a: =>4x-5=0 hoặc 5/4x-2=0

=>x=5/4 hoặc x=2:5/4=2*4/5=8/5

b: =>(1/12+19/6-30,75)*x-8=102

=>-55/2x=110

=>x=-4

\(\left(\dfrac{1}{2}+\dfrac{19}{6}-30,75\right).x-8=\left(\dfrac{3}{5}+0,415+\dfrac{1}{200}\right):0.01\)

\(\left(\dfrac{1}{2}+\dfrac{19}{6}-\dfrac{123}{4}\right).x-8=\left(\dfrac{3}{5}+\dfrac{83}{200}+\dfrac{1}{200}\right):\dfrac{1}{100}\)

\(\dfrac{-325}{12}.x-8=\dfrac{51}{50}:\dfrac{1}{100}\)

\(\dfrac{-325}{12}.x-8=102\)

\(\dfrac{-325}{12}.x=102+8\)

\(\dfrac{-325}{12}.x=110\)

\(x=110:\dfrac{-325}{12}\)

\(x=\dfrac{-264}{65}\)

\(\left(\dfrac{1}{12}+\dfrac{19}{6}-\dfrac{123}{4}\right).x-8=\left(\dfrac{3}{5}+\dfrac{83}{200}+\dfrac{1 }{200}\right)\): \(\dfrac{1}{100}\)

\(\dfrac{-53}{2}\) . x - 8 = \(\dfrac{51}{50}\): \(\dfrac{1}{100}\)

\(\dfrac{-53}{2}.x-8=\)102

\(\dfrac{-53}{2}\).x = 102 + 8

\(\dfrac{-53}{2}\).x = 110

x = 110 : \(\dfrac{-53}{2}\)

x = \(\dfrac{-204}{53}\)

\((\dfrac{1}{12}+3\dfrac{1}{6}-30,75)x-8=\left(\dfrac{3}{5}+0,415+\dfrac{1}{200}\right):0,01\)

\(\dfrac{-55}{2}.x-8=\dfrac{51}{50}:0,01\)

\(\dfrac{-55}{2}.x-8=102\)

\(\dfrac{-55}{2}.x=110\)

\(x=-4\)

co may tinh ma ban

Vậy hộ mink mink k cho tại ngại ấn mà

Nói nhầm

Tại mink ngại ấn nên hộ mink đi

\(M=\left(\frac{3}{5}+0,415\right)+\frac{1}{200}\div0,01\)

\(M=\left(\frac{3}{5}+\frac{83}{200}\right)+\frac{1}{200}\div\frac{1}{100}\)

\(M=\frac{203}{200}+\frac{1}{200}\div\frac{1}{100}\)

\(M=\frac{203}{200}+\frac{1}{2}\)

\(M=\frac{303}{200}\)

\(N=30,75+\frac{1}{12}+3\frac{1}{6}\)

\(N=\frac{123}{4}+\frac{1}{12}+\frac{19}{6}\)

\(N=\frac{185}{6}+\frac{19}{6}\)

\(N=34\)