\(Bài2\)

\(a,\left(3x-1\right)\left(x+3\right)=\left(2-x\right)\left(5-3x\right)\\ =>3x^2-x+9x-3=10-5x-6x+3x^2\\ =>3x^2+8x-3-10+11x-3x^2=0\\ =>19x-13=0\\ =>x=\dfrac{13}{19}\\ b,\left(x+5\right)\left(2x-1\right)=\left(2x-3\right)\left(x+1\right)\\ =>2x^2+10x-x-5=2x^2-3x+2x-3\\ =>9x-5+x+3=0\\ =>10x=2\\ =>x=\dfrac{1}{5}\)

\(c,\left(x+1\right)\left(x+9\right)=\left(x+3\right)\left(x+5\right)\\ =>x^2+x+9x+9=x^2+3x+5x+15\\ =>10x+9=8x+15=>10x-8x=15-9\\ =>2x=6\\ =>x=3\\ d,\left(3x+5\right)\left(2x+1\right)=\left(6x-2\right)\left(x-3\right)\\ =>6x^2+10x+3x+5=6x^2-2x-18x+6\\ =>13x+5=-20x+6\\ =>13x+20x=6-5\\ =>33x=1\\ =>x=\dfrac{1}{33}\)

\(e,\left(x+2\right)^2+2\left(x-4\right)=\left(x-4\right)\left(x-2\right)\\ =>x^2+4x+4+2x-8=x^2-4x-2x+8\\ =>6x-4=-6x+8\\ =>12x=12\\ =>x=1\\ f,\left(x+1\right)\left(2x-3\right)-3\left(x-2\right)=2\left(x-1\right)^2\\ =>2x^2+2x-3x-3-3x+6=2\left(x^2-2x+1\right)\\ =>2x^2-4x+3=2x^2-4x+2\\ =>-4x+3=-4x+2\\ =>3=2\left(voli\right)\)

=> pt vô nghiệm 

\(2x^2=50\\ =>x^2=25\\ =>\left[{}\begin{matrix}x^2=5^2\\x^2=\left(-5\right)^2\end{matrix}\right.\\ =>\left[{}\begin{matrix}x=5\\x=-5\end{matrix}\right.\)

\(1-B.\dfrac{x-1}{x}\)

\(2-D\)

\(3,đk:x^2-4\ne0\\ \Leftrightarrow\left\{{}\begin{matrix}x\ne2\\x\ne-2\end{matrix}\right.\Rightarrow B\)

\(4,\) Cạnh của hình vuông là : \(=sin45^o.3\sqrt{2}=3cm\)

Diện tích hình vuông là : \(S=3\times3=9\left(cm^2\right)\Rightarrow D\)

Đáy lớn là : \(96+36=132\left(m\right)\)

Độ dài chiều cao là : \(132+36=168\left(m\right)\)

Diện tích hình thang là : \(S=\dfrac{\left(36+132\right)\times168}{2}=14112\left(m^2\right)\)

Diện tích làm vườn là : \(14112\times65\%=9172,8\left(m^2\right)\)

Diện tích làm ao là : \(14112-9172,8=4939,2\left(m^2\right)\)

\(4NH_3+7O_2--->4NO_2+6H_2O\)

\(18-\left(-32\right)=18+32=50\)

\(\left(-2\right)^5+\left[\left(-69\right):3+3+53\right].\left(-2\right)-8\\ =\left(-32\right)+\left[\left(-23\right)+3+53\right].\left(-2\right)-8\\ =\left(-32\right)+\left(-20+53\right).\left(-2\right)-8\\ =\left(-32\right)+33.\left(-2\right)-8\\ =-32-66-8\\ =-98-8\\ =-106\)

Thay hai điểm vào hàm số

\(\Rightarrow\left\{{}\begin{matrix}\sqrt{2}=m^2\\-\sqrt{3}=n^2\end{matrix}\right.\)

\(m^2-n^2=\sqrt{2}-\left(-\sqrt{3}\right)=\sqrt{2}+\sqrt{3}\)

\(\left\{{}\begin{matrix}2018-12=2006⋮̸3\left(kot/m\right)\\2020-12=2008⋮̸3\left(kot/m\right)\\2021-12=2009⋮̸3\left(kot/m\right)\\2022-12=2010⋮3\left(t/m\right)\end{matrix}\right.\) 

=> D