Bài 1 : Tính giá trị của các biểu thức sau đã bỏ dấu ngoặc :
A= (3,1 - 2,5) - (-2,5 + 3,1)
B= (5,3 - 2,8) - (4 + 5,3)
C= -(251.3 + 281) + 3.251 - (1-281)
D= -\(\left(\frac{3}{5}+\frac{3}{4}\right)-\left(-\frac{3}{4}+\frac{2}{5}\right)\)
tính giá trị của các biểu thức sau khi đã bỏ dấu ngoặc
A=\(\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)
B=\(\left(5,3-2,8\right)-\left(4+5,3\right)\)
C=\(-\left(251.3+281\right)+3.251-\left(1-281\right)\)
D=\(-\left(\frac{3}{5}+\frac{3}{4}\right)-\left(-\frac{3}{4}+\frac{2}{5}\right)\)
A = \(\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)
\(=3,1-2,5+2,5-3,1=6,2\)
B = \(\left(5,3-2,8\right)-\left(4+5,3\right)\)
\(=5,3-2,8-4-5,3=-6,8\)
C = \(-\left(251.3+281\right)+3.251-\left(1-281\right)\)
\(=-251.3-281+3.251-1+281=-1\)
D = \(-\left(\frac{3}{5}+\frac{3}{4}\right)-\left(-\frac{3}{4}+\frac{2}{5}\right)\)
\(=-\frac{3}{5}-\frac{3}{4}+\frac{3}{4}-\frac{2}{5}=-1\)
(Nhớ k cho mình với nhá!)
Tính giá trị của các biểu thức sau khi đã bỏ dấu ngoặc :
\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)
\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)
\(C=-\left(251.3\right)+281+3.251-\left(1-281\right)\)
\(D=-\left(\dfrac{3}{5}+\dfrac{3}{4}\right)-\left(-\dfrac{3}{4}+\dfrac{2}{5}\right)\)
\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)
\(A=3,1-2,5+2,5-3,1\)
\(A=\left(3,1-3,1\right)-\left(2,5-2,5\right)\)
\(A=0-0\)
\(A=0\)
\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)
\(B=5,3-2,8-4-5,3\)
\(B=\left(5,3-5,3\right)-\left(2,8+4\right)\\ B=0-6,8\\ B=-6,8\)
Tính giá trị:
\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\\ A=3,1-2,5+2,5-3,1\\ A=\left(3,1-3,1\right)-\left(2,5-2,5\right)\\ A=0\)
\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\\ B=5,3-2,8-4-5,3\\ B=\left(5,3-5,3\right)-\left(2,8+4\right)\\ B=-6,8\)
\(C=-\left(251.3\right)+281+3.251-\left(1-281\right)\)
\(C=\left[-\left(251.3\right)+3.251\right]+\left[281-\left(1-281\right)\right]\\ C=0+560\\ C=560\)
\(D=-\left(\dfrac{3}{5}+\dfrac{3}{4}\right)-\left(-\dfrac{3}{4}+\dfrac{2}{5}\right)\\ D=-\dfrac{3}{5}-\dfrac{3}{4}+\dfrac{3}{4}-\dfrac{2}{5}\\ D=\left(-\dfrac{3}{5}-\dfrac{2}{5}\right)+\left(-\dfrac{3}{4}+\dfrac{3}{4}\right)\\ D=-1+0\\ D=-1\)
Tính giá trị biểu thức sau khi đã bỏ dấu ngoặc
\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)
\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)
A = (3,1 – 2,5) – (-2,5 + 3,1) = 3,1 – 2,5 + 2,5 – 3,1 = 0
B = (5,3 – 2,8) – (4 + 5,3) = 5,3 – 2,8 – 4 – 5,3
A=(3,1-2,5)-(-2,5+3,1)=3,1-2,5+2,5-3,1=0
B=(5,3-2,8)-(4+5,3)=5,3-2,8-4-5,3=-6,8
A = ( 3,1 − 2,5 ) − ( −2,5 + 3,1 )
A = 3, 1 - 2,5 + 2,5 - 3,1
A = 0
B = ( 5,3 − 2,8 ) − ( 4 + 5,3 )
B = 5,3 - 2,8 - 4 - 5,3
B = -6,8
tính giá trị của các biểu thức sau khi đã bỏ sấu ngoặc :
A= (3,1-2,5) - (2,5+3,1)
B= (5,3-2,8) - (4+5,3)
C= -(251 . 3 + 281) + 3 . 251 - (1-281)
D= -( \(\frac{3}{5}\)+ \(\frac{3}{4}\)) - ( -\(\frac{3}{4}\)+ \(\frac{2}{5}\) )
Đề bài: Tính:
a) \(\left(4,1-2,5\right)-\left(-2,5+3,1\right)\)
b)\(\left(5,3-2,8\right)-\left(4+5,3\right)\)
c)\(-\left(251,3+281\right)+3,251-\left(1-981\right)\)
d) \(-\left(\frac{3}{5}+\frac{3}{4}\right)-\left(-\frac{3}{4}+\frac{2}{5}\right)\)
a) (4,1 - 2,5 ) - ( -2,5 + 3,1 ) = 1,6 - 0,6 = 1
b) ( 5,3 - 2,8) - ( 4+ 5,3) = 2,5 - 9,3 = -6.8
