a. \(\dfrac{2^3.5^2.7^2.3^7}{49.5^3.3^6.11}\)
= \(\dfrac{2^3.3}{5.11}=\dfrac{24}{55}\)
b. \(4.\left(\dfrac{-1}{2}\right)^3-2.\left(\dfrac{-1}{2}\right)^2+3\left(\dfrac{-1}{2}\right)+1\)
=\(-\dfrac{1}{2}-\dfrac{1}{2}-\dfrac{1}{2}\)
= 3\(\left(\dfrac{-1}{2}\right)\)
=\(\dfrac{-3}{2}\)