330 nha

=330

ủng hộ mk nhé

330 là kết quả đúng đó bạn!

\(330\)nha bạn

\(\frac{2021}{1\cdot2}+\frac{2021}{2\cdot3}+...+\frac{2021}{9\cdot10}=2021\cdot\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+...+\frac{1}{9\cdot10}\right)\)

\(=2021\cdot\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right)=2021\cdot\left(1-\frac{1}{10}\right)\)

\(=2021\cdot\frac{9}{10}=\frac{18189}{10}\)

Ta có : \(\frac{2021}{1.2}+\frac{2021}{2.3}+\frac{2021}{3.4}+...+\frac{2021}{9.10}=2021\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}\right)\)

\(=2021\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\right)\)

\(=2021\left(1-\frac{1}{10}\right)=2021.\frac{9}{10}=1818,9\)

A  = 1 x 2 + 2 x 3 + ....... + 10 x 11

3A = 1 x 2 x 3 + 2 x 3 x 3 + ..........+ 10 x 11 x 3

3A = 1 x 2 x (3-0) + 2 x 3 x (4-1) + .......... + 10 x 11 x (12 -9)

3A = 1 x 2 x 3 + 2 x 3 x 4 - 1 x 2 x 3 + ........... + 10 x 11 x 12 - 9 x 10 x 11

3A = (1 x 2 x 3 - 1 x 2 x 3) + ( 2 x 3 x 4 - 2 x 3 x 4) +............ + 10 x 11 x 12

3A = 10 x 11 x 12 = 1320

A = 1320 : 3 = 440

Gọi biểu thức trên là A, ta có :

A= 1x2 + 2x3 + 3x4 + 4x5 + ...+ 99x100

A x 3 = 1x2x3 + 2x3x3 + 3x4x3 + 4x5x3 + ... + 99x100x3

A x 3 = 1x2x3 + 2x3x(4-1) + 3x4x(5-2) + 4x5x(6-3) + ... + 99x100x(101-98)

A x 3 = 1x2x3 + 2x3x4 - 1x2x3 + 3x4x5 - 2x3x4 + 4x5x6 - 3x4x5 + ... + 99x100x101 - 98x99x100.

A x 3 = 99x100x101 A = 99x100x101 : 3 A = 333300

 

\(1.2+2.3+3.4+4.5+...+9.10\)

Đặt A = \(1.2+2.3+3.4+4.5+...+9.10\)

\(3.A\) = \(1.2.3+2.3.3+3.4.3+4.5.3+...+9.10.3\)

=> \(3.A\) = \(1.2.3+2.3.4+3.4.5+4.5.6+...+9.10.11\)

Ta có: \(3.A=9.10.11\)

=>: \(A=\frac{9.10.11}{3}=330\)

=> A = 330 

2+6+12+20+30+42+56+72+90=330

\(1.2+2.3+4.5+...+9.10\)

Dat A=1.2+2.3+3.4+4.5+...+9.10

3.A=1.2.3+2.3.3+3.4.3+4.5.3+...+9.10.3

3A=1.2.3+2.3.4+3.4.5+4.5.6+...+9.10.11

Ta co:3A=9.10.11

A=9.10.11:3

A=330

Vay A=330

=1/1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+............+1/9+1/10

=1-1/10

=10/10-1/10

=9/10

Bài làm:

  \(\frac{1}{1\times2}+\frac{1}{2\times3}\)\(+\frac{1}{3\times4}+\frac{1}{4\times5}\)\(+...\frac{1}{9\times10}\)

\(=\frac{1}{1}-\frac{1}{2}\)\(+\frac{1}{2}-\frac{1}{3}\)\(+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}\)\(-\frac{1}{5}\)\(+...\frac{1}{9}-\frac{1}{10}\)

\(=\)\(\frac{1}{1}-\frac{1}{10}\)

\(=\frac{9}{10}\)

=1- 1/2 +1/2- 1/3+....+1/9- 1/10

=1- 1/10

=9/10

1/1x2 + 1/2x3 + 1/3x4 +...+1/9x10 = 1/1 - 1/2 + 1/2 -1/3 + 1/3 -1/4 +...+1/9-1/10

=1+( 1/2 -1/2)+(1/3-1/3)+...+(1/9-1/9)-1/10

=1 + 0 + 0 +...-1/10 = 9/10

\(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+....+\frac{1}{9x10}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}=\)\(1-\frac{1}{10}=\frac{9}{10}\) chúc bạn học tốt tk mk nha

Gọi phép tính là: \(A\)

Ta có:

\(A=\dfrac{2}{1\times2}+\dfrac{2}{2\times3}+\dfrac{2}{3\times4}+...+\dfrac{2}{9\times10}\\ A\div2=\dfrac{1}{1\times2}+\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+...+\dfrac{1}{9\times10}\\ A\div2=\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{9}-\dfrac{1}{10}\\ A\div2=\dfrac{9}{10}\\ A=\dfrac{18}{10}=\dfrac{9}{5}\)

\(=2\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{9\cdot10}\right)\)

\(=2\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{9}-\dfrac{1}{10}\right)=2\cdot\dfrac{9}{10}=\dfrac{9}{5}\)

Đặt phép tính  là A

\(A=\dfrac{2}{1.2}+\dfrac{2}{2.3}+\dfrac{2}{3.4}+\dfrac{2}{4.5}+\dfrac{2}{5.6}+\dfrac{2}{6.7}+\dfrac{2}{7.8}+\dfrac{2}{8.9}+\dfrac{2}{9.10}\)

\(2A=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+.....+\dfrac{1}{9}-\dfrac{1}{10}\)

\(2A=1-\dfrac{1}{10}\)

\(2A=\dfrac{9}{10}\)

\(A=\dfrac{9}{5}\)

=3.(1/1.2+1/2.3+....+1/9.10)+11.(1/2.9+1/9.16+...+1/93.100)

=3.(1-1/2+1/2-1/3+1/3 - ... - 1/10)+11.(1/2-1/9+1/9-...-1/100)

= 3.(1-1/10) + 11.( 1/2-1/100)

= 3. 9/10+11.49/100

chỗ này bạn tự tính máy tính nha

bn ơi cho mình hỏi dấu chấm là chia à

=3

=3