c) -( 251,3 + 281) + 3,251 - (1 - 981) = -532,3 + 3,251 + 980 = 450,951
d) -(3/5 + 3/4) - ( -3/4 +2/5) = -3/5 - 3/4 + 3/4 - 2/5 = -1
tính giá trị biểu thức khi đã bỏ dấu ngoặc :
A = ( 3,1 - 2,5 ) - ( - 2,5 + 3,1 )
B = ( 5,3 - 2,8 ) - ( 4 + 5,3 )
C = - ( 251 .3 + 281 ) + 3 . 215 - ( 1 -281 )
D = -\((\dfrac{3}{5}+\dfrac{3}{4})\) - \((-\dfrac{3}{4}+\dfrac{2}{5})\)
giúp mk nhé
\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)
\(=3,1-2,5+2,5-3,1=0\)
\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)
\(=5,3-2,8-4-5,3=-6,8\)
\(C=-\left(251.3+281\right)+3.215-\left(1-281\right)\)
\(=-753-281+645-1+281\)
\(=-753+654-1=-100\)
\(D=-\left(\dfrac{3}{5}+\dfrac{3}{4}\right)-\left(\dfrac{-3}{4}+\dfrac{2}{5}\right)\)
\(=-\dfrac{3}{5}-\dfrac{3}{4}+\dfrac{3}{4}-\dfrac{2}{5}=\dfrac{-3}{5}-\dfrac{2}{5}=-1\)
\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)
\(=3,1-2,5+2,5-3,1\)
\(=\left(3,1-3,1\right)-\left(2,5-2,5\right)\)
\(=0\)
Vậy \(A=0.\)
\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)
\(=5,3-2,8-4-5,3\)
\(=\left(5,3-5,3\right)-\left(2,8+4\right)\)
\(=-\dfrac{34}{5}\)
Vậy \(B=\dfrac{-34}{5}.\)
\(C=-\left(251.3+281\right)+3.215-\left(1-281\right)\)
\(=-251.3-281+3.215-1+281\)
\(=-753-\left(281-281\right)+645\)
\(=-753+645=-108\)
Vậy \(C=-108.\)
\(D=-\left(\dfrac{3}{5}+\dfrac{3}{4}\right)-\left(-\dfrac{3}{4}+\dfrac{2}{5}\right)\)
\(=-\dfrac{3}{5}-\dfrac{3}{4}+\dfrac{3}{4}-\dfrac{2}{5}\)
\(=\left(\dfrac{-3}{5}-\dfrac{2}{5}\right)-\left(\dfrac{3}{4}-\dfrac{3}{4}\right)\)
\(=-1\)
Vậy D = -1.
A=(3,1-2,5)-(-2,5+3,1)
A=3,1-2,5=2,5-3,1
A=(3,1-3,1)+(2,5-2,50
A=0
B=(5,3-2,8)-(4+5,3)
B=5,3-2,8-4-5,3
B=(5,3-5,3)-(4+2,8)
B=0-6,8
B=-6,8
C=-(251.3+281)+3.215-(1-281)
C=-251.3-281+3.215-1+281
C=3(-251+215)-(281+281)-1
C=-108-1
C=-109
D=\(-\left(\dfrac{3}{5}+\dfrac{3}{4}\right)-\left(-\dfrac{3}{4}\right)+\dfrac{2}{5}\)
\(D=-\dfrac{3}{5}+-\dfrac{3}{4}+\dfrac{3}{4}+\dfrac{2}{5}\)
D=\(\left(-\dfrac{3}{5}+\dfrac{2}{5}\right)+\left(-\dfrac{3}{4}+\dfrac{3}{4}\right)\)
\(D=\dfrac{-1}{5}\)
a,(-3,8)+[(-5,7)+(3,8)]
b,[(-9,6)+(4,5)]+[(1,9)+(2,8)]
c,(3,1-2,5)-(-2,5+3,1)
d,-(251.3+281)+3.251-(1-281)
1,
a, \(\left(-3,8\right)+[\left(-5,7\right)+3,8]\)
b, 31,4 + [6,4+(-18)]
c, [(-9,6)+4,5]+[9,6+(-1,5)]
d, [(-4,9)+(-7,8)]+[1,9+2,8]
e, \(\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)
f,\(\left(5,3-2,8\right)-\left(4+5,3\right)\)
g, \(-\left(251,3+281\right)+3,251-\left(1-281\right)\)
h, \(-\left(\dfrac{3}{54}+\dfrac{3}{4}\right)-\left(\dfrac{-3}{4}+\dfrac{2}{5}\right)\)
GIÚP TỚ VỚI >< !!!
1a, (-3,8) + [ (-5,7)+3,8]
= (-3,8+3,8) -5,7
= -5,7
b, 31,4 +[6,4 +(-18)]
= 31,4 - 11,6
= 19,8
c,[(9,6 )+4,5 ] +[9,6 +(-1,5)]
= 9,6 +9,6 +(4,5-1,5)
= 19,2 +3
=22,2
d, [ (-4,9) + (-7,8)] +[1,9+2,8]
= (-4,9 +1,9)+ (-7,8+2,8)
= -3 -5
=-8
e, (3,1-2,5)-(-2,5+3,1)
= (3,1-3,1)+(2,5-2,5)
=0
f, (5,3 -2,8 )- (4+5,3)
= (5,3-5,3) -2,8-4
= -6,8
g, -(251,3 +281 )+ 3,251 -(1-281)
= -251,3-281+3,251 -1+281
= (-281+281) -251,3 +3,251 -1
= -249,049
h,-(3/54+3/4)-(-3/4 +2/5)
= -3/54-3/4 +3/4 +2/5
=(-3/4+3/4) -3/54 +2/5
=123/270
chúc bạn học tốt
Tính giá trị của các biểu thức sau khi bỏ dấu ngoặc: C = - (251.3 + 281) + 3.251 – (1- 281)
C = - (251.3 + 281) + 3.251 – (1- 281)
= -251.3 -281 + 251.3 -1 + 281
= (-251.3 + 251.3 )+ ( -281 + 281) -1
= 0 + 0 - 1 = -1.