1) 2,75 - 5/6 × 2/5 = 2,75 - (5/6) × (2/5) = 2,75 - 1/3 = 2,75 - 0,33 = 2,42

2) 1,25 - (5/6 - 0,75) - 3/5 = 1,25 - (5/6 - 0,75) - 3/5 = 1,25 - (5/6 - 3/4) - 3/5 = 1,25 - (5/6 - 9/12) - 3/5 = 1,25 - (10/12 - 9/12) - 3/5 = 1,25 - 1/12 - 3/5 = 1,25 - 0,08 - 0,6 = 1,25 - 0,68 = 0,57

3) 4/9 × 0,75 + 8/5 + 3,125 = (4/9) × 0,75 + 8/5 + 3,125 = 0,44 + 8/5 + 3,125 = 0,44 + 1,6 + 3,125 = 0,44 + 4,725 = 5,165

4) 1,125 - 4/7 - 0,12 = 1,125 - (4/7) - 0,12 = 1,125 - 0,57 - 0,12 = 0,435 - 0,12 = 0,315

5) (1/3 + 0,4) × 3,5 + (1/6 + 0,75) × 6/5

\(\left(1+2+3+4+5+6+...+999+1000\right)\times\left(0.75\times0.4-\dfrac{3}{4}\times0.3\right)\)

\(=\dfrac{\left(1000+1\right)\times1000}{2}\times\left[0.75\times\left(0.4-0.3\right)\right]\)

\(=500500\times0.75\times0.1=375375\)

Giải:

\(\left(1+2+3+4+5+6+...+999+1000\right).\left(0,75.0,4-\dfrac{3}{4}.0,3\right)\) 

Số số hạng \(\left(1+2+3+4+5+6+...+999+1000\right)\) là:

              \(\left(1000-1\right):1+1=1000\) 

Tổng dãy \(\left(1+2+3+4+5+6+...+999+1000\right)\) là:

              \(\left(1+1000\right).1000:2=500500\) 

\(\Rightarrow\left(1+2+3+4+5+6+...+999+1000\right).\left(0,75.0,4-\dfrac{3}{4}.0,3\right)\) 

\(=500500.\left[0,75.\left(0,4-0,3\right)\right]\) 

\(=500500.\left[0,75.0,1\right]\) 

\(=500500.0,075\) 

\(=37537,5\)

=(1000+1)×10002×[0.75×(0.4−0.3)]=(1000+1)×10002×[0.75×(0.4−0.3)]

 6 x 1/3 + 0,75 + 3/4 : 0,25

=2+0,75+3

=5+0,75

=5,75

\(6.\frac{1}{3}+0,75+\frac{3}{4}:0,25=2+\frac{3}{4}+3=\frac{23}{4}\)

\(6.\frac{1}{3}+0,75+\frac{3}{4}:0,25=\left(6.\frac{1}{3}\right)+0,75+\left(\frac{3}{4}:0,25\right)=2+0,75+3=2,75+3=\frac{23}{4}=5,75\)

* \(\dfrac{15}{12}:x=\left(\dfrac{5}{6}-\dfrac{1}{2}\right).\dfrac{5}{4}\)

\(\dfrac{15}{12}:x=\dfrac{1}{3}.\dfrac{5}{4}\)

\(\dfrac{15}{12}:x=\dfrac{5}{12}\)

\(x=\dfrac{15}{12}:\dfrac{5}{12}\)

\(x=3\)

* \(y:0,15=\left(2,8+0,38\right):0,75\)

\(y:0,15=3,18:0,75\)

\(y:15=4,24\)

\(y=4,24.15\)

\(y=63,6\)

ko biết đau kho quá

15/12 : y = ( 5/6 - 1/2 ) . 5/4 y : 0,15 = (2,8 + 0,38) : 0,75

15/12 : y = 1/3 . 5/4 y : 0,15 = 3,18 : 0,75

15/12 : y = 5/12 y : 0,15 = 4,24

y = 15/12 : 5/12 y = 4,24 . 0,15

y = 3 y = 0,636

b,

y/0,15=3,16/0,75=6,32/0,15

=>y=6,32

a)  \(0,75\times26+49\times\frac{3}{4}+\frac{3}{4}\times24+\) \(0,75\)

