a) \(27^{64}:81^{20}=3^{192}:3^{80}=3^{112}\)

b) \(\left(\dfrac{1}{8}\right)^{20}:\left(\dfrac{1}{16}\right)^9=\left(\dfrac{1}{2}\right)^{60}:\left(\dfrac{1}{2}\right)^{36}=\left(\dfrac{1}{2}\right)^{24}\)

c) \(\dfrac{1}{3}:\dfrac{1}{5}-\dfrac{1}{6}=\dfrac{5}{3}-\dfrac{1}{6}=\dfrac{10}{6}-\dfrac{1}{6}=\dfrac{9}{6}=\dfrac{3}{2}\)

                                                            Bài giải

\(\frac{2}{3}+\frac{3}{4}+\frac{4}{5}=\frac{40}{60}+\frac{45}{60}+\frac{48}{60}=\frac{133}{60}\)

\(\frac{8}{5}+\frac{7}{6}+\frac{10}{9}+\frac{1}{2}=\frac{144}{90}+\frac{105}{90}+\frac{100}{90}+\frac{45}{90}=\frac{394}{90}\)

\(\frac{15}{17}-\frac{11}{13}+\frac{3}{26}=\frac{390}{442}+\frac{374}{442}+\frac{51}{442}=\frac{815}{442}\)

\(\frac{9}{12}\text{ x }\frac{4}{3}\text{ : }\frac{8}{5}=\frac{9}{12}\text{ x }\frac{4}{3}\text{ x }\frac{5}{8}=\frac{9\text{ x }4\text{ x }5}{12\text{ x }3\text{ x }8}=\frac{5}{8}\)

\(\frac{4}{5}\text{ x }\frac{15}{8}\text{ : }\frac{5}{7}=\frac{4}{5}\text{ x }\frac{15}{8}\text{ x }\frac{7}{5}=\frac{4\text{ x }15\text{ x }7}{5\text{ x }8\text{ x }5}=\frac{21}{10}\)

\(\frac{2}{3}+\frac{3}{4}+\frac{4}{5}=\frac{40}{60}+\frac{45}{60}+\frac{48}{60}=\frac{133}{60}\) 

\(\frac{8}{5}+\frac{7}{6}+\frac{10}{9}+\frac{1}{2}=\frac{144}{90}+\frac{105}{90}+\frac{100}{90}+\frac{45}{90}=\frac{197}{45}\)

\(\frac{15}{17}-\frac{11}{13}+\frac{1}{26}=\frac{390}{442}+\frac{374}{442}+\frac{51}{442}=\frac{815}{442}\)

\(\frac{9}{12}\times\frac{4}{3}:\frac{8}{5}=1:\frac{8}{5}=\frac{5}{8}\)

\(\frac{4}{5}\times\frac{15}{8}:\frac{5}{7}=\frac{3}{2}:\frac{5}{7}=\frac{21}{10}\)

khó cậu ạ

a) = ( 9/10 - 4/5) + ( 3/4 + 1/2)

= ( 9/10 - 8/10) + ( 3/4 + 2/4)

= 1/10 + 5/4 

= 2/20 + 25/20 = 27/20

b) = (4/5 + 4/15) +  (5/6 - 1/2)

= (12/15 - 4/15) + (5/6 - 3/6)

= 8/15 + 2/6 

= 16/30 + 10/30 

= 26/30 = 13/15

c) = 55 - 39 - 1 + 60 /75 = 75/75 = 1

d) = 47 + 35 - 36 + 15/42 = 61/42

\(\dfrac{\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{5}}{\dfrac{3}{2}+1+\dfrac{3}{5}}=-\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{5}}{3\left(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{5}\right)}=-\dfrac{1}{3}\)

a, \(\frac{3}{5}+\frac{-4}{15}=\frac{9}{15}-\frac{4}{15}=\frac{5}{15}=\frac{1}{3}\)

b, \(\frac{-1}{3}+\frac{2}{5}+\frac{2}{15}=\frac{-5}{15}+\frac{6}{15}+\frac{2}{15}=\frac{3}{15}=\frac{1}{5}\)

c, \(\frac{-3}{5}+\frac{7}{21}+\frac{-4}{5}+\frac{7}{5}=\frac{-3}{5}+\frac{1}{3}+\frac{-4}{5}+\frac{7}{5}=\left(\frac{-3}{5}+\frac{-4}{5}+\frac{7}{5}\right)+\frac{1}{3}=\frac{1}{3}\)

