Question

Các bn giúp mik câu a vs ạ

Answer 1

\(A=\dfrac{x^2+2x-3-x^2+6x-9-4x+2}{\left(x-3\right)\left(x+3\right)}:\dfrac{x+3-x-1}{x+3}\\ A=\dfrac{2\left(2x-5\right)}{\left(x-3\right)\left(x+3\right)}\cdot\dfrac{x+3}{2}=\dfrac{2x-5}{x-3}\)

Answer 2

a: \(A=\dfrac{x^2+2x-3-x^2+6x-9-4x+2}{\left(x-3\right)\left(x+3\right)}:\dfrac{x+3-x-1}{x+3}\)

\(=\dfrac{4x-10}{\left(x-3\right)\left(x+3\right)}\cdot\dfrac{x+3}{2}=\dfrac{2x-5}{x-3}\)