1 responsible

2 colorful

3 pollution

4 disappointed

5 hopeless

VII

1 wear

2 to take

3 pick

4 didn't have

5 got

1. responsible
2. colourful
3. pollution
4. disappointed
5. wear
6. to take
7. pick
8. didn't have
9. got

26. responsible 

27.  colorful

28. pollution

29. disappointed

30. hoped

31. wear

32. to lake

33. pick

34. didn't have

35. got

36 I think I and my brother will be at school

37 Is the bakery on the corner of the street?

38 Why shouldn't we let our children play in the kitchen?

39 It is usually cool and foggy in autumn in my country

40 How many lessons do you have on Tuesday?

1 means

2 pictures

3 making

4 bring about

5 Through

6 In addition

7 designed 

8 entertaining

9 include

10 events

1 means

2 pictures

3 making

4 bring about

5 Through

6 In addition

7 designed 

8 entertaining

9 include

10 events

nha

1 means

2 pictures

3 making

4 bring about

5 Through

6 In addition

7 designed 

8 entertaining

9 include

10 events

1.

⇒ He doesn't work as hard as me

⇒ He is lazier than me.

2. 

⇒ Your bedroom is more uncomforable than my bedroom.

⇒ Your bedroom is not as comfortable as my bedroom.

3. 

⇒ Mary speaks English better than John.

⇒ Mary doesn't speak English as worse as John.

4. No boy in my class are as intelligent as Jack.

5. They suggest that he should play football.

1. -> He doesn't work as hard as me.

    -> He works lazier than me.

2. -> Your bedroom isn't as comfortable as mine.

    -> Your bedroom is uncomfortable than mine.

3. -> Mary speaks English better than John.

   -> Mary doesn't speak English as bad as John.

4. -> No boy is as intelligent as Jack in my class.

5. -> They suggest playing football. 

giúp với

CHữ xấu bỏ mẹ ai mà đọc đc

Em cần bài nào đăng lên 1 bài đó nha

\(A=\dfrac{x^2+2x-3-x^2+6x-9-4x+2}{\left(x-3\right)\left(x+3\right)}:\dfrac{x+3-x-1}{x+3}\\ A=\dfrac{2\left(2x-5\right)}{\left(x-3\right)\left(x+3\right)}\cdot\dfrac{x+3}{2}=\dfrac{2x-5}{x-3}\)

a: \(A=\dfrac{x^2+2x-3-x^2+6x-9-4x+2}{\left(x-3\right)\left(x+3\right)}:\dfrac{x+3-x-1}{x+3}\)

\(=\dfrac{4x-10}{\left(x-3\right)\left(x+3\right)}\cdot\dfrac{x+3}{2}=\dfrac{2x-5}{x-3}\)

e tách ra 10 câu 1 thôi nhé =)

tách ra nhé bn