d, \(\frac{2}{7}+\frac{1}{9}+\frac{3}{7}+\frac{5}{9}+\frac{-5}{6}=\left(\frac{2}{7}+\frac{3}{7}\right)+\left(\frac{1}{9}+\frac{5}{9}\right)+\frac{-5}{6}=\frac{5}{7}+\frac{6}{9}+\frac{-5}{6}=\frac{90}{126}+\frac{84}{126}+\frac{-105}{126}=\frac{69}{126}=\frac{23}{42}\)

e, \(\frac{-5}{7}+\frac{3}{4}+\frac{-1}{5}+\frac{-2}{7}+\frac{1}{4}=\left(\frac{-5}{7}+\frac{-2}{7}\right)+\left(\frac{3}{4}+\frac{1}{4}\right)+\frac{-1}{5}=\left(-1\right)+1+\frac{-1}{5}=\frac{-1}{5}\)

f, \(\frac{-3}{31}+\frac{-6}{17}+\frac{1}{25}+\frac{-28}{31}+\frac{-1}{17}+\frac{-1}{5}=\left(\frac{-3}{31}+\frac{-28}{31}\right)+\left(\frac{-6}{17}+\frac{-1}{17}\right)+\left(\frac{1}{25}+\frac{-1}{5}\right)=\left(-1\right)+\frac{-7}{17}+\frac{-4}{25}=\frac{-425}{425}+\frac{-175}{425}+\frac{-68}{425}=\frac{-668}{425}\)

Chúc bn học tốt

hi {\___/}

(^__^)

>like>

ngu thế

\(\frac{1}{5}\div\frac{1}{10}-\frac{1}{3}\cdot\left(\frac{6}{5}-\frac{9}{4}\right)^2=2-\frac{1}{3}\cdot-\frac{21}{20}^2\)

\(=2-\frac{1}{3}\cdot\frac{441}{400}\)

\(=2-\frac{147}{400}=\frac{800}{400}-\frac{147}{400}=\frac{653}{400}\)

Chúc chị/anh học tốt.

\(\frac{1}{5}:\frac{1}{10}-\frac{1}{3}\left(\frac{6}{5}-\frac{9}{4}\right)^2\)

\(=2-\frac{1}{3}\left[\frac{\left(-21\right)}{20}\right]^2\)

\(=2-\frac{1}{3}\cdot\frac{441}{400}\)( số âm. số âm = số dương )

\(=2-\frac{147}{400}\)

\(=\frac{800-147}{400}\)

\(=\frac{653}{400}=1\frac{253}{400}=1,6325\)

\(\frac{1}{5}:\frac{1}{10}-\frac{1}{3}\left(\frac{6}{5}-\frac{9}{4}\right)^2\)

\(=\frac{1}{5}.10-\frac{1}{3}\left(\frac{24}{20}-\frac{45}{20}\right)^2\)

\(=2-\frac{1}{3}\left(\frac{-21}{20}\right)^2\)

\(=2-\frac{1}{3}.\frac{441}{400}\)

\(=2-\frac{147}{400}\)

\(=\frac{800}{400}-\frac{147}{400}\)

\(=\frac{653}{400}\)

\(\dfrac{4}{5}+\dfrac{19}{18}-\dfrac{1}{2}+\dfrac{1}{5}-\dfrac{10}{8}\)

\(=\left(\dfrac{4}{5}+\dfrac{1}{5}\right)-\left(\dfrac{4}{8}+\dfrac{10}{8}\right)+\dfrac{19}{18}\)

\(=\dfrac{5}{5}-\dfrac{14}{8}+\dfrac{19}{18}\)

\(=1-\dfrac{7}{4}+\dfrac{19}{18}\)

\(=-\dfrac{3}{4}+\dfrac{19}{18}=\dfrac{11}{36}\)

\(\dfrac{4}{5}+\dfrac{19}{18}-\dfrac{1}{2}+\dfrac{1}{5}-\dfrac{10}{8}=\dfrac{4}{5}+\dfrac{19}{18}-\dfrac{1}{2}+\dfrac{1}{5}-\dfrac{5}{4}=\left(\dfrac{4}{5}+\dfrac{1}{5}\right)+\left(\dfrac{19}{18}-\dfrac{1}{2}\right)-\dfrac{5}{4}=1+\dfrac{5}{9}-\dfrac{5}{4}=\dfrac{36}{36}+\dfrac{20}{36}-\dfrac{45}{36}=\dfrac{11}{36}\)