​khó thế

Ta có :M=\(\frac{2012^{37}+37^{2012}+1}{2012^{38}}\)=\(\frac{1}{2012}\)+\(\frac{37^{2012}}{2018^{38}}\)+\(\frac{1}{2012^{38}}\)

N=\(\frac{2012^{38}+37^{2012}+2}{2012^{39}}\)=\(\frac{1}{2012}\)+\(\frac{37^{2012}}{2012^{39}}\)+\(\frac{2}{2012^{39}}\)

Suy ra: M-N=\(\frac{37^{2012}}{2012^{38}}\left(1-\frac{1}{2012}\right)\)+\(\frac{1}{2012^{38}}\left(1-\frac{2}{2012}\right)\)

\(\Rightarrow\)M-N=\(\frac{37^{2012}}{2012^{38}}.\frac{2011}{2012}+\frac{1}{2012^{38}}.\frac{2010}{2012}\)

\(\Rightarrow\)M-N>0

\(\Rightarrow\)M>N

Vậy M>N

Đặt \(A=\frac{37^{2013}+1}{37^{2012}+1}\) và \(B=\frac{37^{2014}+1}{37^{2013}+1}\) ta có : 

\(\frac{1}{37}A=\frac{37^{2013}+1}{37^{2013}+37}=\frac{37^{2013}+37-36}{37^{2013}+37}=\frac{37^{2013}+37}{37^{2013}+37}-\frac{36}{37^{2013}+37}=1-\frac{36}{37^{2013}+37}\)

\(\frac{1}{37}B=\frac{37^{2014}+1}{37^{2014}+37}=\frac{37^{2014}+37-36}{37^{2014}+37}=\frac{37^{2014}+37}{37^{2014}+37}-\frac{36}{37^{2014}+37}=1-\frac{36}{37^{2014}+37}\)

Vì \(\frac{36}{37^{2013}+37}>\frac{36}{37^{2014}+37}\) nên \(1-\frac{36}{37^{2013}+37}< 1-\frac{36}{37^{2014}+37}\)

\(\Rightarrow\)\(\frac{1}{37}A< \frac{1}{38}B\)

\(\Rightarrow\)\(A< B\)

Vậy \(A< B\)

Chúc bạn học tốt ~ 

\(A< B\)

Chúc bạn học tốt\(\approx\)

a) Ta có:

5³⁷ > 5³⁶ = (5³)¹² = 125¹²

11²⁴ = (11²)¹² = 121¹²

Vì 5³⁷ > 125¹² > 121¹²

=> 5³⁷ > 11²⁴

b) + Nếu a < b

=> 2012a < 2012b

=> 2012a + ab < 2012b + ab

=> a.(b + 2012) < b.(a + 2012)

=> \(\frac{a}{b}< \frac{a+2012}{b+2012}\)

+ Nếu a = b

=> 2012a = 2012b

=> 2012a + ab = 2012b + ab

=> a.(b + 2012) = b.(a + 2012)

=> \(\frac{a}{b}=\frac{a+2012}{b+2012}\)

+ Nếu a > b

=> 2012a > 2012b

=> 2012a + ab > 2012b + ab

=> a.(b + 2012) > b.(a + 2012)

=> \(\frac{a}{b}>\frac{a+2012}{b+2012}\)

ÁP DỤNG CÔNG THỨC NẾU \(\frac{a}{b}\)>1 thì

\(\frac{a}{b}\)>\(\frac{a+m}{b+m}\)

Ta có : \(\frac{2012^{12}+1}{2012^{13}+1}\)>\(\frac{2012^{12}+1+2011}{2012^{13}+1+2011}\)=\(\frac{2012^{12}+2012}{2012^{13}+2012}\)=\(\frac{2012.\left(2012^{11}+1\right)}{2012.\left(2012^{12}+1\right)}\)

rồi rút gọn thành \(\frac{2012^{11}+1}{2012^{12}+1}=B\)

Vậy A>B

Nhớ cho mình đúng nha

Ta có:\(A=\dfrac{2012^{2012}+1}{2012^{2013}+1}\)

\(\Rightarrow2012.A=\dfrac{2012^{2013}+2012}{2012^{2013}+1}=\dfrac{2012^{2013}+1+2011}{2012^{2013}+1}=1+\dfrac{2011}{2012^{2013}+1}\)Ta có:\(B=\dfrac{2012^{2011}+1}{2012^{2012}+1}\)

\(\Rightarrow2012.B=\dfrac{2012^{2012}+2012}{2012^{2012}+1}=\dfrac{2012^{2012}+1+2011}{2012^{2012}+1}=1+\dfrac{2011}{2012^{2012}+1}\)Vì\(\dfrac{2011}{2012^{2013}+1}< \dfrac{2011}{2012^{2012}+1}\)

\(\Rightarrow1+\dfrac{2011}{2012^{2013}+1}< 1+\dfrac{2011}{2012^{2012}+1}\)

\(\Rightarrow\dfrac{2012^{2012}+1}{2012^{2013}+1}< \dfrac{2012^{2011}+1}{2012^{2012}+1}\)

Vậy A<B

Ta có : \(Q=\frac{2010+2011+2012}{2011+2012+2013}\)

\(\Rightarrow Q=\frac{2010}{2011+2012+2013}+\frac{2011}{2011+2012+2013}+\frac{2012}{2011+2012+2013}\)

Mà \(\frac{2010}{2011}>\frac{2010}{2011+2012+2013}\)

       \(\frac{2011}{2012}>\frac{2011}{2011+2012+2013}\)

      \(\frac{2012}{2013}>\frac{2012}{2011+2012+2013}\)

Cộng vế theo vế, ta có : \(\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2013}>\frac{2010+2011+2012}{2011+2012+2013}\)

\(\Rightarrow P>Q\)

Ta có:

2010/2011 >2010/2011+2012+2013. ;2011/2012 >2011/2011+2012+2013 .;2012/2013 >2012/2011+2012+2013 ->2010/2011+2011/2012+2012/2013 >2010+2011+2012/2011+2012+2013. Vậy P > Q

thanks các bạn nhìu nha

ta có      A=\(\frac{2011+2012}{2012+2013}=\frac{2011}{2012+2013}+\frac{2012}{2012+2013}\)(1)

             B=\(\frac{2011}{2012}+\frac{2012}{2013}\left(2\right)\)

so sánh 1 và 2 ta có           A<B                       

B=2011+2012/2012+2013

=2011/2012+2013 +2012/2012+2013<2011/2012 +2012/2013=a

vậy........................

tai sao lai nhu vay?