    \(=\) \(0,75\times\left(26+1\right)+\frac{3}{4}\times\left(49+24\right)\)

     \(=\)  \(\frac{3}{4}\times27+\frac{3}{4}\times73\)

      \(=\) \(\frac{3}{4}\times\left(27+73\right)\)

        \(=\)\(\frac{3}{4}\times100=75\)

b) câu b,c làm tương tự

= 2028,2018

a, \(\Leftrightarrow2x^2=72\)

\(\Leftrightarrow x^2=36\)

\(\Leftrightarrow x=\pm6\)

Vậy ...

\(b,\Leftrightarrow\dfrac{3}{5}x-0,75=2\dfrac{4}{5}.\dfrac{3}{7}=\dfrac{6}{5}\)

\(\Leftrightarrow\dfrac{3}{5}x=\dfrac{6}{5}+0,75=\dfrac{39}{20}\)

\(\Leftrightarrow x=\dfrac{39}{20}:\dfrac{3}{5}=\dfrac{13}{4}\)

Vậy ...

\(c,\Leftrightarrow2x=1\dfrac{5}{6}.\dfrac{6}{11}-\dfrac{3}{10}=\dfrac{7}{10}\)

\(\Leftrightarrow x=\dfrac{7}{10}:2=\dfrac{7}{20}\)

Vậy ...

\(d,\Leftrightarrow\dfrac{1}{x-7\dfrac{1}{3}}=1.5:2\dfrac{1}{4}=\dfrac{2}{3}\)

\(\Leftrightarrow x-7\dfrac{1}{3}=\dfrac{3}{2}\)

\(\Leftrightarrow x=\dfrac{3}{2}+7\dfrac{1}{3}=\dfrac{53}{6}\)

Vậy ...

a) 2x² - 72 = 0

\(\Rightarrow\) 2x² = 72

\(\Rightarrow\) x² = 36 = 6² = (- 6)²

\(\Rightarrow\) x = 6 hoặc x = - 6

Vậy x = 6 hoặc x = - 6

b) (\(\dfrac{3}{5}\)x - 0,75) : \(\dfrac{3}{7}\) = \(2\dfrac{4}{5}\)

\(\Rightarrow\)  (\(\dfrac{3}{5}\)x - 0,75) : \(\dfrac{3}{7}\) = \(\dfrac{14}{5}\)

\(\Rightarrow\)  \(\dfrac{3}{5}\)x - \(\dfrac{3}{4}\) = \(\dfrac{6}{5}\)

\(\Rightarrow\) \(\dfrac{3}{5}\)x = \(\dfrac{39}{20}\)

\(\Rightarrow\) x = \(\dfrac{13}{4}\)

Vậy x = \(\dfrac{13}{4}\)

c) \(2x+\dfrac{3}{10}=1\dfrac{5}{6}.\dfrac{6}{11}\)

\(\Rightarrow\) \(2x+\dfrac{3}{10}=\dfrac{11}{6}.\dfrac{6}{11}=1\)

\(\Rightarrow\) \(2x=\dfrac{7}{10}\)

\(\Rightarrow\) \(x=\dfrac{7}{20}\)

Vậy \(x=\dfrac{7}{20}\)

d) \(2\dfrac{1}{4}:\left(x-7\dfrac{1}{3}\right)=1,5\)

\(\Rightarrow\) \(\dfrac{9}{4}:\left(x-\dfrac{22}{3}\right)=\dfrac{3}{2}\)

\(\Rightarrow\) \(x-\dfrac{22}{3}=\dfrac{3}{2}\)

\(\Rightarrow\) \(x=\dfrac{53}{6}\)

Vậy \(x=\dfrac{53}{6}\)