\(2006.\left(43.10-2.43.5\right)+10\\ =2006\left(43.10-43.10\right)+10\\ =2006\left(430-430\right)+10\\ =2006.0+10\\ =10\)

\(2006\times\left(43\times10-2\times43\times5\right)+10\) 

\(=2006\times\left(43\times10-43\times10\right)+10\) 

\(=2006\times0+10\) 

\(=0+10\) 

\(=10\)

bằng 10 nha

giải ra chi tiết giúp mink với ạ

\(4\times126\times25\\ =\left(4\times25\right)\times126\\ =100\times126\\ =12600\)

\(\left(9\times8-12-5\times12\right)\times\left(1+2+3+4+5\right)\\ =\left(72-12-60\right)\times15\\ =\left(60-60\right)\times15\\ =0\times15\\ =0\)

\(4\times126\times25=\left(4\times25\right)\times126=100\times126=12600\\ \left(9\times8-12-5\times12\right)\times\left(1+2+3+4+5\right)\\ =\left(3\times3\times2\times4-12-5\times12\right)\times\left(1+2+3+4+5\right)\\ =\left(12\times6-12-5\times12\right)\times\left(1+2+3+4+5\right)\\ =\left[12\times\left(6-1-5\right)\right]\times\left(1+2+3+4+5\right)\\ =\left(12\times0\right)\times\left(1+2+3+4+5\right)\\ =0\times\left(1+2+3+4+5\right)=0\)

(9x8-12-12x5)x(1+2+3+4+5)

= (72-12-60)x(1+2+3+4+5)

= 0x(1+2+3+4+5)

=0

 ( 9 x 8 - 12 - 5 x 12 ) x ( 1 + 2 + 3 + 4 + 5 )

= ( 3 x 3 x 4 x 2 - 12 - 5 x 12 ) x ( 1 + 2 + 3 + 4 + 5 )

= ( 6 x 12 - 12 - 5 x 12 ) x ( 1 + 2 + 3 + 4 + 5 )

= { 12 x ( 6 - 5 - 1 ) } x ( 1 + 2 + 3 + 4 + 5 )

= 12 x 0 x ( 1 + 2 + 3 + 4 + 5 )

= 0

k cho mình nha chúc bạn học tốt

Trả lời :.............................................

( 9 x 8 - 12 - 5 x 12 ) x ( 1 + 2 + 3 + 4 + 5 )

= 72    -  12 - 60        x    15

=                0 -                    900

= 900

Hk tốt..........................................

k nhé Ter Stegen

= 

Ta có: ( 9x8-12-5x12) x (1+2+3+4+5)

=( 72-12-60) x ( 1+2+3+4+5)

=(60-60) x (1+2+3+4+5)

=0 x (1+2+3+4+5)

=0

Mọi người tk cho mình nha. Mình cảm ơn trước vậy ^.<

(9 x 8 - 12 - 5 x 12) x (1 + 2 + 3 + 4 + 5)

= (72 - 12 - 60) x (1 + 2 + 3 + 4 + 5)

= ( 60 - 60) x (1 + 2 + 3 + 4 + 5)

=      0        x (1 + 2 + 3 + 4 + 5)

=                    0

(9x8-12-5x12)x(1+2+3+4+5)

=(72-12-60)x(15)

=0x15

=0

A = 5x( x - 1 )( 2x + 3 ) - 10x( x - 4 )

= 5x( 2x² + x - 3 ) - 10x² + 40x

= 10x³ + 5x² - 15x - 10x² + 40x

= 10x³ - 5x² + 25x

Thế x = -1/3 ta được

A = \(10\times\left(-\frac{1}{3}\right)^3-5\times\left(-\frac{1}{3}\right)^2+25\times\left(-\frac{1}{3}\right)\)

= \(10\times\left(-\frac{1}{27}\right)-5\times\frac{1}{9}-\frac{25}{3}\)

= \(-\frac{10}{27}-\frac{5}{9}-\frac{25}{3}\)

= \(-\frac{250}{27}\)

b) Đề sai . Tính khó

c) x = 14

=> 13 = x - 1

15 = x + 1

16 = x + 2

29 = 2x + 1 

Thế vào C ta được :

C = x⁵ - ( x + 1 )x⁴ + ( x + 2 )x³ - ( 2x + 1 )x² + ( x - 1 )x

= x⁵ - x⁵ - x⁴ + x⁴ + 2x³ - 2x³ - x² + x² - x

= -x = -14

a) \(\frac{6^7}{4^3\cdot9^2}=\frac{2^7\cdot3^7}{2^6\cdot3^4}=2\cdot3^3=2\cdot27=54\)

b) \(\frac{12^3\cdot15^3}{4^3\cdot25^2\cdot9^2}=\frac{2^6\cdot3^3\cdot3^3\cdot5^3}{2^6\cdot5^4\cdot3^4}=\frac{3^2}{5}=1,8\)

c) \(\frac{2^{11}+3\cdot2^{10}}{10\cdot4^5}=\frac{2^{10}\left(2+3\right)}{2\cdot5\cdot2^{10}}=\frac{1}{2}=0,5\)

d) \(\frac{3^8\cdot2-3^6}{2\cdot17\cdot3^7}=\frac{3^6\left(3^2\cdot2-1\right)}{2\cdot17\cdot3^7}=\frac{1}{2\cdot3}=\frac{1}{6}\)

a)\(=\dfrac{16}{13}-\dfrac{3}{15}+\dfrac{6}{13}=\dfrac{22}{13}-\dfrac{3}{15}=\dfrac{96}{65}\)

b)\(=\dfrac{21}{8}-\left(\dfrac{5}{10}+\dfrac{6}{10}\right)=\dfrac{21}{8}-\dfrac{11}{10}=\dfrac{61}{40}\)

c)\(=\dfrac{27}{10}-3-\dfrac{4}{7}--\dfrac{61}{70}\)

d)\(=\dfrac{576}{702}=\dfrac{4}{5}\)

e)\(=\left(\dfrac{20}{15}-\dfrac{12}{15}\right)\times\dfrac{25}{2}=\dfrac{8}{15}\times\dfrac{25}{2}=\dfrac{20}{3}\)

f)\(=\dfrac{24}{12}-\dfrac{4}{12}-\dfrac{6}{12}-\dfrac{2}{12}-\dfrac{3}{12}=\dfrac{9}{12}=\dfrac{3}{4}\)

d) \(=\dfrac{32}{45}x\dfrac{18}{16}=\dfrac{576}{720}=\dfrac{115}{114}\)

e) \(=\left(\dfrac{4}{3}-\dfrac{4}{5}\right)x\dfrac{25}{12}=\dfrac{8}{15}x\dfrac{25}{12}=\dfrac{200}{180}=\dfrac{10}{9}\)

f) \(=\dfrac{2}{1}-\dfrac{1}{3}-\dfrac{1}{2}-\dfrac{1}{6}-\dfrac{3}{12}=\dfrac{24}{12}-\dfrac{4}{12}-\dfrac{6}{12}-\dfrac{2}{12}-\dfrac{3}{12}\)

\(=\dfrac{20}{12}-\dfrac{4}{12}-\dfrac{3}{12}=\dfrac{16}{12}-\dfrac{3}{12}=\dfrac{13}{12}\)