Bài 2: 

a: \(x^2\left(x^2-16\right)=0\)

\(\Leftrightarrow x\left(x-4\right)\left(x+4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=4\\x=-4\end{matrix}\right.\)

b: \(x^8+36x^4=0\)

\(\Leftrightarrow x^4=0\)

hay x=0

a(b+3)-b(3+b)

=(3+b)(a-b)

Thay số, có: (3+1997).(2003-1997)

= 2000.6 =12000

xy(x+y)-2x-2y

xy(x+y)- 2(x+y)

(x+y).(xy-2)

Thay số, co: 7. (8-2)

7.4=28

a) Với a = 3,05 thì ta có:

\(a\times2,46\) \(=3,05\times2,46=7,503\)

b) Với \(a=\dfrac{15}{8}\) thì ta có:

\(\left(\dfrac{5}{6}+\dfrac{7}{12}\right):a\) \(=\left(\dfrac{5}{6}+\dfrac{7}{12}\right):\dfrac{15}{8}\) \(=\left(\dfrac{10}{12}+\dfrac{7}{12}\right)\times\dfrac{8}{15}\) \(=\dfrac{17}{12}\times\dfrac{8}{15}\) \(=\dfrac{34}{45}\)

a) Thay a=3,05 vào 2,46a, ta được:

\(2.46\cdot3.05=7.503\)

b) Thay \(a=\dfrac{15}{8}\) vào biểu thức \(\left(\dfrac{5}{6}+\dfrac{7}{12}\right):a\), ta được:

\(\left(\dfrac{5}{6}+\dfrac{7}{12}\right):\dfrac{15}{8}\)

\(=\dfrac{17}{12}\cdot\dfrac{8}{15}=\dfrac{34}{45}\)

a) (-12). (7 - 72) - 25. (55 - 43) 

= (-12). (- 65) - 25. 12 

= 12. 65 – 12. 25

= 12. (65 - 25) 

= 12. 40 

= 480

b) (39 - 19) : (- 2) + (34 - 22). 5 

= 20 : (- 2) + 12. 5 

= - 10 + 60

= 60 - 10 

= 50.

Sửa đề: A=7/12-9/20+11/30-13/42+15/56

A=1/3+1/4-1/4-1/5+1/5+1/6-1/6-1/7+1/7+1/8

=1/3+1/8=11/24

\(\frac{29}{9}.\frac{109}{7}-\frac{29}{9}.\frac{57}{7}+\frac{29}{9}.\frac{12}{7}-\frac{29}{9}.\frac{1}{7}\)

= \(\frac{29}{9}.\left(\frac{109}{7}-\frac{57}{7}+\frac{12}{7}-\frac{1}{7}\right)\)

= \(\frac{29}{9}.\frac{63}{7}\)

=\(\frac{29}{9}.9\)

=\(\frac{29.9}{9}\)

=\(\frac{261}{9}\)

= \(29\)

hứ 7 nộp rùi giải giúp mình à

Được cập nhật 10 giờ trước (09:01)

Toán lớp 6

Chau Nguyen Van 9 giờ trước (09:40)
 Báo cáo sai phạm

299 .1097 −299 .577 +299 .127 −299 .17 

= 299 .(1097 −577 +127 −17 )

= 299 .637 

=299 .9

=29.99 

=2619 

= 

\(A=\dfrac{7}{3}+\dfrac{5}{7}+\dfrac{2}{3}-\dfrac{7}{12}+\dfrac{5}{2}=3+\dfrac{221}{84}=\dfrac{473}{84}\)

a) (2/5 x 25/29) + (3/5 x 25/29)
= (50/145) + (75/145)
= 125/145

b) (5/2 x 3/7) - (3/14 : 6/7)
= 15/14 - (3/14 x 7/6)
= 15/14 - 1/2
= (30/28) - (14/28)
= 16/28
= 4/7

c) (15/4 : 5/12) - (6/5 : 11/15)
= (15/4 x 12/5) - (6/5 x 15/11)
= 180/20 - 90/55
= 9 - 18/11
= (99/11) - (18/11)
= 81/11
= 7 4/11

a) (2/3) + (20/21 x 3/2 x 7/5)
= 2/3 + (60/210)
= 2/3 + 2/7
= (14/21) + (6/21)
= 20/21

b) (5/17 x 21/32 x 47/24 x 0)
= 0

c) (11/3 x 26/7) - (26/7 x 8/3)
= (286/21) - (208/21)
= 78/21
= 3 9/21
= 3 3/7

a) (25/8) : x = 5/16
=> (25/8) x (16/5) = x
=> 4 = x

b) x + (7/15) = 6/15
=> x = (6/15) - (7/15)
=> x = -1/15

c) x : (28/49) = 7/12
=> x x (49/28) = 7/12
=> x = (7/12) x (28/49)
=> x = 1/2

a) 6 x x = (5/8) : (3/4)
=> 6x = (5/8) x (4/3)
=> 6x = 20/24
=> 6x = 5/6
=> x = (5/6) / 6
=> x = 5/36

câu,b,không,đủ,thông,tin,nhan,bạn.

a) \(\dfrac{9}{5}+\dfrac{9}{5}:\dfrac{9}{5}\)

\(=\dfrac{9}{5}+\dfrac{9}{5}\times\dfrac{5}{9}\)

\(=\dfrac{9}{5}+1\)

\(=\dfrac{14}{5}\)

b) \(\dfrac{7}{5}-\dfrac{1}{2}\times\dfrac{1}{3}\)

\(=\dfrac{7}{5}-\dfrac{1}{6}\)

\(=\dfrac{42}{30}-\dfrac{5}{30}\)

\(=\dfrac{37}{30}\)

\(a,\dfrac{9}{5}+\dfrac{9}{5}:\dfrac{9}{5}\)

\(=\dfrac{9}{5}+\dfrac{9}{5}\times\dfrac{5}{9}\)

\(=\dfrac{9}{5}+1\)

\(=\dfrac{9}{5}+\dfrac{5}{5}\)

\(=\dfrac{14}{5}\)

\(b,\dfrac{7}{5}-\dfrac{1}{2}\times\dfrac{1}{3}\)

\(=\dfrac{7}{5}-\dfrac{1}{6}\)

\(=\dfrac{42}{30}-\dfrac{5}{30}\)

\(=\dfrac{37}{30}\)