[\begin{array}{nghiempt}x=0\\x-\frac{1}{7}=0\end{array}\right.\)<=> \(\left[\begin{array}{nghiempt}x=0\\x=\frac{1}{7}\end{array}\right.\)

vậy x={\(0;\frac{1}{7}\)}

c, 3/4 + 1/4 : x = 2/5

<=>\(\frac{1}{4}:x=\frac{2}{5}-\frac{3}{4}=-\frac{7}{20}\)

<=> \(x=\frac{1}{4}:\left(-\frac{7}{20}\right)=-\frac{5}{7}\)

vậy x=-5/7

a) \(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\frac{2}{3}\)

\(\Leftrightarrow\frac{11}{12}-\frac{2}{5}-x=\frac{2}{3}\)

\(\Leftrightarrow-x=\frac{2}{3}-\frac{11}{12}+\frac{2}{5}=\frac{3}{20}\)

\(\Leftrightarrow x=-\frac{3}{20}\)

b) \(2x\left(x-\frac{1}{7}\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x-\frac{1}{7}=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x=\frac{1}{7}\end{array}\right.\)

c) \(\frac{3}{4}+\frac{1}{4}:x=\frac{2}{5}\)

\(\Leftrightarrow\frac{1}{4x}=\frac{2}{5}-\frac{3}{4}=-\frac{7}{20}\)

\(\Leftrightarrow4x=\frac{-20}{7}\)

\(\Leftrightarrow x=-\frac{5}{7}\)

a) \(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\frac{2}{3}\)

\(\frac{2}{5}+x=\frac{11}{12}-\frac{2}{3}\)

\(\frac{2}{5}+x=\frac{1}{4}\)

\(x=\frac{1}{4}-\frac{2}{5}\)

\(x=-\frac{3}{20}\)

Vậy \(x=-\frac{3}{20}\)

b) \(2x\left(x-\frac{1}{7}\right)=0\)

\(\Rightarrow\begin{cases}2x=0\\x-\frac{1}{7}=0\end{cases}\Rightarrow\begin{cases}x=0\\x=\frac{1}{7}\end{cases}\)

Vậy x = 0 hoặc \(x=\frac{1}{7}\)

c) \(\frac{3}{4}+\frac{1}{4}:x=\frac{2}{5}\)

\(\frac{1}{4}:x=\frac{2}{5}-\frac{3}{4}\)

\(\frac{1}{4}:x=-\frac{7}{20}\)

\(x=\frac{1}{4}:\left(-\frac{7}{20}\right)\)

\(x=-\frac{5}{7}\)

Vậy \(x=-\frac{5}{7}\)

1) \(\frac{25}{12}.x+\frac{11}{15}=\frac{9}{10}\)

=> \(\frac{25}{12}.x=\frac{9}{10}-\frac{11}{15}\)

=> \(\frac{25}{12}.x=\frac{1}{6}\)

=> \(x=\frac{1}{6}:\frac{25}{12}\)

=> \(x=\frac{2}{25}\)

Vậy \(x=\frac{2}{25}\).

3) \(\frac{29}{12}.\left[x\right]-\frac{5}{6}=\frac{3}{8}\)

=> \(\frac{29}{12}.\left[x\right]=\frac{3}{8}+\frac{5}{6}\)

=> \(\frac{29}{12}.x=\frac{29}{24}\)

=> \(x=\frac{29}{24}:\frac{29}{12}\)

=> \(x=\frac{1}{2}\)

Vậy \(x=\frac{1}{2}\).

4) \(\left[4x+\frac{3}{4}\right]-\frac{5}{4}=2\)

=> \(\left[4x+\frac{3}{4}\right]=2+\frac{5}{4}\)

=> \(4x+\frac{3}{4}=\frac{13}{4}\)

=> \(4x=\frac{13}{4}-\frac{3}{4}\)

=> \(4x=\frac{5}{2}\)

=> \(x=\frac{5}{2}:4\)

=> \(x=\frac{5}{8}\)

Vậy \(x=\frac{5}{8}\).

5) 2^x + 2^x+3 = 144

⇔ 2^x + 2^x . 2³ = 144

⇔ 2^x . (1 + 2³) = 144

⇔ 2^x . 9 = 144

⇔ 2^x = 144 : 9

⇔ 2^x = 16

⇔ 2^x = 2⁴

=> x = 4

Vậy x = 4.

Chúc bạn học tốt!

(4x+5) : 3 -121 : 11 = 4

=> (4x + 5) : 3 - 11 = 4

=> (4x + 5) : 3 = 15

=> 4x + 5= 45

=> 4x = 40

=> x=10

Vậy...

(2x + 1)³ = 125

=> (2x + 1)³= 5³

=> 2x + 1= 5

=> 2x= 4

=> x=2

Vậy...

(4x - 1)² = 25.9

=> (4x - 1)²= (5.3)²

=> 4x - 1= 15

=> 4x = 16

=> x = 4

Vậy...

2^x + 2^x+3= 144

=> 2^x . (1 + 2³) = 144

=> 2^x . 9= 144

=> 2^x = 16 = 2⁴

=> x= 4

Vậy...

1 + 3 + 5 + ... + x = 1000 ( x lẻ)

Số số hạng của dãy số (1 + 3 + 5 + ... + x) là:

(x - 1) : 2 + 1 = (x-1)/2 + 2/2 = x - 1 + 2= (x + 1)/2 (số hạng)

=> (x+1)(x+1)/2 : 2=1000

=> (x+1)(x+1)=4000

=> (x+1)²= 4000

Ta có: 4000= 2⁵.5³

=> 4000 có số lượng ước là: (5+1).(3+1)= 24 là số chẵn

=> 4000 k phải là số chính phương

=> Không tìm được giá trị của x

Vậy...

ミ★ʂтαɾ ɠɾα¢ĭα★彡 ơi dấu / là gì

Là gạch ngang phân số nha!

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