24/55 nha

\(\frac{2^35^27^23^7}{49.5^3.3^6.11}\)

= \(\frac{2^31^21^21^7}{7.1^3.1^6.11}\)

= \(\frac{8}{77}\)

                         \(\frac{2^3.5^2.7^2.3^7}{49.5^3.3^6.11}\)\(=\frac{2^3.5^2.7^2.3^7}{7^2.5^3.3^6.11}=\frac{2^3.3}{5.11}=\frac{24}{55}\)

                            Ủng hộ mk nha!!!

                         Chúc các bn học tốt nha !!

\(\frac{2^3.5^2.7^2.3^7}{49.5^3.3^6.11}=\frac{2^3.5^2.7^2.3^7}{7^2.5^3.3^6.11}=\frac{2^3.1.1.3}{1.5.1.11}=\frac{24}{55}\)

a. \(\dfrac{2^3.5^2.7^2.3^7}{49.5^3.3^6.11}\)

= \(\dfrac{2^3.3}{5.11}=\dfrac{24}{55}\)

b. \(4.\left(\dfrac{-1}{2}\right)^3-2.\left(\dfrac{-1}{2}\right)^2+3\left(\dfrac{-1}{2}\right)+1\)

=\(-\dfrac{1}{2}-\dfrac{1}{2}-\dfrac{1}{2}\)

= 3\(\left(\dfrac{-1}{2}\right)\)

=\(\dfrac{-3}{2}\)

TA CÓ : \(\frac{2^3.3^4}{2^2.3^2.5}\)= \(\frac{2^3.3^4}{\left(2.3\right)^2.5}\)= \(\frac{2^3.3^4}{6^2.5}\)= \(\frac{2^3.3^4}{36.5}\)= \(\frac{8.81}{180}\)=  \(\frac{648}{180}\)= 648 : 180 = 3,6 HOẶC \(\frac{648}{180}\)= \(\frac{18}{5}\)

câu b) thì sao bạn

ngu..............................

tao lao

Ta có:

\(\frac{2^3.3^4}{2^2.3^2.5}=\frac{2.3^2}{5}=\frac{18}{5}\)

\(\frac{2^4.5^2.11^2.7}{2^3.5^3.7^2.11}=\frac{2.11}{5.7}=\frac{22}{35}\)

\(a.\frac{2\cdot\left(-13\right)\cdot9\cdot10}{\left(-3\right)\cdot4\cdot\left(-5\right)\cdot26}\)

\(=\frac{2\cdot\left(-13\right)\cdot3\cdot3\cdot2\cdot5}{\left(-3\right)\cdot2\cdot2\cdot\left(-5\right)\cdot13\cdot2}\)

\(=-\frac{3}{2}\)

b) \(\frac{2^3\cdot3^4}{2^2\cdot3^2\cdot5}=\frac{2\cdot3^2}{5}=\frac{2\cdot9}{5}=\frac{18}{5}\)

\(\frac{2^4\cdot5^2\cdot11^2\cdot7}{2^3\cdot5^3\cdot7^2\cdot11}=\frac{2\cdot1\cdot11\cdot1}{1\cdot5\cdot7\cdot1}=\frac{22}{35}\)

c) \(\frac{121\cdot75\cdot130\cdot169}{39\cdot60\cdot11\cdot198}=\frac{11\cdot11\cdot13\cdot10\cdot169}{13\cdot3\cdot6\cdot10\cdot11\cdot11\cdot6\cdot3}\)

\(=\frac{169}{3\cdot6\cdot6\cdot3}=\frac{169}{324}\)

d) \(\frac{1998\cdot1990+3978}{1992\cdot1991-3984}\)

\(\frac{1+2.3^6}{2^3.3^6-2^3.5^3}-\frac{1+3^6}{8\left(9^3-125\right)}-\frac{5^3}{18^3-10^3}\)

\(=\frac{1+2.3^6}{2^3\left(3^6-5^5\right)}-\frac{1+3^6}{2^3\left[\left(3^2\right)^3-5^3\right]}-\frac{5^3}{\left(2.3^2\right)^3-\left(2.5\right)^3}\)

\(=\frac{1+2.3^6}{2^3\left(3^6-5^3\right)}-\frac{1+3^6}{2^3\left(3^6-5^3\right)}-\frac{5^3}{2^3\left(3^6-5^3\right)}\)

\(=\frac{\left(1+2.3^6\right)-\left(1+3^6\right)-5^3}{2^3\left(3^6-5^2\right)}\)

\(=\frac{3^6-5^3}{2^3\left(3^6-5^3\right)}\)

\(=\frac{1}{8}\)