Ta có : 

\(A=2.\left(\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+............+\frac{2}{53.55}\right)\)

\(\Rightarrow A=2.\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+..............+\frac{1}{53}-\frac{1}{55}\right)\)

\(\Rightarrow A=2.\left(\frac{1}{5}-\frac{1}{55}\right)=2.\frac{2}{11}=\frac{4}{11}\)

k nha bạn !!!

a)\(=\frac{3}{2}\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{2013}-\frac{1}{2015}\right)\)

\(=\frac{3}{2}\left(\frac{1}{5}-\frac{1}{2015}\right)\)

\(=\frac{3}{2}\cdot\frac{402}{2015}\)

\(=\frac{603}{2015}\)

b)\(=\frac{4}{5}\left(\frac{1}{3}-\frac{1}{8}+\frac{1}{8}-\frac{1}{13}+...+\frac{1}{93}-\frac{1}{98}\right)\)

\(=\frac{4}{5}\left(\frac{1}{3}-\frac{1}{98}\right)\)

\(=\frac{4}{5}\cdot\frac{95}{294}\)

\(=\frac{38}{147}\)

a) Gọi tổng trên là A

A = \(\frac{3}{5.7}+\frac{3}{7.9}+\frac{3}{9.11}+...+\frac{3}{2013.2015}\)

A == \(\frac{3}{5}-\frac{3}{7}+\frac{3}{7}-\frac{3}{9}+\frac{3}{9}-\frac{3}{11}+...+\frac{3}{2013}-\frac{3}{2015}\)

Vì một số trừ cho a rồi cộng cho a sẽ bằng chính số đó nên:

A = \(\frac{3}{5}-\frac{3}{2015}\)

A = \(\frac{1209}{2015}-\frac{3}{2015}\)

A = \(\frac{1206}{2015}\)

b) Gọi tổng trên là B

B = \(\frac{4}{3.8}+\frac{4}{8.13}+\frac{4}{13.15}+...+\frac{4}{93.98}\)

B = \(\frac{4}{3}-\frac{4}{8}+\frac{4}{8}-\frac{4}{13}+\frac{4}{13}-\frac{4}{15}+...+\frac{4}{93}-\frac{4}{98}\)

Vì một số trừ cho a rồi cộng cho a sẽ bằng chính số đó nên:

B = \(\frac{4}{3}-\frac{4}{98}\)

B = \(\frac{686}{294}-\frac{12}{294}\)

B = \(\frac{674}{294}=\frac{337}{147}\)

bai thang dung roi

\(=4\left(\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}+...+\frac{1}{53.55}\right)\)

\(=4\left(\frac{1}{5}-\frac{1}{5}+\frac{1}{7}-\frac{1}{7}+...+\frac{1}{53}-\frac{1}{55}\right)\)

\(=4\left(\frac{1}{5}-\frac{1}{55}\right)\)

\(=4.\frac{2}{11}\)

\(=\frac{8}{11}\)

dễ thế mà mày ko bít làm à

B=2(2/3.5 - 2/ 5.7 +....................+ 2/99.101) 

B=2(1/3.5 -2/5.7+..............+1/99.100)

B=2(1/3-1/5+1/5-.............+1/99-1/100)

B=2(1/3-1/100)

B=2.97/100

B=97/50

\(\frac{1}{2}-\frac{1}{1.3}-\frac{1}{3.5}-\frac{1}{5.7}-\frac{1}{7.9}-\frac{1}{9.11}=\frac{4}{5}-x\)

<=> \(2.\frac{1}{2}-\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\right)=\frac{8}{5}-2x\)

<=> \(1-\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{11}\right)=\frac{8}{5}-2x\)

<=> \(1-\left(1-\frac{1}{11}\right)-\frac{8}{5}=-2x\)

<=> \(-\frac{83}{55}=-2x\)

<=> \(x=\frac{83}{110}\)